140409 A simple pendulum having bob of mass $m$ and length of string $L$ has time period of $T$. If the mass of the bob in doubled and the length of the string in halved, then the time period of this pendulum will be

140411 Assume there are two identical simple pendulum Clocks-1 is placed on the earth and Clock-2 is placed on a space station located at a height $h$ above the earth surface. Clock-1 and Clock-2 operate at time periods $4 s$ and $6 s$ respectively. Then the value of $h$ is -
(Consider radius of earth $R_{E}=6400 \mathrm{~km}$ and $g$ on earth $10 \mathrm{~m} / \mathrm{s}^{2}$ )

140413 A simple pendulum of length $1 \mathrm{~m}$ and having a bob of mass $100 \mathrm{~g}$ is suspended in a car. moving on a circular track of radius $100 \mathrm{~m}$ with uniform speed $10 \mathrm{~m} / \mathrm{s}$ If the pendulum makes small oscillation in a radial direction about its equilibrium position, then its time period can be given by $T=2 \pi / \alpha^{1 / 4}$ The value of $\alpha$ is
[Take $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}$ ]

140414 The time periods of a given simple pendulum on the surface of earth $T_{1}$. In international space station $T_{2}$ and on the surface of the moon $T_{3}$ are related as

140415 The time period of a pendulum in a stationary lift is ' $T$ '. If the lift moves upwards with acceleration $\frac{g}{6}$, the time period of the pendulum becomes

140409 A simple pendulum having bob of mass $m$ and length of string $L$ has time period of $T$. If the mass of the bob in doubled and the length of the string in halved, then the time period of this pendulum will be

140411 Assume there are two identical simple pendulum Clocks-1 is placed on the earth and Clock-2 is placed on a space station located at a height $h$ above the earth surface. Clock-1 and Clock-2 operate at time periods $4 s$ and $6 s$ respectively. Then the value of $h$ is -
(Consider radius of earth $R_{E}=6400 \mathrm{~km}$ and $g$ on earth $10 \mathrm{~m} / \mathrm{s}^{2}$ )

140413 A simple pendulum of length $1 \mathrm{~m}$ and having a bob of mass $100 \mathrm{~g}$ is suspended in a car. moving on a circular track of radius $100 \mathrm{~m}$ with uniform speed $10 \mathrm{~m} / \mathrm{s}$ If the pendulum makes small oscillation in a radial direction about its equilibrium position, then its time period can be given by $T=2 \pi / \alpha^{1 / 4}$ The value of $\alpha$ is
[Take $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}$ ]

140414 The time periods of a given simple pendulum on the surface of earth $T_{1}$. In international space station $T_{2}$ and on the surface of the moon $T_{3}$ are related as

140415 The time period of a pendulum in a stationary lift is ' $T$ '. If the lift moves upwards with acceleration $\frac{g}{6}$, the time period of the pendulum becomes

140409 A simple pendulum having bob of mass $m$ and length of string $L$ has time period of $T$. If the mass of the bob in doubled and the length of the string in halved, then the time period of this pendulum will be

140411 Assume there are two identical simple pendulum Clocks-1 is placed on the earth and Clock-2 is placed on a space station located at a height $h$ above the earth surface. Clock-1 and Clock-2 operate at time periods $4 s$ and $6 s$ respectively. Then the value of $h$ is -
(Consider radius of earth $R_{E}=6400 \mathrm{~km}$ and $g$ on earth $10 \mathrm{~m} / \mathrm{s}^{2}$ )

140413 A simple pendulum of length $1 \mathrm{~m}$ and having a bob of mass $100 \mathrm{~g}$ is suspended in a car. moving on a circular track of radius $100 \mathrm{~m}$ with uniform speed $10 \mathrm{~m} / \mathrm{s}$ If the pendulum makes small oscillation in a radial direction about its equilibrium position, then its time period can be given by $T=2 \pi / \alpha^{1 / 4}$ The value of $\alpha$ is
[Take $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}$ ]

140414 The time periods of a given simple pendulum on the surface of earth $T_{1}$. In international space station $T_{2}$ and on the surface of the moon $T_{3}$ are related as

140415 The time period of a pendulum in a stationary lift is ' $T$ '. If the lift moves upwards with acceleration $\frac{g}{6}$, the time period of the pendulum becomes

140409 A simple pendulum having bob of mass $m$ and length of string $L$ has time period of $T$. If the mass of the bob in doubled and the length of the string in halved, then the time period of this pendulum will be

140411 Assume there are two identical simple pendulum Clocks-1 is placed on the earth and Clock-2 is placed on a space station located at a height $h$ above the earth surface. Clock-1 and Clock-2 operate at time periods $4 s$ and $6 s$ respectively. Then the value of $h$ is -
(Consider radius of earth $R_{E}=6400 \mathrm{~km}$ and $g$ on earth $10 \mathrm{~m} / \mathrm{s}^{2}$ )

140413 A simple pendulum of length $1 \mathrm{~m}$ and having a bob of mass $100 \mathrm{~g}$ is suspended in a car. moving on a circular track of radius $100 \mathrm{~m}$ with uniform speed $10 \mathrm{~m} / \mathrm{s}$ If the pendulum makes small oscillation in a radial direction about its equilibrium position, then its time period can be given by $T=2 \pi / \alpha^{1 / 4}$ The value of $\alpha$ is
[Take $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}$ ]

140414 The time periods of a given simple pendulum on the surface of earth $T_{1}$. In international space station $T_{2}$ and on the surface of the moon $T_{3}$ are related as

140415 The time period of a pendulum in a stationary lift is ' $T$ '. If the lift moves upwards with acceleration $\frac{g}{6}$, the time period of the pendulum becomes

140409 A simple pendulum having bob of mass $m$ and length of string $L$ has time period of $T$. If the mass of the bob in doubled and the length of the string in halved, then the time period of this pendulum will be

140411 Assume there are two identical simple pendulum Clocks-1 is placed on the earth and Clock-2 is placed on a space station located at a height $h$ above the earth surface. Clock-1 and Clock-2 operate at time periods $4 s$ and $6 s$ respectively. Then the value of $h$ is -
(Consider radius of earth $R_{E}=6400 \mathrm{~km}$ and $g$ on earth $10 \mathrm{~m} / \mathrm{s}^{2}$ )

140413 A simple pendulum of length $1 \mathrm{~m}$ and having a bob of mass $100 \mathrm{~g}$ is suspended in a car. moving on a circular track of radius $100 \mathrm{~m}$ with uniform speed $10 \mathrm{~m} / \mathrm{s}$ If the pendulum makes small oscillation in a radial direction about its equilibrium position, then its time period can be given by $T=2 \pi / \alpha^{1 / 4}$ The value of $\alpha$ is
[Take $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}$ ]

140414 The time periods of a given simple pendulum on the surface of earth $T_{1}$. In international space station $T_{2}$ and on the surface of the moon $T_{3}$ are related as

140415 The time period of a pendulum in a stationary lift is ' $T$ '. If the lift moves upwards with acceleration $\frac{g}{6}$, the time period of the pendulum becomes