Pendulum (Simple Pendulum and Compound Pendulum)
Oscillations

140564 A simple pendulum is taken at a place where its separation from the Earth's surface is equal to the radius of the Earth. Then the time period of small oscillations of the pendulum (with string length of 1.0 m ) is given by

1 1 s
2 2 s
3 4 s
4 0.5 s
Oscillations

140565 A pendulum clock gains 5 seconds per day at a temperature of $15^{\circ} \mathrm{C}$ and loses 10 seconds per day at a temperature $30^{\circ} \mathrm{C}$. At what temperature, the pendulum clock will neither gain nor lose time?

1 $18^{\circ} \mathrm{C}$
2 $20^{\circ} \mathrm{C}$
3 $22.5^{\circ} \mathrm{C}$
4 $25^{\circ} \mathrm{C}$
Oscillations

140566 A simple pendulum is suspended from the ceiling of a lift. When the lift is at rest its time period is $T$. With what acceleration should the lift be accelerated upwards in order to reduce its period to $T / 2$ ? ( $g$ is acceleration due to gravity).

1 $2 \mathrm{~g}$
2 $3 \mathrm{~g}$
3 $4 \mathrm{~g}$
4 $\mathrm{g}$
Oscillations

140567 A simple pendulum has a length $I$ and the mass of the bob is $\mathrm{m}$. The bob is given a charge $q$ coulomb. The pendulum is suspended between the vertical plates of a charged parallel plate capacitor. If $E$ is the electric field strength between the plates, the time period of the pendulum is given by :

1 $2 \pi \sqrt{\frac{l}{\mathrm{~g}}}$
2 $2 \pi \sqrt{\frac{l}{\sqrt{g+\frac{q E}{m}}}}$
3 $2 \pi \sqrt{\frac{l}{\sqrt{g-\frac{\mathrm{qE}}{\mathrm{m}}}}}$
4 $2 \pi \sqrt{\frac{l}{\sqrt{g^{2}+\left(\frac{q E}{m}\right)^{2}}}}$
Oscillations

140564 A simple pendulum is taken at a place where its separation from the Earth's surface is equal to the radius of the Earth. Then the time period of small oscillations of the pendulum (with string length of 1.0 m ) is given by

1 1 s
2 2 s
3 4 s
4 0.5 s
Oscillations

140565 A pendulum clock gains 5 seconds per day at a temperature of $15^{\circ} \mathrm{C}$ and loses 10 seconds per day at a temperature $30^{\circ} \mathrm{C}$. At what temperature, the pendulum clock will neither gain nor lose time?

1 $18^{\circ} \mathrm{C}$
2 $20^{\circ} \mathrm{C}$
3 $22.5^{\circ} \mathrm{C}$
4 $25^{\circ} \mathrm{C}$
Oscillations

140566 A simple pendulum is suspended from the ceiling of a lift. When the lift is at rest its time period is $T$. With what acceleration should the lift be accelerated upwards in order to reduce its period to $T / 2$ ? ( $g$ is acceleration due to gravity).

1 $2 \mathrm{~g}$
2 $3 \mathrm{~g}$
3 $4 \mathrm{~g}$
4 $\mathrm{g}$
Oscillations

140567 A simple pendulum has a length $I$ and the mass of the bob is $\mathrm{m}$. The bob is given a charge $q$ coulomb. The pendulum is suspended between the vertical plates of a charged parallel plate capacitor. If $E$ is the electric field strength between the plates, the time period of the pendulum is given by :

1 $2 \pi \sqrt{\frac{l}{\mathrm{~g}}}$
2 $2 \pi \sqrt{\frac{l}{\sqrt{g+\frac{q E}{m}}}}$
3 $2 \pi \sqrt{\frac{l}{\sqrt{g-\frac{\mathrm{qE}}{\mathrm{m}}}}}$
4 $2 \pi \sqrt{\frac{l}{\sqrt{g^{2}+\left(\frac{q E}{m}\right)^{2}}}}$
Oscillations

140564 A simple pendulum is taken at a place where its separation from the Earth's surface is equal to the radius of the Earth. Then the time period of small oscillations of the pendulum (with string length of 1.0 m ) is given by

1 1 s
2 2 s
3 4 s
4 0.5 s
Oscillations

140565 A pendulum clock gains 5 seconds per day at a temperature of $15^{\circ} \mathrm{C}$ and loses 10 seconds per day at a temperature $30^{\circ} \mathrm{C}$. At what temperature, the pendulum clock will neither gain nor lose time?

1 $18^{\circ} \mathrm{C}$
2 $20^{\circ} \mathrm{C}$
3 $22.5^{\circ} \mathrm{C}$
4 $25^{\circ} \mathrm{C}$
Oscillations

140566 A simple pendulum is suspended from the ceiling of a lift. When the lift is at rest its time period is $T$. With what acceleration should the lift be accelerated upwards in order to reduce its period to $T / 2$ ? ( $g$ is acceleration due to gravity).

1 $2 \mathrm{~g}$
2 $3 \mathrm{~g}$
3 $4 \mathrm{~g}$
4 $\mathrm{g}$
Oscillations

140567 A simple pendulum has a length $I$ and the mass of the bob is $\mathrm{m}$. The bob is given a charge $q$ coulomb. The pendulum is suspended between the vertical plates of a charged parallel plate capacitor. If $E$ is the electric field strength between the plates, the time period of the pendulum is given by :

1 $2 \pi \sqrt{\frac{l}{\mathrm{~g}}}$
2 $2 \pi \sqrt{\frac{l}{\sqrt{g+\frac{q E}{m}}}}$
3 $2 \pi \sqrt{\frac{l}{\sqrt{g-\frac{\mathrm{qE}}{\mathrm{m}}}}}$
4 $2 \pi \sqrt{\frac{l}{\sqrt{g^{2}+\left(\frac{q E}{m}\right)^{2}}}}$
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
Oscillations

140564 A simple pendulum is taken at a place where its separation from the Earth's surface is equal to the radius of the Earth. Then the time period of small oscillations of the pendulum (with string length of 1.0 m ) is given by

1 1 s
2 2 s
3 4 s
4 0.5 s
Oscillations

140565 A pendulum clock gains 5 seconds per day at a temperature of $15^{\circ} \mathrm{C}$ and loses 10 seconds per day at a temperature $30^{\circ} \mathrm{C}$. At what temperature, the pendulum clock will neither gain nor lose time?

1 $18^{\circ} \mathrm{C}$
2 $20^{\circ} \mathrm{C}$
3 $22.5^{\circ} \mathrm{C}$
4 $25^{\circ} \mathrm{C}$
Oscillations

140566 A simple pendulum is suspended from the ceiling of a lift. When the lift is at rest its time period is $T$. With what acceleration should the lift be accelerated upwards in order to reduce its period to $T / 2$ ? ( $g$ is acceleration due to gravity).

1 $2 \mathrm{~g}$
2 $3 \mathrm{~g}$
3 $4 \mathrm{~g}$
4 $\mathrm{g}$
Oscillations

140567 A simple pendulum has a length $I$ and the mass of the bob is $\mathrm{m}$. The bob is given a charge $q$ coulomb. The pendulum is suspended between the vertical plates of a charged parallel plate capacitor. If $E$ is the electric field strength between the plates, the time period of the pendulum is given by :

1 $2 \pi \sqrt{\frac{l}{\mathrm{~g}}}$
2 $2 \pi \sqrt{\frac{l}{\sqrt{g+\frac{q E}{m}}}}$
3 $2 \pi \sqrt{\frac{l}{\sqrt{g-\frac{\mathrm{qE}}{\mathrm{m}}}}}$
4 $2 \pi \sqrt{\frac{l}{\sqrt{g^{2}+\left(\frac{q E}{m}\right)^{2}}}}$