QBManager

Dual nature of radiation and Matter

142133 $6.4 \times 10^{- 9}$ joule is approximately

1 4 electron volt

2 6 electron volt

3 8 electron volt

4 1 electron volt

Explanation:

A We know that,
$1 eV = 1.6 \times 10^{- 19} J$
$J = \frac{1}{1.6 \times 10^{- 19}} eV$
$6.4 \times 10^{- 9} J = \frac{1}{1.6 \times 10^{- 19}} \times 6.4 \times 10^{- 19}$
$= 4 eV$

SRMJEEE - 2015

Dual nature of radiation and Matter

142001 Threshold frequency for photoelectric effect on sodium corresponds to a wavelength $5000 \AA$ . Its work function is

1

15 J

2

16 \times 10^{- 14} J

3

4 \times 10^{- 19} J

4

4 \times 10^{- 18} J

Explanation:

C Given that, $λ_{o} = 5000 \AA = 5 \times 10^{- 7} m$ Work function, $ϕ_{o} = \frac{hc}{λ_{o}}$
$ϕ_{o} = \frac{6.62 \times 10^{- 34} \times 3 \times 10^{8}}{5 \times 10^{- 7}}$
$ϕ_{o} = 3.972 \times 10^{- 19} J$
$ϕ_{o} = 4 \times 10^{- 19} J$

Shift-I

Dual nature of radiation and Matter

142002 In the experimental study of photoelectric effect, if $V_{0}$ is the stopping potential and $v$ is the frequency of the incident light on the metal the slope of graph plotted for $V_{0}$ versus $v$ is (Where $h$ , e and $ϕ_{0}$ are Planck's constant, charge of electron and work function of the metal respectively.)

1

h

2

\frac{h}{e}

3

\frac{ϕ_{o}}{e}

4

ϕ_{o}

Explanation:

B According to the Einstein photoelectric equation -
${eV}_{o} = h v - ϕ_{o}$
$V_{o} = (\frac{h}{e}) v - \frac{ϕ_{o}}{e}$
$∵ Slope = \frac{h}{e}$

Shift-I

Dual nature of radiation and Matter

142005 When light of wavelength ' $λ$ ' is incident on photosensitive surface, photons of power ' $P$ ' are emitted. The number of photons (n) emitted in ' $t$ ' second is
$(h =$ Planck's constant, $c =$ velocity of light in vacuum)

1

\frac{P λ t}{hc}

2

\frac{hP}{λ tc}

3

\frac{P λ}{htc}

4

\frac{hc}{P λ t}

Explanation:

A Energy of each photon $= \frac{hc}{λ}$
If $n$ photons are emitted in the time t then the energy emitted in time $t$ is $\frac{nhc}{λ}$
Number of photons emitted in the $t$ second
i.e power $(P) = \frac{nhc}{λ t}$
$n = \frac{P λ t}{hc}$

MHT-CET 2020

Dual nature of radiation and Matter

142006 The maximum velocity of the photoelectron emitted by the metal surface is ' $v$ '. Charge and mass of the photoelectron is denoted by ' $e$ ' and ' $m$ ' respectively. The stopping potential in volt is

1

\frac{v^{2}}{(\frac{e}{m})}

2

\frac{v^{2}}{(\frac{m}{e})}

3

\frac{v^{2}}{2 (\frac{e}{m})}

4

\frac{v^{2}}{2 (\frac{m}{e})}

Explanation:

C We know that,
$(K . E)_{max} = \frac{1}{2} {mv}^{2} = {eV}_{0}$
Stopping potential $(V_{0}) = \frac{{mv}^{2}}{2 e}$
$V_{0} = \frac{v^{2}}{2 (\frac{e}{m})}$

MHT-CET 2020

Dual nature of radiation and Matter

142133 $6.4 \times 10^{- 9}$ joule is approximately

1 4 electron volt

2 6 electron volt

3 8 electron volt

4 1 electron volt

Explanation:

A We know that,
$1 eV = 1.6 \times 10^{- 19} J$
$J = \frac{1}{1.6 \times 10^{- 19}} eV$
$6.4 \times 10^{- 9} J = \frac{1}{1.6 \times 10^{- 19}} \times 6.4 \times 10^{- 19}$
$= 4 eV$

SRMJEEE - 2015

Dual nature of radiation and Matter

142001 Threshold frequency for photoelectric effect on sodium corresponds to a wavelength $5000 \AA$ . Its work function is

1

15 J

2

16 \times 10^{- 14} J

3

4 \times 10^{- 19} J

4

4 \times 10^{- 18} J

Explanation:

C Given that, $λ_{o} = 5000 \AA = 5 \times 10^{- 7} m$ Work function, $ϕ_{o} = \frac{hc}{λ_{o}}$
$ϕ_{o} = \frac{6.62 \times 10^{- 34} \times 3 \times 10^{8}}{5 \times 10^{- 7}}$
$ϕ_{o} = 3.972 \times 10^{- 19} J$
$ϕ_{o} = 4 \times 10^{- 19} J$

Shift-I

Dual nature of radiation and Matter

142002 In the experimental study of photoelectric effect, if $V_{0}$ is the stopping potential and $v$ is the frequency of the incident light on the metal the slope of graph plotted for $V_{0}$ versus $v$ is (Where $h$ , e and $ϕ_{0}$ are Planck's constant, charge of electron and work function of the metal respectively.)

1

h

2

\frac{h}{e}

3

\frac{ϕ_{o}}{e}

4

ϕ_{o}

Explanation:

B According to the Einstein photoelectric equation -
${eV}_{o} = h v - ϕ_{o}$
$V_{o} = (\frac{h}{e}) v - \frac{ϕ_{o}}{e}$
$∵ Slope = \frac{h}{e}$

Shift-I

Dual nature of radiation and Matter

142005 When light of wavelength ' $λ$ ' is incident on photosensitive surface, photons of power ' $P$ ' are emitted. The number of photons (n) emitted in ' $t$ ' second is
$(h =$ Planck's constant, $c =$ velocity of light in vacuum)

1

\frac{P λ t}{hc}

2

\frac{hP}{λ tc}

3

\frac{P λ}{htc}

4

\frac{hc}{P λ t}

Explanation:

A Energy of each photon $= \frac{hc}{λ}$
If $n$ photons are emitted in the time t then the energy emitted in time $t$ is $\frac{nhc}{λ}$
Number of photons emitted in the $t$ second
i.e power $(P) = \frac{nhc}{λ t}$
$n = \frac{P λ t}{hc}$

MHT-CET 2020

Dual nature of radiation and Matter

142006 The maximum velocity of the photoelectron emitted by the metal surface is ' $v$ '. Charge and mass of the photoelectron is denoted by ' $e$ ' and ' $m$ ' respectively. The stopping potential in volt is

1

\frac{v^{2}}{(\frac{e}{m})}

2

\frac{v^{2}}{(\frac{m}{e})}

3

\frac{v^{2}}{2 (\frac{e}{m})}

4

\frac{v^{2}}{2 (\frac{m}{e})}

Explanation:

C We know that,
$(K . E)_{max} = \frac{1}{2} {mv}^{2} = {eV}_{0}$
Stopping potential $(V_{0}) = \frac{{mv}^{2}}{2 e}$
$V_{0} = \frac{v^{2}}{2 (\frac{e}{m})}$

MHT-CET 2020

Dual nature of radiation and Matter

142133 $6.4 \times 10^{- 9}$ joule is approximately

1 4 electron volt

2 6 electron volt

3 8 electron volt

4 1 electron volt

Explanation:

A We know that,
$1 eV = 1.6 \times 10^{- 19} J$
$J = \frac{1}{1.6 \times 10^{- 19}} eV$
$6.4 \times 10^{- 9} J = \frac{1}{1.6 \times 10^{- 19}} \times 6.4 \times 10^{- 19}$
$= 4 eV$

SRMJEEE - 2015

Dual nature of radiation and Matter

142001 Threshold frequency for photoelectric effect on sodium corresponds to a wavelength $5000 \AA$ . Its work function is

1

15 J

2

16 \times 10^{- 14} J

3

4 \times 10^{- 19} J

4

4 \times 10^{- 18} J

Explanation:

C Given that, $λ_{o} = 5000 \AA = 5 \times 10^{- 7} m$ Work function, $ϕ_{o} = \frac{hc}{λ_{o}}$
$ϕ_{o} = \frac{6.62 \times 10^{- 34} \times 3 \times 10^{8}}{5 \times 10^{- 7}}$
$ϕ_{o} = 3.972 \times 10^{- 19} J$
$ϕ_{o} = 4 \times 10^{- 19} J$

Shift-I

Dual nature of radiation and Matter

142002 In the experimental study of photoelectric effect, if $V_{0}$ is the stopping potential and $v$ is the frequency of the incident light on the metal the slope of graph plotted for $V_{0}$ versus $v$ is (Where $h$ , e and $ϕ_{0}$ are Planck's constant, charge of electron and work function of the metal respectively.)

1

h

2

\frac{h}{e}

3

\frac{ϕ_{o}}{e}

4

ϕ_{o}

Explanation:

B According to the Einstein photoelectric equation -
${eV}_{o} = h v - ϕ_{o}$
$V_{o} = (\frac{h}{e}) v - \frac{ϕ_{o}}{e}$
$∵ Slope = \frac{h}{e}$

Shift-I

Dual nature of radiation and Matter

142005 When light of wavelength ' $λ$ ' is incident on photosensitive surface, photons of power ' $P$ ' are emitted. The number of photons (n) emitted in ' $t$ ' second is
$(h =$ Planck's constant, $c =$ velocity of light in vacuum)

1

\frac{P λ t}{hc}

2

\frac{hP}{λ tc}

3

\frac{P λ}{htc}

4

\frac{hc}{P λ t}

Explanation:

A Energy of each photon $= \frac{hc}{λ}$
If $n$ photons are emitted in the time t then the energy emitted in time $t$ is $\frac{nhc}{λ}$
Number of photons emitted in the $t$ second
i.e power $(P) = \frac{nhc}{λ t}$
$n = \frac{P λ t}{hc}$

MHT-CET 2020

Dual nature of radiation and Matter

142006 The maximum velocity of the photoelectron emitted by the metal surface is ' $v$ '. Charge and mass of the photoelectron is denoted by ' $e$ ' and ' $m$ ' respectively. The stopping potential in volt is

1

\frac{v^{2}}{(\frac{e}{m})}

2

\frac{v^{2}}{(\frac{m}{e})}

3

\frac{v^{2}}{2 (\frac{e}{m})}

4

\frac{v^{2}}{2 (\frac{m}{e})}

Explanation:

C We know that,
$(K . E)_{max} = \frac{1}{2} {mv}^{2} = {eV}_{0}$
Stopping potential $(V_{0}) = \frac{{mv}^{2}}{2 e}$
$V_{0} = \frac{v^{2}}{2 (\frac{e}{m})}$

MHT-CET 2020

Dual nature of radiation and Matter

142133 $6.4 \times 10^{- 9}$ joule is approximately

1 4 electron volt

2 6 electron volt

3 8 electron volt

4 1 electron volt

Explanation:

A We know that,
$1 eV = 1.6 \times 10^{- 19} J$
$J = \frac{1}{1.6 \times 10^{- 19}} eV$
$6.4 \times 10^{- 9} J = \frac{1}{1.6 \times 10^{- 19}} \times 6.4 \times 10^{- 19}$
$= 4 eV$

SRMJEEE - 2015

Dual nature of radiation and Matter

142001 Threshold frequency for photoelectric effect on sodium corresponds to a wavelength $5000 \AA$ . Its work function is

1

15 J

2

16 \times 10^{- 14} J

3

4 \times 10^{- 19} J

4

4 \times 10^{- 18} J

Explanation:

C Given that, $λ_{o} = 5000 \AA = 5 \times 10^{- 7} m$ Work function, $ϕ_{o} = \frac{hc}{λ_{o}}$
$ϕ_{o} = \frac{6.62 \times 10^{- 34} \times 3 \times 10^{8}}{5 \times 10^{- 7}}$
$ϕ_{o} = 3.972 \times 10^{- 19} J$
$ϕ_{o} = 4 \times 10^{- 19} J$

Shift-I

Dual nature of radiation and Matter

142002 In the experimental study of photoelectric effect, if $V_{0}$ is the stopping potential and $v$ is the frequency of the incident light on the metal the slope of graph plotted for $V_{0}$ versus $v$ is (Where $h$ , e and $ϕ_{0}$ are Planck's constant, charge of electron and work function of the metal respectively.)

1

h

2

\frac{h}{e}

3

\frac{ϕ_{o}}{e}

4

ϕ_{o}

Explanation:

B According to the Einstein photoelectric equation -
${eV}_{o} = h v - ϕ_{o}$
$V_{o} = (\frac{h}{e}) v - \frac{ϕ_{o}}{e}$
$∵ Slope = \frac{h}{e}$

Shift-I

Dual nature of radiation and Matter

142005 When light of wavelength ' $λ$ ' is incident on photosensitive surface, photons of power ' $P$ ' are emitted. The number of photons (n) emitted in ' $t$ ' second is
$(h =$ Planck's constant, $c =$ velocity of light in vacuum)

1

\frac{P λ t}{hc}

2

\frac{hP}{λ tc}

3

\frac{P λ}{htc}

4

\frac{hc}{P λ t}

Explanation:

A Energy of each photon $= \frac{hc}{λ}$
If $n$ photons are emitted in the time t then the energy emitted in time $t$ is $\frac{nhc}{λ}$
Number of photons emitted in the $t$ second
i.e power $(P) = \frac{nhc}{λ t}$
$n = \frac{P λ t}{hc}$

MHT-CET 2020

Dual nature of radiation and Matter

142006 The maximum velocity of the photoelectron emitted by the metal surface is ' $v$ '. Charge and mass of the photoelectron is denoted by ' $e$ ' and ' $m$ ' respectively. The stopping potential in volt is

1

\frac{v^{2}}{(\frac{e}{m})}

2

\frac{v^{2}}{(\frac{m}{e})}

3

\frac{v^{2}}{2 (\frac{e}{m})}

4

\frac{v^{2}}{2 (\frac{m}{e})}

Explanation:

C We know that,
$(K . E)_{max} = \frac{1}{2} {mv}^{2} = {eV}_{0}$
Stopping potential $(V_{0}) = \frac{{mv}^{2}}{2 e}$
$V_{0} = \frac{v^{2}}{2 (\frac{e}{m})}$

MHT-CET 2020

Dual nature of radiation and Matter

142133 $6.4 \times 10^{- 9}$ joule is approximately

1 4 electron volt

2 6 electron volt

3 8 electron volt

4 1 electron volt

Explanation:

A We know that,
$1 eV = 1.6 \times 10^{- 19} J$
$J = \frac{1}{1.6 \times 10^{- 19}} eV$
$6.4 \times 10^{- 9} J = \frac{1}{1.6 \times 10^{- 19}} \times 6.4 \times 10^{- 19}$
$= 4 eV$

SRMJEEE - 2015

Dual nature of radiation and Matter

142001 Threshold frequency for photoelectric effect on sodium corresponds to a wavelength $5000 \AA$ . Its work function is

1

15 J

2

16 \times 10^{- 14} J

3

4 \times 10^{- 19} J

4

4 \times 10^{- 18} J

Explanation:

C Given that, $λ_{o} = 5000 \AA = 5 \times 10^{- 7} m$ Work function, $ϕ_{o} = \frac{hc}{λ_{o}}$
$ϕ_{o} = \frac{6.62 \times 10^{- 34} \times 3 \times 10^{8}}{5 \times 10^{- 7}}$
$ϕ_{o} = 3.972 \times 10^{- 19} J$
$ϕ_{o} = 4 \times 10^{- 19} J$

Shift-I

Dual nature of radiation and Matter

142002 In the experimental study of photoelectric effect, if $V_{0}$ is the stopping potential and $v$ is the frequency of the incident light on the metal the slope of graph plotted for $V_{0}$ versus $v$ is (Where $h$ , e and $ϕ_{0}$ are Planck's constant, charge of electron and work function of the metal respectively.)

1

h

2

\frac{h}{e}

3

\frac{ϕ_{o}}{e}

4

ϕ_{o}

Explanation:

B According to the Einstein photoelectric equation -
${eV}_{o} = h v - ϕ_{o}$
$V_{o} = (\frac{h}{e}) v - \frac{ϕ_{o}}{e}$
$∵ Slope = \frac{h}{e}$

Shift-I

Dual nature of radiation and Matter

142005 When light of wavelength ' $λ$ ' is incident on photosensitive surface, photons of power ' $P$ ' are emitted. The number of photons (n) emitted in ' $t$ ' second is
$(h =$ Planck's constant, $c =$ velocity of light in vacuum)

1

\frac{P λ t}{hc}

2

\frac{hP}{λ tc}

3

\frac{P λ}{htc}

4

\frac{hc}{P λ t}

Explanation:

A Energy of each photon $= \frac{hc}{λ}$
If $n$ photons are emitted in the time t then the energy emitted in time $t$ is $\frac{nhc}{λ}$
Number of photons emitted in the $t$ second
i.e power $(P) = \frac{nhc}{λ t}$
$n = \frac{P λ t}{hc}$

MHT-CET 2020

Dual nature of radiation and Matter

142006 The maximum velocity of the photoelectron emitted by the metal surface is ' $v$ '. Charge and mass of the photoelectron is denoted by ' $e$ ' and ' $m$ ' respectively. The stopping potential in volt is

1

\frac{v^{2}}{(\frac{e}{m})}

2

\frac{v^{2}}{(\frac{m}{e})}

3

\frac{v^{2}}{2 (\frac{e}{m})}

4

\frac{v^{2}}{2 (\frac{m}{e})}

Explanation:

C We know that,
$(K . E)_{max} = \frac{1}{2} {mv}^{2} = {eV}_{0}$
Stopping potential $(V_{0}) = \frac{{mv}^{2}}{2 e}$
$V_{0} = \frac{v^{2}}{2 (\frac{e}{m})}$

MHT-CET 2020

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