Explanation:
(C) : Given equation of circle is,
\(x^{2}+y^{2}=8\)
centre \((0,0)\), radius \((r)=2 \sqrt{2}\)
Since, The chord of the circle makes equal intercepts of length 'a' on co-ordinate axis.
So, equation of chord is,
\(x \pm y= \pm a\)
Now, since the chord intersect the given circle at two distinct point. So, the length of perpendicular from \((0,0)\) to the chord is less than radius.
\(\left|\frac{ \pm \mathrm{a}}{\sqrt{2}}\right|\lt 2 \sqrt{2} \Rightarrow \frac{\mathrm{a}^{2}}{2}\lt 8\)
\(\mathrm{a}^{2}\lt 16\)
\(|\mathrm{a}|\lt 4\)