140360 A body of mass $1 \mathrm{~kg}$ is executing simple harmonic motion (SHM). Its displacement y(in cm) at time $t$ is given by $y=$ $\left[6 \sin \left(100 t+\frac{\pi}{4}\right)\right] \mathrm{cm}$. Its maximum kinetic energy is

140361 A body performing simple harmonic motion has potential energy ' $P_{1}$ ' at displacement ' $x_{1}$ '. Its potential energy is ' $P_{2}$ ' at displacement ' $x_{2}$ '. The potential energy ' $P$ ' at displacement $\left(\mathbf{x}_{1}+\mathbf{x}_{2}\right)$ is

140363 The kinetic energy, $K$ of a body performing simple harmonic motion varies with time $t$, is indicated in graph

1

2

3

4

140364 The ratio of kinetic energy to the potential energy of a particle executing S.H.M. at a distance equal to $(1 / 3) \mathrm{rd}$ of its amplitude is

140366 A particle of mass $0.1 \mathrm{~kg}$ is executing simple harmonic motion of amplitude $0.1 \mathrm{~m}$. When the particle passes through the mean position, its kinetic energy is $8 \times 10^{-3} \mathrm{~J}$. If the initial phase is $45^{\circ}$, the equation of its motion is (Assume, $x(t)$ as the position of the particle at time t.)

140360 A body of mass $1 \mathrm{~kg}$ is executing simple harmonic motion (SHM). Its displacement y(in cm) at time $t$ is given by $y=$ $\left[6 \sin \left(100 t+\frac{\pi}{4}\right)\right] \mathrm{cm}$. Its maximum kinetic energy is

140361 A body performing simple harmonic motion has potential energy ' $P_{1}$ ' at displacement ' $x_{1}$ '. Its potential energy is ' $P_{2}$ ' at displacement ' $x_{2}$ '. The potential energy ' $P$ ' at displacement $\left(\mathbf{x}_{1}+\mathbf{x}_{2}\right)$ is

140363 The kinetic energy, $K$ of a body performing simple harmonic motion varies with time $t$, is indicated in graph

1

2

3

4

140364 The ratio of kinetic energy to the potential energy of a particle executing S.H.M. at a distance equal to $(1 / 3) \mathrm{rd}$ of its amplitude is

140366 A particle of mass $0.1 \mathrm{~kg}$ is executing simple harmonic motion of amplitude $0.1 \mathrm{~m}$. When the particle passes through the mean position, its kinetic energy is $8 \times 10^{-3} \mathrm{~J}$. If the initial phase is $45^{\circ}$, the equation of its motion is (Assume, $x(t)$ as the position of the particle at time t.)

140360 A body of mass $1 \mathrm{~kg}$ is executing simple harmonic motion (SHM). Its displacement y(in cm) at time $t$ is given by $y=$ $\left[6 \sin \left(100 t+\frac{\pi}{4}\right)\right] \mathrm{cm}$. Its maximum kinetic energy is

140361 A body performing simple harmonic motion has potential energy ' $P_{1}$ ' at displacement ' $x_{1}$ '. Its potential energy is ' $P_{2}$ ' at displacement ' $x_{2}$ '. The potential energy ' $P$ ' at displacement $\left(\mathbf{x}_{1}+\mathbf{x}_{2}\right)$ is

140363 The kinetic energy, $K$ of a body performing simple harmonic motion varies with time $t$, is indicated in graph

1

2

3

4

140364 The ratio of kinetic energy to the potential energy of a particle executing S.H.M. at a distance equal to $(1 / 3) \mathrm{rd}$ of its amplitude is

140366 A particle of mass $0.1 \mathrm{~kg}$ is executing simple harmonic motion of amplitude $0.1 \mathrm{~m}$. When the particle passes through the mean position, its kinetic energy is $8 \times 10^{-3} \mathrm{~J}$. If the initial phase is $45^{\circ}$, the equation of its motion is (Assume, $x(t)$ as the position of the particle at time t.)

140360 A body of mass $1 \mathrm{~kg}$ is executing simple harmonic motion (SHM). Its displacement y(in cm) at time $t$ is given by $y=$ $\left[6 \sin \left(100 t+\frac{\pi}{4}\right)\right] \mathrm{cm}$. Its maximum kinetic energy is

140361 A body performing simple harmonic motion has potential energy ' $P_{1}$ ' at displacement ' $x_{1}$ '. Its potential energy is ' $P_{2}$ ' at displacement ' $x_{2}$ '. The potential energy ' $P$ ' at displacement $\left(\mathbf{x}_{1}+\mathbf{x}_{2}\right)$ is

140363 The kinetic energy, $K$ of a body performing simple harmonic motion varies with time $t$, is indicated in graph

1

2

3

4

140364 The ratio of kinetic energy to the potential energy of a particle executing S.H.M. at a distance equal to $(1 / 3) \mathrm{rd}$ of its amplitude is

140366 A particle of mass $0.1 \mathrm{~kg}$ is executing simple harmonic motion of amplitude $0.1 \mathrm{~m}$. When the particle passes through the mean position, its kinetic energy is $8 \times 10^{-3} \mathrm{~J}$. If the initial phase is $45^{\circ}$, the equation of its motion is (Assume, $x(t)$ as the position of the particle at time t.)

140360 A body of mass $1 \mathrm{~kg}$ is executing simple harmonic motion (SHM). Its displacement y(in cm) at time $t$ is given by $y=$ $\left[6 \sin \left(100 t+\frac{\pi}{4}\right)\right] \mathrm{cm}$. Its maximum kinetic energy is

140361 A body performing simple harmonic motion has potential energy ' $P_{1}$ ' at displacement ' $x_{1}$ '. Its potential energy is ' $P_{2}$ ' at displacement ' $x_{2}$ '. The potential energy ' $P$ ' at displacement $\left(\mathbf{x}_{1}+\mathbf{x}_{2}\right)$ is

140363 The kinetic energy, $K$ of a body performing simple harmonic motion varies with time $t$, is indicated in graph

1

2

3

4

140364 The ratio of kinetic energy to the potential energy of a particle executing S.H.M. at a distance equal to $(1 / 3) \mathrm{rd}$ of its amplitude is

140366 A particle of mass $0.1 \mathrm{~kg}$ is executing simple harmonic motion of amplitude $0.1 \mathrm{~m}$. When the particle passes through the mean position, its kinetic energy is $8 \times 10^{-3} \mathrm{~J}$. If the initial phase is $45^{\circ}$, the equation of its motion is (Assume, $x(t)$ as the position of the particle at time t.)