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ALDEHYDES, KETONES AND CARBOXYLIC ACID

28286 Which gas will be evolved out when $[C H_{3} C H_{2} N H_{2} + (C H_{3})_{2} C H N H_{2}]$ is treated with sodium nitrite and $H C l$ :

1 Chlorine

2 Ammonia

3 Nitrogen

4

N O_{2}

Explanation:

Primary amine reacts with nitrous acid (obtained from sodium nitrite and $H C l$ ) to form primary alcohol along with evolution of nitrogen gas.
$C H_{3} C H_{2} N H_{2} + {(C H_{3})}_{2} C H N H_{2} + H N O_{2} \underset{273 - 278 K}{\overset{N a N O_{2} + H C l}{⟶}} C H_{3} C H_{2} O H + {(C H_{3})}_{2} C H O H + H_{2} O + N_{2} ↑$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28287 Boiling Ethylamine on reaction with acidified $K M n O_{4}$ gives :

1 Acetaldehyde

2 Ethanoic Acid

3 Ethanol

4 Acetamide

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28288 Methyl amine on reaction with chlorine in the presence of $N a O H$ gives :

1 Chloroform

2 Methyl chloride

3

N -

Methyl chloramine

4 Chloramine

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28289 Highest value of $p K_{b}$ will be of :

1

N H_{3}

2

(C H_{3})_{2} N H

3

(C H_{3})_{3} N

4

C H_{3} N H_{2}

Explanation:

when a compound attech with alkyl compound so the $p K b$ value is less so amine $N H_{3}$ have highest value of $P k b$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28290 Lowest boiling point will be of the compound :

1 Ethylamine

2 Ethylmethylamine

3

1 -

Propaneamine

4

N, N -

Dimethylmethaneamine

Explanation:

$N, N -$ dimethylmethanamine will have the lowest boiling points as it cannot form hydrogen bonds. Other amines can form hydrogen bonds and have higher boiling points.

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28286 Which gas will be evolved out when $[C H_{3} C H_{2} N H_{2} + (C H_{3})_{2} C H N H_{2}]$ is treated with sodium nitrite and $H C l$ :

1 Chlorine

2 Ammonia

3 Nitrogen

4

N O_{2}

Explanation:

Primary amine reacts with nitrous acid (obtained from sodium nitrite and $H C l$ ) to form primary alcohol along with evolution of nitrogen gas.
$C H_{3} C H_{2} N H_{2} + {(C H_{3})}_{2} C H N H_{2} + H N O_{2} \underset{273 - 278 K}{\overset{N a N O_{2} + H C l}{⟶}} C H_{3} C H_{2} O H + {(C H_{3})}_{2} C H O H + H_{2} O + N_{2} ↑$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28287 Boiling Ethylamine on reaction with acidified $K M n O_{4}$ gives :

1 Acetaldehyde

2 Ethanoic Acid

3 Ethanol

4 Acetamide

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28288 Methyl amine on reaction with chlorine in the presence of $N a O H$ gives :

1 Chloroform

2 Methyl chloride

3

N -

Methyl chloramine

4 Chloramine

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28289 Highest value of $p K_{b}$ will be of :

1

N H_{3}

2

(C H_{3})_{2} N H

3

(C H_{3})_{3} N

4

C H_{3} N H_{2}

Explanation:

when a compound attech with alkyl compound so the $p K b$ value is less so amine $N H_{3}$ have highest value of $P k b$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28290 Lowest boiling point will be of the compound :

1 Ethylamine

2 Ethylmethylamine

3

1 -

Propaneamine

4

N, N -

Dimethylmethaneamine

Explanation:

$N, N -$ dimethylmethanamine will have the lowest boiling points as it cannot form hydrogen bonds. Other amines can form hydrogen bonds and have higher boiling points.

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28286 Which gas will be evolved out when $[C H_{3} C H_{2} N H_{2} + (C H_{3})_{2} C H N H_{2}]$ is treated with sodium nitrite and $H C l$ :

1 Chlorine

2 Ammonia

3 Nitrogen

4

N O_{2}

Explanation:

Primary amine reacts with nitrous acid (obtained from sodium nitrite and $H C l$ ) to form primary alcohol along with evolution of nitrogen gas.
$C H_{3} C H_{2} N H_{2} + {(C H_{3})}_{2} C H N H_{2} + H N O_{2} \underset{273 - 278 K}{\overset{N a N O_{2} + H C l}{⟶}} C H_{3} C H_{2} O H + {(C H_{3})}_{2} C H O H + H_{2} O + N_{2} ↑$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28287 Boiling Ethylamine on reaction with acidified $K M n O_{4}$ gives :

1 Acetaldehyde

2 Ethanoic Acid

3 Ethanol

4 Acetamide

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28288 Methyl amine on reaction with chlorine in the presence of $N a O H$ gives :

1 Chloroform

2 Methyl chloride

3

N -

Methyl chloramine

4 Chloramine

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28289 Highest value of $p K_{b}$ will be of :

1

N H_{3}

2

(C H_{3})_{2} N H

3

(C H_{3})_{3} N

4

C H_{3} N H_{2}

Explanation:

when a compound attech with alkyl compound so the $p K b$ value is less so amine $N H_{3}$ have highest value of $P k b$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28290 Lowest boiling point will be of the compound :

1 Ethylamine

2 Ethylmethylamine

3

1 -

Propaneamine

4

N, N -

Dimethylmethaneamine

Explanation:

$N, N -$ dimethylmethanamine will have the lowest boiling points as it cannot form hydrogen bonds. Other amines can form hydrogen bonds and have higher boiling points.

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28286 Which gas will be evolved out when $[C H_{3} C H_{2} N H_{2} + (C H_{3})_{2} C H N H_{2}]$ is treated with sodium nitrite and $H C l$ :

1 Chlorine

2 Ammonia

3 Nitrogen

4

N O_{2}

Explanation:

Primary amine reacts with nitrous acid (obtained from sodium nitrite and $H C l$ ) to form primary alcohol along with evolution of nitrogen gas.
$C H_{3} C H_{2} N H_{2} + {(C H_{3})}_{2} C H N H_{2} + H N O_{2} \underset{273 - 278 K}{\overset{N a N O_{2} + H C l}{⟶}} C H_{3} C H_{2} O H + {(C H_{3})}_{2} C H O H + H_{2} O + N_{2} ↑$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28287 Boiling Ethylamine on reaction with acidified $K M n O_{4}$ gives :

1 Acetaldehyde

2 Ethanoic Acid

3 Ethanol

4 Acetamide

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28288 Methyl amine on reaction with chlorine in the presence of $N a O H$ gives :

1 Chloroform

2 Methyl chloride

3

N -

Methyl chloramine

4 Chloramine

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28289 Highest value of $p K_{b}$ will be of :

1

N H_{3}

2

(C H_{3})_{2} N H

3

(C H_{3})_{3} N

4

C H_{3} N H_{2}

Explanation:

when a compound attech with alkyl compound so the $p K b$ value is less so amine $N H_{3}$ have highest value of $P k b$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28290 Lowest boiling point will be of the compound :

1 Ethylamine

2 Ethylmethylamine

3

1 -

Propaneamine

4

N, N -

Dimethylmethaneamine

Explanation:

$N, N -$ dimethylmethanamine will have the lowest boiling points as it cannot form hydrogen bonds. Other amines can form hydrogen bonds and have higher boiling points.

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28286 Which gas will be evolved out when $[C H_{3} C H_{2} N H_{2} + (C H_{3})_{2} C H N H_{2}]$ is treated with sodium nitrite and $H C l$ :

1 Chlorine

2 Ammonia

3 Nitrogen

4

N O_{2}

Explanation:

Primary amine reacts with nitrous acid (obtained from sodium nitrite and $H C l$ ) to form primary alcohol along with evolution of nitrogen gas.
$C H_{3} C H_{2} N H_{2} + {(C H_{3})}_{2} C H N H_{2} + H N O_{2} \underset{273 - 278 K}{\overset{N a N O_{2} + H C l}{⟶}} C H_{3} C H_{2} O H + {(C H_{3})}_{2} C H O H + H_{2} O + N_{2} ↑$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28287 Boiling Ethylamine on reaction with acidified $K M n O_{4}$ gives :

1 Acetaldehyde

2 Ethanoic Acid

3 Ethanol

4 Acetamide

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28288 Methyl amine on reaction with chlorine in the presence of $N a O H$ gives :

1 Chloroform

2 Methyl chloride

3

N -

Methyl chloramine

4 Chloramine

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28289 Highest value of $p K_{b}$ will be of :

1

N H_{3}

2

(C H_{3})_{2} N H

3

(C H_{3})_{3} N

4

C H_{3} N H_{2}

Explanation:

when a compound attech with alkyl compound so the $p K b$ value is less so amine $N H_{3}$ have highest value of $P k b$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28290 Lowest boiling point will be of the compound :

1 Ethylamine

2 Ethylmethylamine

3

1 -

Propaneamine

4

N, N -

Dimethylmethaneamine

Explanation:

$N, N -$ dimethylmethanamine will have the lowest boiling points as it cannot form hydrogen bonds. Other amines can form hydrogen bonds and have higher boiling points.

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