140807 A small block of mass $100 \mathrm{~g}$ is tied to a spring of spring constant $7.5 \mathrm{~N} / \mathrm{m}$ and length $20 \mathrm{~cm}$. the other end of spring is fixed at a particular point $A$. If the block moves in a circular path on a smooth horizontal surface with constant angular velocity $5 \mathrm{rad} / \mathrm{s}$ about point $A$, then tension in the spring is

140808 If the amplitude of a lightly damped oscillator decreases by $1.5 \%$ then the mechanical energy of the oscillator lost in each cycle is

140809 The amplitude of a damped oscillator varies with time as $A(t)=A_{0} \exp (-b t / 2 m)$ where $b=$ $70 \mathrm{~g} / \mathrm{s}$ and $\mathrm{m}=200 \mathrm{~g}$. How long does it take for the mechanical energy to drop to one - fourth of its initial value?
[Take $\ln 2=0.7]$

140810 The amplitude of a damped oscillator is known to decreases to 0.9 times its original magnitude in 5 seconds. Approximately, by how many times its original magnitude will its amplitude decrease after another 10 seconds?

140811 A particle of mass ' $m$ ' is under an influence of a force $\overrightarrow{\mathbf{F}}=-\mathbf{k} \overrightarrow{\mathbf{x}}+\overrightarrow{\mathbf{F}}_{0}$. The particle when disturbed will oscillate

140807 A small block of mass $100 \mathrm{~g}$ is tied to a spring of spring constant $7.5 \mathrm{~N} / \mathrm{m}$ and length $20 \mathrm{~cm}$. the other end of spring is fixed at a particular point $A$. If the block moves in a circular path on a smooth horizontal surface with constant angular velocity $5 \mathrm{rad} / \mathrm{s}$ about point $A$, then tension in the spring is

140808 If the amplitude of a lightly damped oscillator decreases by $1.5 \%$ then the mechanical energy of the oscillator lost in each cycle is

140809 The amplitude of a damped oscillator varies with time as $A(t)=A_{0} \exp (-b t / 2 m)$ where $b=$ $70 \mathrm{~g} / \mathrm{s}$ and $\mathrm{m}=200 \mathrm{~g}$. How long does it take for the mechanical energy to drop to one - fourth of its initial value?
[Take $\ln 2=0.7]$

140810 The amplitude of a damped oscillator is known to decreases to 0.9 times its original magnitude in 5 seconds. Approximately, by how many times its original magnitude will its amplitude decrease after another 10 seconds?

140811 A particle of mass ' $m$ ' is under an influence of a force $\overrightarrow{\mathbf{F}}=-\mathbf{k} \overrightarrow{\mathbf{x}}+\overrightarrow{\mathbf{F}}_{0}$. The particle when disturbed will oscillate

140807 A small block of mass $100 \mathrm{~g}$ is tied to a spring of spring constant $7.5 \mathrm{~N} / \mathrm{m}$ and length $20 \mathrm{~cm}$. the other end of spring is fixed at a particular point $A$. If the block moves in a circular path on a smooth horizontal surface with constant angular velocity $5 \mathrm{rad} / \mathrm{s}$ about point $A$, then tension in the spring is

140808 If the amplitude of a lightly damped oscillator decreases by $1.5 \%$ then the mechanical energy of the oscillator lost in each cycle is

140809 The amplitude of a damped oscillator varies with time as $A(t)=A_{0} \exp (-b t / 2 m)$ where $b=$ $70 \mathrm{~g} / \mathrm{s}$ and $\mathrm{m}=200 \mathrm{~g}$. How long does it take for the mechanical energy to drop to one - fourth of its initial value?
[Take $\ln 2=0.7]$

140810 The amplitude of a damped oscillator is known to decreases to 0.9 times its original magnitude in 5 seconds. Approximately, by how many times its original magnitude will its amplitude decrease after another 10 seconds?

140811 A particle of mass ' $m$ ' is under an influence of a force $\overrightarrow{\mathbf{F}}=-\mathbf{k} \overrightarrow{\mathbf{x}}+\overrightarrow{\mathbf{F}}_{0}$. The particle when disturbed will oscillate

140807 A small block of mass $100 \mathrm{~g}$ is tied to a spring of spring constant $7.5 \mathrm{~N} / \mathrm{m}$ and length $20 \mathrm{~cm}$. the other end of spring is fixed at a particular point $A$. If the block moves in a circular path on a smooth horizontal surface with constant angular velocity $5 \mathrm{rad} / \mathrm{s}$ about point $A$, then tension in the spring is

140808 If the amplitude of a lightly damped oscillator decreases by $1.5 \%$ then the mechanical energy of the oscillator lost in each cycle is

140809 The amplitude of a damped oscillator varies with time as $A(t)=A_{0} \exp (-b t / 2 m)$ where $b=$ $70 \mathrm{~g} / \mathrm{s}$ and $\mathrm{m}=200 \mathrm{~g}$. How long does it take for the mechanical energy to drop to one - fourth of its initial value?
[Take $\ln 2=0.7]$

140810 The amplitude of a damped oscillator is known to decreases to 0.9 times its original magnitude in 5 seconds. Approximately, by how many times its original magnitude will its amplitude decrease after another 10 seconds?

140811 A particle of mass ' $m$ ' is under an influence of a force $\overrightarrow{\mathbf{F}}=-\mathbf{k} \overrightarrow{\mathbf{x}}+\overrightarrow{\mathbf{F}}_{0}$. The particle when disturbed will oscillate

140807 A small block of mass $100 \mathrm{~g}$ is tied to a spring of spring constant $7.5 \mathrm{~N} / \mathrm{m}$ and length $20 \mathrm{~cm}$. the other end of spring is fixed at a particular point $A$. If the block moves in a circular path on a smooth horizontal surface with constant angular velocity $5 \mathrm{rad} / \mathrm{s}$ about point $A$, then tension in the spring is

140808 If the amplitude of a lightly damped oscillator decreases by $1.5 \%$ then the mechanical energy of the oscillator lost in each cycle is

140809 The amplitude of a damped oscillator varies with time as $A(t)=A_{0} \exp (-b t / 2 m)$ where $b=$ $70 \mathrm{~g} / \mathrm{s}$ and $\mathrm{m}=200 \mathrm{~g}$. How long does it take for the mechanical energy to drop to one - fourth of its initial value?
[Take $\ln 2=0.7]$

140810 The amplitude of a damped oscillator is known to decreases to 0.9 times its original magnitude in 5 seconds. Approximately, by how many times its original magnitude will its amplitude decrease after another 10 seconds?

140811 A particle of mass ' $m$ ' is under an influence of a force $\overrightarrow{\mathbf{F}}=-\mathbf{k} \overrightarrow{\mathbf{x}}+\overrightarrow{\mathbf{F}}_{0}$. The particle when disturbed will oscillate