NEET Test Series from KOTA - 10 Papers In MS WORD
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ALDEHYDES, KETONES AND CARBOXYLIC ACID
28260
Which one of the following on heating gives unsaturated acid :
1 \(\alpha -\) Hydroxy acid
2 \(\beta -\) Hydroxy acid
3 \(\gamma -\) Hyroxy acid
4 \(\delta -\) Hydroxy acid
Explanation:
Hydroxy acid on heating loses a molecule of water to give unsaturated acid. The carbon-carbon double bond is in conjugation with carbon oxygen double bond. \(RCH ( OH ) CH _2 COOH \stackrel{\text { heat }}{\longrightarrow} RCH = CHCOOH + H _2 O\)
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28261
Which will form lactone on treatment with \(NaOH\) ?
1 \(\alpha -\) Bromo acid
2 \(\beta -\) Bromo acid
3 \(\beta -\) Hydroxy acid
4 \(\delta -\) Bromo acid
Explanation:
Bromo acid will form lactone on treatment with \(NaOH\). The lactone formed will contain a six member ring which is stable.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28262
Which one of the following will go decarboxylation on heating?
1 Succinic acid
2 Phthalic acid
3 Malonic acid
4 Adipic acid
Explanation:
Keto acids or \(1,3-\) dicarboxylic acids, on heating undergo decarboxylation. Malonic acid is a \(1,3-\) dicarboxylic acid. Hence, it will undergo decarboxylation on heating.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28263
In the given reaction :\(CH_3-COOH\) \(\mathop {\xrightarrow{{(i)\,B{r_2}/P}}}\limits_{(ii)\,NaCN\,(iii)\,{H_2}O/{H^ \oplus }/\Delta } \,[X]\)\([X]\) will be :
28260
Which one of the following on heating gives unsaturated acid :
1 \(\alpha -\) Hydroxy acid
2 \(\beta -\) Hydroxy acid
3 \(\gamma -\) Hyroxy acid
4 \(\delta -\) Hydroxy acid
Explanation:
Hydroxy acid on heating loses a molecule of water to give unsaturated acid. The carbon-carbon double bond is in conjugation with carbon oxygen double bond. \(RCH ( OH ) CH _2 COOH \stackrel{\text { heat }}{\longrightarrow} RCH = CHCOOH + H _2 O\)
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28261
Which will form lactone on treatment with \(NaOH\) ?
1 \(\alpha -\) Bromo acid
2 \(\beta -\) Bromo acid
3 \(\beta -\) Hydroxy acid
4 \(\delta -\) Bromo acid
Explanation:
Bromo acid will form lactone on treatment with \(NaOH\). The lactone formed will contain a six member ring which is stable.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28262
Which one of the following will go decarboxylation on heating?
1 Succinic acid
2 Phthalic acid
3 Malonic acid
4 Adipic acid
Explanation:
Keto acids or \(1,3-\) dicarboxylic acids, on heating undergo decarboxylation. Malonic acid is a \(1,3-\) dicarboxylic acid. Hence, it will undergo decarboxylation on heating.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28263
In the given reaction :\(CH_3-COOH\) \(\mathop {\xrightarrow{{(i)\,B{r_2}/P}}}\limits_{(ii)\,NaCN\,(iii)\,{H_2}O/{H^ \oplus }/\Delta } \,[X]\)\([X]\) will be :
28260
Which one of the following on heating gives unsaturated acid :
1 \(\alpha -\) Hydroxy acid
2 \(\beta -\) Hydroxy acid
3 \(\gamma -\) Hyroxy acid
4 \(\delta -\) Hydroxy acid
Explanation:
Hydroxy acid on heating loses a molecule of water to give unsaturated acid. The carbon-carbon double bond is in conjugation with carbon oxygen double bond. \(RCH ( OH ) CH _2 COOH \stackrel{\text { heat }}{\longrightarrow} RCH = CHCOOH + H _2 O\)
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28261
Which will form lactone on treatment with \(NaOH\) ?
1 \(\alpha -\) Bromo acid
2 \(\beta -\) Bromo acid
3 \(\beta -\) Hydroxy acid
4 \(\delta -\) Bromo acid
Explanation:
Bromo acid will form lactone on treatment with \(NaOH\). The lactone formed will contain a six member ring which is stable.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28262
Which one of the following will go decarboxylation on heating?
1 Succinic acid
2 Phthalic acid
3 Malonic acid
4 Adipic acid
Explanation:
Keto acids or \(1,3-\) dicarboxylic acids, on heating undergo decarboxylation. Malonic acid is a \(1,3-\) dicarboxylic acid. Hence, it will undergo decarboxylation on heating.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28263
In the given reaction :\(CH_3-COOH\) \(\mathop {\xrightarrow{{(i)\,B{r_2}/P}}}\limits_{(ii)\,NaCN\,(iii)\,{H_2}O/{H^ \oplus }/\Delta } \,[X]\)\([X]\) will be :
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28260
Which one of the following on heating gives unsaturated acid :
1 \(\alpha -\) Hydroxy acid
2 \(\beta -\) Hydroxy acid
3 \(\gamma -\) Hyroxy acid
4 \(\delta -\) Hydroxy acid
Explanation:
Hydroxy acid on heating loses a molecule of water to give unsaturated acid. The carbon-carbon double bond is in conjugation with carbon oxygen double bond. \(RCH ( OH ) CH _2 COOH \stackrel{\text { heat }}{\longrightarrow} RCH = CHCOOH + H _2 O\)
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28261
Which will form lactone on treatment with \(NaOH\) ?
1 \(\alpha -\) Bromo acid
2 \(\beta -\) Bromo acid
3 \(\beta -\) Hydroxy acid
4 \(\delta -\) Bromo acid
Explanation:
Bromo acid will form lactone on treatment with \(NaOH\). The lactone formed will contain a six member ring which is stable.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28262
Which one of the following will go decarboxylation on heating?
1 Succinic acid
2 Phthalic acid
3 Malonic acid
4 Adipic acid
Explanation:
Keto acids or \(1,3-\) dicarboxylic acids, on heating undergo decarboxylation. Malonic acid is a \(1,3-\) dicarboxylic acid. Hence, it will undergo decarboxylation on heating.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28263
In the given reaction :\(CH_3-COOH\) \(\mathop {\xrightarrow{{(i)\,B{r_2}/P}}}\limits_{(ii)\,NaCN\,(iii)\,{H_2}O/{H^ \oplus }/\Delta } \,[X]\)\([X]\) will be :
