121356 The distance of the point \((3,4,5)\) from the point of intersection of the line \(\frac{x-3}{1}=\frac{y-4}{2}=\frac{z-5}{2}\) and plane \(x+y+z=2\) is

121359 The distance of a point \((1,2,-1)\) from the plane \(\mathbf{x}-\mathbf{2 y}+\mathbf{4 z}+\mathbf{1 0}=\mathbf{0}\) is

121360 The length of the perpendicular from the point \((1,2,3)\) on the line \(\frac{x-6}{3}=\frac{y-7}{2}=\frac{z-7}{-2}\) is

121362 Image point of \((1,3,4)\) in the plane \(2 x-y+z+\) \(\mathbf{3}=\mathbf{0}\) will be

121363 The distance of the point \((1,-2,3)\) from the plane \(x-y+z=5\) measured parallel to the line \(\overrightarrow{\mathbf{r}}=(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+4 \hat{\mathbf{k}})+\mathbf{t}(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}-6 \hat{\mathbf{k}})\) will be

121356 The distance of the point \((3,4,5)\) from the point of intersection of the line \(\frac{x-3}{1}=\frac{y-4}{2}=\frac{z-5}{2}\) and plane \(x+y+z=2\) is

121359 The distance of a point \((1,2,-1)\) from the plane \(\mathbf{x}-\mathbf{2 y}+\mathbf{4 z}+\mathbf{1 0}=\mathbf{0}\) is

121360 The length of the perpendicular from the point \((1,2,3)\) on the line \(\frac{x-6}{3}=\frac{y-7}{2}=\frac{z-7}{-2}\) is

121362 Image point of \((1,3,4)\) in the plane \(2 x-y+z+\) \(\mathbf{3}=\mathbf{0}\) will be

121363 The distance of the point \((1,-2,3)\) from the plane \(x-y+z=5\) measured parallel to the line \(\overrightarrow{\mathbf{r}}=(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+4 \hat{\mathbf{k}})+\mathbf{t}(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}-6 \hat{\mathbf{k}})\) will be

121356 The distance of the point \((3,4,5)\) from the point of intersection of the line \(\frac{x-3}{1}=\frac{y-4}{2}=\frac{z-5}{2}\) and plane \(x+y+z=2\) is

121359 The distance of a point \((1,2,-1)\) from the plane \(\mathbf{x}-\mathbf{2 y}+\mathbf{4 z}+\mathbf{1 0}=\mathbf{0}\) is

121360 The length of the perpendicular from the point \((1,2,3)\) on the line \(\frac{x-6}{3}=\frac{y-7}{2}=\frac{z-7}{-2}\) is

121362 Image point of \((1,3,4)\) in the plane \(2 x-y+z+\) \(\mathbf{3}=\mathbf{0}\) will be

121363 The distance of the point \((1,-2,3)\) from the plane \(x-y+z=5\) measured parallel to the line \(\overrightarrow{\mathbf{r}}=(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+4 \hat{\mathbf{k}})+\mathbf{t}(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}-6 \hat{\mathbf{k}})\) will be

121356 The distance of the point \((3,4,5)\) from the point of intersection of the line \(\frac{x-3}{1}=\frac{y-4}{2}=\frac{z-5}{2}\) and plane \(x+y+z=2\) is

121359 The distance of a point \((1,2,-1)\) from the plane \(\mathbf{x}-\mathbf{2 y}+\mathbf{4 z}+\mathbf{1 0}=\mathbf{0}\) is

121360 The length of the perpendicular from the point \((1,2,3)\) on the line \(\frac{x-6}{3}=\frac{y-7}{2}=\frac{z-7}{-2}\) is

121362 Image point of \((1,3,4)\) in the plane \(2 x-y+z+\) \(\mathbf{3}=\mathbf{0}\) will be

121363 The distance of the point \((1,-2,3)\) from the plane \(x-y+z=5\) measured parallel to the line \(\overrightarrow{\mathbf{r}}=(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+4 \hat{\mathbf{k}})+\mathbf{t}(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}-6 \hat{\mathbf{k}})\) will be

121356 The distance of the point \((3,4,5)\) from the point of intersection of the line \(\frac{x-3}{1}=\frac{y-4}{2}=\frac{z-5}{2}\) and plane \(x+y+z=2\) is

121359 The distance of a point \((1,2,-1)\) from the plane \(\mathbf{x}-\mathbf{2 y}+\mathbf{4 z}+\mathbf{1 0}=\mathbf{0}\) is

121360 The length of the perpendicular from the point \((1,2,3)\) on the line \(\frac{x-6}{3}=\frac{y-7}{2}=\frac{z-7}{-2}\) is

121362 Image point of \((1,3,4)\) in the plane \(2 x-y+z+\) \(\mathbf{3}=\mathbf{0}\) will be

121363 The distance of the point \((1,-2,3)\) from the plane \(x-y+z=5\) measured parallel to the line \(\overrightarrow{\mathbf{r}}=(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+4 \hat{\mathbf{k}})+\mathbf{t}(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}-6 \hat{\mathbf{k}})\) will be