116761
In a group of 100 persons, 80 people can speak Malayalam and 60 can speak English. The number of people who speak English only is
1 40
2 30
3 20
4 25
5 35
Explanation:
C Total number of person \(=100\) Let \(A\) be the set of person who speak malayalum Let \(B\) be the set of person who speak English \(\begin{array}{rl} n(A)=80 & n(B)=60 \\ n(A \cup B) & =100 \\ n(A \cup B) & =n(A)+n(B)-n(A \cap B) \\ 100 & =80+60-n(A \cap B) \\ 140-100 & =n(A \cap B) \\ 40 & =n(A \cap B) \end{array}\) \(\therefore\) The person who speak English only \(n(B)-n(A \cap B)\) \(=60-40 \\ =20\)
Kerala CEE-2020
Sets, Relation and Function
116762
Let \(A\) and \(B\) be finite sets such that \(n(A-B)=\) \(18, n(A \cap B)=25\) and \(n(A \cup B)=70\). Then \(n(B)\) is equal to
116763
In a class of 100 student, there are 70 boys whose average marks in a subject are 75 . If the average marks of the complete class is 72 , then what is the average of the girls?
1 73
2 85
3 68
4 74
5 65
Explanation:
E Total no. of student in class \(=100\) Number of boys \(=70\) Average marks of boys \(=75\) So, Total marks of boys \(=70 \times 75=5250\) And, Total marks of the class \(=72 \times 100\) \(=7200\) Total marks of girls \(=7200-5250\) \(=1950\) Average of the girls \(=\frac{1950}{30}\) \(=65\)
Kerala CEE-2019
Sets, Relation and Function
116764
In a flight 50 people speak Hindi, 20 speak English and 10 speak both English and Hindi. The number of people who speak at least one of the languages is
1 40
2 50
3 20
4 80
5 60
Explanation:
E Let \(\mathrm{H}=\) people who speak Hindi \(\mathrm{E}=\) People who speak English Given \(\mathrm{N}(\mathrm{H})=50, \mathrm{n}(\mathrm{E})=20, \mathrm{n}(\mathrm{H} \cap \mathrm{E})=10\) \(\therefore\) Number of people who speak at least two language \(\mathrm{n}(\mathrm{H} \cup \mathrm{E}) =\mathrm{n}(\mathrm{H})+\mathrm{n}(\mathrm{E})-\mathrm{n}(\mathrm{H} \cap \mathrm{E})\) \(=50+20-10\) \(=60\)
116761
In a group of 100 persons, 80 people can speak Malayalam and 60 can speak English. The number of people who speak English only is
1 40
2 30
3 20
4 25
5 35
Explanation:
C Total number of person \(=100\) Let \(A\) be the set of person who speak malayalum Let \(B\) be the set of person who speak English \(\begin{array}{rl} n(A)=80 & n(B)=60 \\ n(A \cup B) & =100 \\ n(A \cup B) & =n(A)+n(B)-n(A \cap B) \\ 100 & =80+60-n(A \cap B) \\ 140-100 & =n(A \cap B) \\ 40 & =n(A \cap B) \end{array}\) \(\therefore\) The person who speak English only \(n(B)-n(A \cap B)\) \(=60-40 \\ =20\)
Kerala CEE-2020
Sets, Relation and Function
116762
Let \(A\) and \(B\) be finite sets such that \(n(A-B)=\) \(18, n(A \cap B)=25\) and \(n(A \cup B)=70\). Then \(n(B)\) is equal to
116763
In a class of 100 student, there are 70 boys whose average marks in a subject are 75 . If the average marks of the complete class is 72 , then what is the average of the girls?
1 73
2 85
3 68
4 74
5 65
Explanation:
E Total no. of student in class \(=100\) Number of boys \(=70\) Average marks of boys \(=75\) So, Total marks of boys \(=70 \times 75=5250\) And, Total marks of the class \(=72 \times 100\) \(=7200\) Total marks of girls \(=7200-5250\) \(=1950\) Average of the girls \(=\frac{1950}{30}\) \(=65\)
Kerala CEE-2019
Sets, Relation and Function
116764
In a flight 50 people speak Hindi, 20 speak English and 10 speak both English and Hindi. The number of people who speak at least one of the languages is
1 40
2 50
3 20
4 80
5 60
Explanation:
E Let \(\mathrm{H}=\) people who speak Hindi \(\mathrm{E}=\) People who speak English Given \(\mathrm{N}(\mathrm{H})=50, \mathrm{n}(\mathrm{E})=20, \mathrm{n}(\mathrm{H} \cap \mathrm{E})=10\) \(\therefore\) Number of people who speak at least two language \(\mathrm{n}(\mathrm{H} \cup \mathrm{E}) =\mathrm{n}(\mathrm{H})+\mathrm{n}(\mathrm{E})-\mathrm{n}(\mathrm{H} \cap \mathrm{E})\) \(=50+20-10\) \(=60\)
116761
In a group of 100 persons, 80 people can speak Malayalam and 60 can speak English. The number of people who speak English only is
1 40
2 30
3 20
4 25
5 35
Explanation:
C Total number of person \(=100\) Let \(A\) be the set of person who speak malayalum Let \(B\) be the set of person who speak English \(\begin{array}{rl} n(A)=80 & n(B)=60 \\ n(A \cup B) & =100 \\ n(A \cup B) & =n(A)+n(B)-n(A \cap B) \\ 100 & =80+60-n(A \cap B) \\ 140-100 & =n(A \cap B) \\ 40 & =n(A \cap B) \end{array}\) \(\therefore\) The person who speak English only \(n(B)-n(A \cap B)\) \(=60-40 \\ =20\)
Kerala CEE-2020
Sets, Relation and Function
116762
Let \(A\) and \(B\) be finite sets such that \(n(A-B)=\) \(18, n(A \cap B)=25\) and \(n(A \cup B)=70\). Then \(n(B)\) is equal to
116763
In a class of 100 student, there are 70 boys whose average marks in a subject are 75 . If the average marks of the complete class is 72 , then what is the average of the girls?
1 73
2 85
3 68
4 74
5 65
Explanation:
E Total no. of student in class \(=100\) Number of boys \(=70\) Average marks of boys \(=75\) So, Total marks of boys \(=70 \times 75=5250\) And, Total marks of the class \(=72 \times 100\) \(=7200\) Total marks of girls \(=7200-5250\) \(=1950\) Average of the girls \(=\frac{1950}{30}\) \(=65\)
Kerala CEE-2019
Sets, Relation and Function
116764
In a flight 50 people speak Hindi, 20 speak English and 10 speak both English and Hindi. The number of people who speak at least one of the languages is
1 40
2 50
3 20
4 80
5 60
Explanation:
E Let \(\mathrm{H}=\) people who speak Hindi \(\mathrm{E}=\) People who speak English Given \(\mathrm{N}(\mathrm{H})=50, \mathrm{n}(\mathrm{E})=20, \mathrm{n}(\mathrm{H} \cap \mathrm{E})=10\) \(\therefore\) Number of people who speak at least two language \(\mathrm{n}(\mathrm{H} \cup \mathrm{E}) =\mathrm{n}(\mathrm{H})+\mathrm{n}(\mathrm{E})-\mathrm{n}(\mathrm{H} \cap \mathrm{E})\) \(=50+20-10\) \(=60\)
NEET Test Series from KOTA - 10 Papers In MS WORD
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Sets, Relation and Function
116761
In a group of 100 persons, 80 people can speak Malayalam and 60 can speak English. The number of people who speak English only is
1 40
2 30
3 20
4 25
5 35
Explanation:
C Total number of person \(=100\) Let \(A\) be the set of person who speak malayalum Let \(B\) be the set of person who speak English \(\begin{array}{rl} n(A)=80 & n(B)=60 \\ n(A \cup B) & =100 \\ n(A \cup B) & =n(A)+n(B)-n(A \cap B) \\ 100 & =80+60-n(A \cap B) \\ 140-100 & =n(A \cap B) \\ 40 & =n(A \cap B) \end{array}\) \(\therefore\) The person who speak English only \(n(B)-n(A \cap B)\) \(=60-40 \\ =20\)
Kerala CEE-2020
Sets, Relation and Function
116762
Let \(A\) and \(B\) be finite sets such that \(n(A-B)=\) \(18, n(A \cap B)=25\) and \(n(A \cup B)=70\). Then \(n(B)\) is equal to
116763
In a class of 100 student, there are 70 boys whose average marks in a subject are 75 . If the average marks of the complete class is 72 , then what is the average of the girls?
1 73
2 85
3 68
4 74
5 65
Explanation:
E Total no. of student in class \(=100\) Number of boys \(=70\) Average marks of boys \(=75\) So, Total marks of boys \(=70 \times 75=5250\) And, Total marks of the class \(=72 \times 100\) \(=7200\) Total marks of girls \(=7200-5250\) \(=1950\) Average of the girls \(=\frac{1950}{30}\) \(=65\)
Kerala CEE-2019
Sets, Relation and Function
116764
In a flight 50 people speak Hindi, 20 speak English and 10 speak both English and Hindi. The number of people who speak at least one of the languages is
1 40
2 50
3 20
4 80
5 60
Explanation:
E Let \(\mathrm{H}=\) people who speak Hindi \(\mathrm{E}=\) People who speak English Given \(\mathrm{N}(\mathrm{H})=50, \mathrm{n}(\mathrm{E})=20, \mathrm{n}(\mathrm{H} \cap \mathrm{E})=10\) \(\therefore\) Number of people who speak at least two language \(\mathrm{n}(\mathrm{H} \cup \mathrm{E}) =\mathrm{n}(\mathrm{H})+\mathrm{n}(\mathrm{E})-\mathrm{n}(\mathrm{H} \cap \mathrm{E})\) \(=50+20-10\) \(=60\)
