79894 If \(f(x)=\frac{\left(e^{2 x}-1\right) \sin x^{0}}{x^{2}}, x \neq 0\) is continuous at \(x\) \(=0\), then \(\mathbf{f}(0)=\)

79895 If the function
\(\begin{array}{cc}f(x)=\frac{1-\sin 2 x+\cos 2 x}{1+\sin 2 x+\cos 2 x}, & \text { if } x \neq \frac{\pi}{2} \\ f(x)=k, & \text { if } x=\frac{\pi}{2}\end{array}\)
is continuous at \(\mathrm{x}=\frac{\boldsymbol{\pi}}{\boldsymbol{2}}\), then \(\mathrm{k}=\)

79896 If \(\begin{aligned} f(x) & =\frac{(81)^x-9^x}{(k)^x-1}, \text { if } x \neq 0 \\ & =2, \quad \text { if } x=0\end{aligned}\)
is continuous at \(x=0\), then the value of \(k\) is

79897 If the function
\(\begin{aligned} f(x) & =\frac{\log 10+\log (0.1+2 x)}{2 x}, \text { if } x \neq 0 \\ & =k . \quad \text { if } x=0\end{aligned}\)
is continuous at \(x=0\), then \(k+2=\)

79898 If \(f(x)=\frac{\sqrt{2}-\sqrt{1+\sin x}}{\cos ^{2} x}, x \neq \frac{\pi}{2}\) is continuous at \(\mathrm{x}=\frac{\pi}{2}\), then \(\mathrm{f}\left(\frac{\pi}{2}\right)=\)

79894 If \(f(x)=\frac{\left(e^{2 x}-1\right) \sin x^{0}}{x^{2}}, x \neq 0\) is continuous at \(x\) \(=0\), then \(\mathbf{f}(0)=\)

79895 If the function
\(\begin{array}{cc}f(x)=\frac{1-\sin 2 x+\cos 2 x}{1+\sin 2 x+\cos 2 x}, & \text { if } x \neq \frac{\pi}{2} \\ f(x)=k, & \text { if } x=\frac{\pi}{2}\end{array}\)
is continuous at \(\mathrm{x}=\frac{\boldsymbol{\pi}}{\boldsymbol{2}}\), then \(\mathrm{k}=\)

79896 If \(\begin{aligned} f(x) & =\frac{(81)^x-9^x}{(k)^x-1}, \text { if } x \neq 0 \\ & =2, \quad \text { if } x=0\end{aligned}\)
is continuous at \(x=0\), then the value of \(k\) is

79897 If the function
\(\begin{aligned} f(x) & =\frac{\log 10+\log (0.1+2 x)}{2 x}, \text { if } x \neq 0 \\ & =k . \quad \text { if } x=0\end{aligned}\)
is continuous at \(x=0\), then \(k+2=\)

79898 If \(f(x)=\frac{\sqrt{2}-\sqrt{1+\sin x}}{\cos ^{2} x}, x \neq \frac{\pi}{2}\) is continuous at \(\mathrm{x}=\frac{\pi}{2}\), then \(\mathrm{f}\left(\frac{\pi}{2}\right)=\)

79894 If \(f(x)=\frac{\left(e^{2 x}-1\right) \sin x^{0}}{x^{2}}, x \neq 0\) is continuous at \(x\) \(=0\), then \(\mathbf{f}(0)=\)

79895 If the function
\(\begin{array}{cc}f(x)=\frac{1-\sin 2 x+\cos 2 x}{1+\sin 2 x+\cos 2 x}, & \text { if } x \neq \frac{\pi}{2} \\ f(x)=k, & \text { if } x=\frac{\pi}{2}\end{array}\)
is continuous at \(\mathrm{x}=\frac{\boldsymbol{\pi}}{\boldsymbol{2}}\), then \(\mathrm{k}=\)

79896 If \(\begin{aligned} f(x) & =\frac{(81)^x-9^x}{(k)^x-1}, \text { if } x \neq 0 \\ & =2, \quad \text { if } x=0\end{aligned}\)
is continuous at \(x=0\), then the value of \(k\) is

79897 If the function
\(\begin{aligned} f(x) & =\frac{\log 10+\log (0.1+2 x)}{2 x}, \text { if } x \neq 0 \\ & =k . \quad \text { if } x=0\end{aligned}\)
is continuous at \(x=0\), then \(k+2=\)

79898 If \(f(x)=\frac{\sqrt{2}-\sqrt{1+\sin x}}{\cos ^{2} x}, x \neq \frac{\pi}{2}\) is continuous at \(\mathrm{x}=\frac{\pi}{2}\), then \(\mathrm{f}\left(\frac{\pi}{2}\right)=\)

79894 If \(f(x)=\frac{\left(e^{2 x}-1\right) \sin x^{0}}{x^{2}}, x \neq 0\) is continuous at \(x\) \(=0\), then \(\mathbf{f}(0)=\)

79895 If the function
\(\begin{array}{cc}f(x)=\frac{1-\sin 2 x+\cos 2 x}{1+\sin 2 x+\cos 2 x}, & \text { if } x \neq \frac{\pi}{2} \\ f(x)=k, & \text { if } x=\frac{\pi}{2}\end{array}\)
is continuous at \(\mathrm{x}=\frac{\boldsymbol{\pi}}{\boldsymbol{2}}\), then \(\mathrm{k}=\)

79896 If \(\begin{aligned} f(x) & =\frac{(81)^x-9^x}{(k)^x-1}, \text { if } x \neq 0 \\ & =2, \quad \text { if } x=0\end{aligned}\)
is continuous at \(x=0\), then the value of \(k\) is

79897 If the function
\(\begin{aligned} f(x) & =\frac{\log 10+\log (0.1+2 x)}{2 x}, \text { if } x \neq 0 \\ & =k . \quad \text { if } x=0\end{aligned}\)
is continuous at \(x=0\), then \(k+2=\)

79898 If \(f(x)=\frac{\sqrt{2}-\sqrt{1+\sin x}}{\cos ^{2} x}, x \neq \frac{\pi}{2}\) is continuous at \(\mathrm{x}=\frac{\pi}{2}\), then \(\mathrm{f}\left(\frac{\pi}{2}\right)=\)

79894 If \(f(x)=\frac{\left(e^{2 x}-1\right) \sin x^{0}}{x^{2}}, x \neq 0\) is continuous at \(x\) \(=0\), then \(\mathbf{f}(0)=\)

79895 If the function
\(\begin{array}{cc}f(x)=\frac{1-\sin 2 x+\cos 2 x}{1+\sin 2 x+\cos 2 x}, & \text { if } x \neq \frac{\pi}{2} \\ f(x)=k, & \text { if } x=\frac{\pi}{2}\end{array}\)
is continuous at \(\mathrm{x}=\frac{\boldsymbol{\pi}}{\boldsymbol{2}}\), then \(\mathrm{k}=\)

79896 If \(\begin{aligned} f(x) & =\frac{(81)^x-9^x}{(k)^x-1}, \text { if } x \neq 0 \\ & =2, \quad \text { if } x=0\end{aligned}\)
is continuous at \(x=0\), then the value of \(k\) is

79897 If the function
\(\begin{aligned} f(x) & =\frac{\log 10+\log (0.1+2 x)}{2 x}, \text { if } x \neq 0 \\ & =k . \quad \text { if } x=0\end{aligned}\)
is continuous at \(x=0\), then \(k+2=\)

79898 If \(f(x)=\frac{\sqrt{2}-\sqrt{1+\sin x}}{\cos ^{2} x}, x \neq \frac{\pi}{2}\) is continuous at \(\mathrm{x}=\frac{\pi}{2}\), then \(\mathrm{f}\left(\frac{\pi}{2}\right)=\)