88774 If \(A(4,3,2), B(5,4,6), C(-1,-1,5)\) are vertices of a triangle, then the coordinates of the point in which the bisector of the angle \(A\) meet the side \(B C\) is

88775 Let \(P\) be the point of intersection of the lines \(\mathrm{L}_{1} \equiv \mathrm{x}-\mathrm{y}-\mathbf{7}=\mathbf{0}\) and \(\mathrm{L}_{2} \equiv \mathrm{x}+\mathrm{y}-\mathbf{5}=\mathbf{0} . \mathrm{A}\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)\) and \(B\left(x_{2}, y_{2}\right)\) are points on the lines \(l_{1}=0\) and \(l_{2}\) \(=0\) respectively such that \(P A=3 \sqrt{2}, P B=\) \(\sqrt{2}, x_{1}, y_{1} \geq 0, x_{2} y_{2} \geq 0\), then the angle made by the line segment \(A B\) at the origin is

88776 A bisector of the angle between the normal's of the planes \(4 x+3 y=5\) and \(x+2 y+2 z=4\) is along the vector

88777 If the vertices of a triangle \(\mathrm{ABC}\) are \(\mathrm{A}(1,7), \mathrm{B}\) \((-5,-1)\) and \(C(7,4)\), then the equation of a bisector of \(\triangle \mathrm{ABC}\) is

88774 If \(A(4,3,2), B(5,4,6), C(-1,-1,5)\) are vertices of a triangle, then the coordinates of the point in which the bisector of the angle \(A\) meet the side \(B C\) is

88775 Let \(P\) be the point of intersection of the lines \(\mathrm{L}_{1} \equiv \mathrm{x}-\mathrm{y}-\mathbf{7}=\mathbf{0}\) and \(\mathrm{L}_{2} \equiv \mathrm{x}+\mathrm{y}-\mathbf{5}=\mathbf{0} . \mathrm{A}\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)\) and \(B\left(x_{2}, y_{2}\right)\) are points on the lines \(l_{1}=0\) and \(l_{2}\) \(=0\) respectively such that \(P A=3 \sqrt{2}, P B=\) \(\sqrt{2}, x_{1}, y_{1} \geq 0, x_{2} y_{2} \geq 0\), then the angle made by the line segment \(A B\) at the origin is

88776 A bisector of the angle between the normal's of the planes \(4 x+3 y=5\) and \(x+2 y+2 z=4\) is along the vector

88777 If the vertices of a triangle \(\mathrm{ABC}\) are \(\mathrm{A}(1,7), \mathrm{B}\) \((-5,-1)\) and \(C(7,4)\), then the equation of a bisector of \(\triangle \mathrm{ABC}\) is

88774 If \(A(4,3,2), B(5,4,6), C(-1,-1,5)\) are vertices of a triangle, then the coordinates of the point in which the bisector of the angle \(A\) meet the side \(B C\) is

88775 Let \(P\) be the point of intersection of the lines \(\mathrm{L}_{1} \equiv \mathrm{x}-\mathrm{y}-\mathbf{7}=\mathbf{0}\) and \(\mathrm{L}_{2} \equiv \mathrm{x}+\mathrm{y}-\mathbf{5}=\mathbf{0} . \mathrm{A}\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)\) and \(B\left(x_{2}, y_{2}\right)\) are points on the lines \(l_{1}=0\) and \(l_{2}\) \(=0\) respectively such that \(P A=3 \sqrt{2}, P B=\) \(\sqrt{2}, x_{1}, y_{1} \geq 0, x_{2} y_{2} \geq 0\), then the angle made by the line segment \(A B\) at the origin is

88776 A bisector of the angle between the normal's of the planes \(4 x+3 y=5\) and \(x+2 y+2 z=4\) is along the vector

88777 If the vertices of a triangle \(\mathrm{ABC}\) are \(\mathrm{A}(1,7), \mathrm{B}\) \((-5,-1)\) and \(C(7,4)\), then the equation of a bisector of \(\triangle \mathrm{ABC}\) is

88774 If \(A(4,3,2), B(5,4,6), C(-1,-1,5)\) are vertices of a triangle, then the coordinates of the point in which the bisector of the angle \(A\) meet the side \(B C\) is

88775 Let \(P\) be the point of intersection of the lines \(\mathrm{L}_{1} \equiv \mathrm{x}-\mathrm{y}-\mathbf{7}=\mathbf{0}\) and \(\mathrm{L}_{2} \equiv \mathrm{x}+\mathrm{y}-\mathbf{5}=\mathbf{0} . \mathrm{A}\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)\) and \(B\left(x_{2}, y_{2}\right)\) are points on the lines \(l_{1}=0\) and \(l_{2}\) \(=0\) respectively such that \(P A=3 \sqrt{2}, P B=\) \(\sqrt{2}, x_{1}, y_{1} \geq 0, x_{2} y_{2} \geq 0\), then the angle made by the line segment \(A B\) at the origin is

88776 A bisector of the angle between the normal's of the planes \(4 x+3 y=5\) and \(x+2 y+2 z=4\) is along the vector

88777 If the vertices of a triangle \(\mathrm{ABC}\) are \(\mathrm{A}(1,7), \mathrm{B}\) \((-5,-1)\) and \(C(7,4)\), then the equation of a bisector of \(\triangle \mathrm{ABC}\) is