Explanation:
D Given, \(x \text { intercept }=-2, \quad y \text { intercept }=3\)
Let the circle be
\(\mathrm{x}^2+\mathrm{y}^2+2 \mathrm{gx}+2 \mathrm{fy}+\mathrm{c}=0\)
\((0,0),(-2,0),(0,3)\)
\((0,0) \rightarrow \mathrm{c}=0\)
\((-2,0) \rightarrow 4-4 \mathrm{~g}=0\)
\(\mathrm{~g}=1\)
\((0,3) \rightarrow 9+6 \mathrm{f}=0\)
\(6 \mathrm{f}=-9\)
\(f=\frac{-9}{6}=-3 / 2\)
Required equation of circle
\(x^2+y^2+2 x-3 y=0\)