Explanation:
B \(100^{\text {th }}\) place can be occupied by \(1,2,3,4,6,7\),
8 , and 9 ( 8 ways)
Similarly
\(10^{\text {th }}\) place can be occupied
\(0,1,2,3,4,5,6,7,8\), and 9 (9ways)
\(1^{\text {th }}\) place can occupied by \(0,2,4,6\) and 8 ( 5 ways)
\(\because\) Total no of ways \(=8 \times 9 \times 5\)
\(=360\)
5 ! must be followed by 7
So only possible way is \(57 \mathrm{x}\)
So, total no of ways \(=1 \times 1 \times 5\)
\(=5\)
\(360+5=365\)