Equation of Hyperbola
Hyperbola

120706 The distance between the foci of the conic \(7 x^2\) \(9 y^2=63\) is
#[Qdiff: Hard, QCat: Numerical Based, examname: BCECE-2010], \(\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\), Comparing Standard equation of ellipse, \(\mathrm{a}^2=12-\mathrm{k} >0 \text { and } \mathrm{b}^2=\mathrm{k}-8>0\), \(\mathrm{k}\lt 12 \quad \mathrm{k} >8\)Hence, a hyperbola, if \(8\lt \mathrm{k}\lt 12\)., 985. Find the equation of chord of \(x^2-y^2=9\) which is bisected at \((5,-3)\).,

1 8
2 4
3 3
4 7
Hyperbola

120707 The latus rectum of the hyperbola is
\(9 x^2-16 y^2-18 x-32 y-151=0\)

1 \(9 / 4\)
2 \(3 / 2\)
3 9
4 \(9 / 2\)
Hyperbola

120708 The foci of the hyperbola \(9 x^2-16 y^2=144\) are

1 \(( \pm 4,0)\)
2 \((0, \pm 4)\)
3 \(( \pm 5,0)\)
4 \((0, \pm 5)\)
Hyperbola

120709 The eccentricity of the hyperbola with latus rectum 12 and semiconjugate axis \(2 \sqrt{3}\), is

1 3
2 \(\sqrt{\frac{3}{2}}\)
3 \(2 \sqrt{3}\)
4 2
Hyperbola

120710 The hyperbola though foci of ellipse \(\frac{x^2}{25}+\frac{y^2}{16}=1\) and transverse and conjugate axes are coincide with the major and minor axis of the ellipse. If product of eccentricities of ellipse and hyperbola is 1 then equation of hyperbola is

1 \(x^2-y^2=9\)
2 \(\frac{x^2}{9}-\frac{y^2}{16}=1\)
3 \(\frac{x^2}{9}-\frac{y^2}{25}=1\)
4 \(\frac{x^2}{16}-\frac{y^2}{25}=1\)
Hyperbola

120706 The distance between the foci of the conic \(7 x^2\) \(9 y^2=63\) is
#[Qdiff: Hard, QCat: Numerical Based, examname: BCECE-2010], \(\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\), Comparing Standard equation of ellipse, \(\mathrm{a}^2=12-\mathrm{k} >0 \text { and } \mathrm{b}^2=\mathrm{k}-8>0\), \(\mathrm{k}\lt 12 \quad \mathrm{k} >8\)Hence, a hyperbola, if \(8\lt \mathrm{k}\lt 12\)., 985. Find the equation of chord of \(x^2-y^2=9\) which is bisected at \((5,-3)\).,

1 8
2 4
3 3
4 7
Hyperbola

120707 The latus rectum of the hyperbola is
\(9 x^2-16 y^2-18 x-32 y-151=0\)

1 \(9 / 4\)
2 \(3 / 2\)
3 9
4 \(9 / 2\)
Hyperbola

120708 The foci of the hyperbola \(9 x^2-16 y^2=144\) are

1 \(( \pm 4,0)\)
2 \((0, \pm 4)\)
3 \(( \pm 5,0)\)
4 \((0, \pm 5)\)
Hyperbola

120709 The eccentricity of the hyperbola with latus rectum 12 and semiconjugate axis \(2 \sqrt{3}\), is

1 3
2 \(\sqrt{\frac{3}{2}}\)
3 \(2 \sqrt{3}\)
4 2
Hyperbola

120710 The hyperbola though foci of ellipse \(\frac{x^2}{25}+\frac{y^2}{16}=1\) and transverse and conjugate axes are coincide with the major and minor axis of the ellipse. If product of eccentricities of ellipse and hyperbola is 1 then equation of hyperbola is

1 \(x^2-y^2=9\)
2 \(\frac{x^2}{9}-\frac{y^2}{16}=1\)
3 \(\frac{x^2}{9}-\frac{y^2}{25}=1\)
4 \(\frac{x^2}{16}-\frac{y^2}{25}=1\)
Hyperbola

120706 The distance between the foci of the conic \(7 x^2\) \(9 y^2=63\) is
#[Qdiff: Hard, QCat: Numerical Based, examname: BCECE-2010], \(\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\), Comparing Standard equation of ellipse, \(\mathrm{a}^2=12-\mathrm{k} >0 \text { and } \mathrm{b}^2=\mathrm{k}-8>0\), \(\mathrm{k}\lt 12 \quad \mathrm{k} >8\)Hence, a hyperbola, if \(8\lt \mathrm{k}\lt 12\)., 985. Find the equation of chord of \(x^2-y^2=9\) which is bisected at \((5,-3)\).,

1 8
2 4
3 3
4 7
Hyperbola

120707 The latus rectum of the hyperbola is
\(9 x^2-16 y^2-18 x-32 y-151=0\)

1 \(9 / 4\)
2 \(3 / 2\)
3 9
4 \(9 / 2\)
Hyperbola

120708 The foci of the hyperbola \(9 x^2-16 y^2=144\) are

1 \(( \pm 4,0)\)
2 \((0, \pm 4)\)
3 \(( \pm 5,0)\)
4 \((0, \pm 5)\)
Hyperbola

120709 The eccentricity of the hyperbola with latus rectum 12 and semiconjugate axis \(2 \sqrt{3}\), is

1 3
2 \(\sqrt{\frac{3}{2}}\)
3 \(2 \sqrt{3}\)
4 2
Hyperbola

120710 The hyperbola though foci of ellipse \(\frac{x^2}{25}+\frac{y^2}{16}=1\) and transverse and conjugate axes are coincide with the major and minor axis of the ellipse. If product of eccentricities of ellipse and hyperbola is 1 then equation of hyperbola is

1 \(x^2-y^2=9\)
2 \(\frac{x^2}{9}-\frac{y^2}{16}=1\)
3 \(\frac{x^2}{9}-\frac{y^2}{25}=1\)
4 \(\frac{x^2}{16}-\frac{y^2}{25}=1\)
Hyperbola

120706 The distance between the foci of the conic \(7 x^2\) \(9 y^2=63\) is
#[Qdiff: Hard, QCat: Numerical Based, examname: BCECE-2010], \(\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\), Comparing Standard equation of ellipse, \(\mathrm{a}^2=12-\mathrm{k} >0 \text { and } \mathrm{b}^2=\mathrm{k}-8>0\), \(\mathrm{k}\lt 12 \quad \mathrm{k} >8\)Hence, a hyperbola, if \(8\lt \mathrm{k}\lt 12\)., 985. Find the equation of chord of \(x^2-y^2=9\) which is bisected at \((5,-3)\).,

1 8
2 4
3 3
4 7
Hyperbola

120707 The latus rectum of the hyperbola is
\(9 x^2-16 y^2-18 x-32 y-151=0\)

1 \(9 / 4\)
2 \(3 / 2\)
3 9
4 \(9 / 2\)
Hyperbola

120708 The foci of the hyperbola \(9 x^2-16 y^2=144\) are

1 \(( \pm 4,0)\)
2 \((0, \pm 4)\)
3 \(( \pm 5,0)\)
4 \((0, \pm 5)\)
Hyperbola

120709 The eccentricity of the hyperbola with latus rectum 12 and semiconjugate axis \(2 \sqrt{3}\), is

1 3
2 \(\sqrt{\frac{3}{2}}\)
3 \(2 \sqrt{3}\)
4 2
Hyperbola

120710 The hyperbola though foci of ellipse \(\frac{x^2}{25}+\frac{y^2}{16}=1\) and transverse and conjugate axes are coincide with the major and minor axis of the ellipse. If product of eccentricities of ellipse and hyperbola is 1 then equation of hyperbola is

1 \(x^2-y^2=9\)
2 \(\frac{x^2}{9}-\frac{y^2}{16}=1\)
3 \(\frac{x^2}{9}-\frac{y^2}{25}=1\)
4 \(\frac{x^2}{16}-\frac{y^2}{25}=1\)
Hyperbola

120706 The distance between the foci of the conic \(7 x^2\) \(9 y^2=63\) is
#[Qdiff: Hard, QCat: Numerical Based, examname: BCECE-2010], \(\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\), Comparing Standard equation of ellipse, \(\mathrm{a}^2=12-\mathrm{k} >0 \text { and } \mathrm{b}^2=\mathrm{k}-8>0\), \(\mathrm{k}\lt 12 \quad \mathrm{k} >8\)Hence, a hyperbola, if \(8\lt \mathrm{k}\lt 12\)., 985. Find the equation of chord of \(x^2-y^2=9\) which is bisected at \((5,-3)\).,

1 8
2 4
3 3
4 7
Hyperbola

120707 The latus rectum of the hyperbola is
\(9 x^2-16 y^2-18 x-32 y-151=0\)

1 \(9 / 4\)
2 \(3 / 2\)
3 9
4 \(9 / 2\)
Hyperbola

120708 The foci of the hyperbola \(9 x^2-16 y^2=144\) are

1 \(( \pm 4,0)\)
2 \((0, \pm 4)\)
3 \(( \pm 5,0)\)
4 \((0, \pm 5)\)
Hyperbola

120709 The eccentricity of the hyperbola with latus rectum 12 and semiconjugate axis \(2 \sqrt{3}\), is

1 3
2 \(\sqrt{\frac{3}{2}}\)
3 \(2 \sqrt{3}\)
4 2
Hyperbola

120710 The hyperbola though foci of ellipse \(\frac{x^2}{25}+\frac{y^2}{16}=1\) and transverse and conjugate axes are coincide with the major and minor axis of the ellipse. If product of eccentricities of ellipse and hyperbola is 1 then equation of hyperbola is

1 \(x^2-y^2=9\)
2 \(\frac{x^2}{9}-\frac{y^2}{16}=1\)
3 \(\frac{x^2}{9}-\frac{y^2}{25}=1\)
4 \(\frac{x^2}{16}-\frac{y^2}{25}=1\)