142232
The electric field of certain radiation is given by the equation
$E=200\left\{\sin \left(4 \pi \times 10^{10}\right) t+\sin \left(4 \pi \times 10^{15}\right) t\right\}$ falls in a metal surface having work function $2.0 \mathrm{eV}$. The maximum kinetic energy (in $\mathrm{eV}$ ) of the photoelectrons is [use Planck's constant $(h)=6.63 \times 10^{-34} \mathrm{~J}-\mathrm{s}$ and electron charge $(E)=$ $\left.1.6 \times 10^{-19} \mathrm{C}\right]$
142233 Photons of wavelength $\lambda$ emitted by a source of power $P$ incident on a photo cell. If the current produced in the cell, is $I$, then the percentage of incident photons which produce current in the photo cell is. (Where, $h$ is Planck's constant and $\mathrm{c}$ is the speed of light in vacuum)
142234 For sodium light, the two yellow lines occur at $\lambda_{1}$ and $\lambda_{2}$ wavelengths. If the mean of these two is $6000 \AA$ and $\left|\lambda_{2}-\lambda_{1}\right|=6 \AA$, then the approximate energy difference between the two levels corresponding to $\lambda_{1}$ and $\lambda_{2}$ is
142232
The electric field of certain radiation is given by the equation
$E=200\left\{\sin \left(4 \pi \times 10^{10}\right) t+\sin \left(4 \pi \times 10^{15}\right) t\right\}$ falls in a metal surface having work function $2.0 \mathrm{eV}$. The maximum kinetic energy (in $\mathrm{eV}$ ) of the photoelectrons is [use Planck's constant $(h)=6.63 \times 10^{-34} \mathrm{~J}-\mathrm{s}$ and electron charge $(E)=$ $\left.1.6 \times 10^{-19} \mathrm{C}\right]$
142233 Photons of wavelength $\lambda$ emitted by a source of power $P$ incident on a photo cell. If the current produced in the cell, is $I$, then the percentage of incident photons which produce current in the photo cell is. (Where, $h$ is Planck's constant and $\mathrm{c}$ is the speed of light in vacuum)
142234 For sodium light, the two yellow lines occur at $\lambda_{1}$ and $\lambda_{2}$ wavelengths. If the mean of these two is $6000 \AA$ and $\left|\lambda_{2}-\lambda_{1}\right|=6 \AA$, then the approximate energy difference between the two levels corresponding to $\lambda_{1}$ and $\lambda_{2}$ is
142232
The electric field of certain radiation is given by the equation
$E=200\left\{\sin \left(4 \pi \times 10^{10}\right) t+\sin \left(4 \pi \times 10^{15}\right) t\right\}$ falls in a metal surface having work function $2.0 \mathrm{eV}$. The maximum kinetic energy (in $\mathrm{eV}$ ) of the photoelectrons is [use Planck's constant $(h)=6.63 \times 10^{-34} \mathrm{~J}-\mathrm{s}$ and electron charge $(E)=$ $\left.1.6 \times 10^{-19} \mathrm{C}\right]$
142233 Photons of wavelength $\lambda$ emitted by a source of power $P$ incident on a photo cell. If the current produced in the cell, is $I$, then the percentage of incident photons which produce current in the photo cell is. (Where, $h$ is Planck's constant and $\mathrm{c}$ is the speed of light in vacuum)
142234 For sodium light, the two yellow lines occur at $\lambda_{1}$ and $\lambda_{2}$ wavelengths. If the mean of these two is $6000 \AA$ and $\left|\lambda_{2}-\lambda_{1}\right|=6 \AA$, then the approximate energy difference between the two levels corresponding to $\lambda_{1}$ and $\lambda_{2}$ is
142232
The electric field of certain radiation is given by the equation
$E=200\left\{\sin \left(4 \pi \times 10^{10}\right) t+\sin \left(4 \pi \times 10^{15}\right) t\right\}$ falls in a metal surface having work function $2.0 \mathrm{eV}$. The maximum kinetic energy (in $\mathrm{eV}$ ) of the photoelectrons is [use Planck's constant $(h)=6.63 \times 10^{-34} \mathrm{~J}-\mathrm{s}$ and electron charge $(E)=$ $\left.1.6 \times 10^{-19} \mathrm{C}\right]$
142233 Photons of wavelength $\lambda$ emitted by a source of power $P$ incident on a photo cell. If the current produced in the cell, is $I$, then the percentage of incident photons which produce current in the photo cell is. (Where, $h$ is Planck's constant and $\mathrm{c}$ is the speed of light in vacuum)
142234 For sodium light, the two yellow lines occur at $\lambda_{1}$ and $\lambda_{2}$ wavelengths. If the mean of these two is $6000 \AA$ and $\left|\lambda_{2}-\lambda_{1}\right|=6 \AA$, then the approximate energy difference between the two levels corresponding to $\lambda_{1}$ and $\lambda_{2}$ is