28255 Sodium bicarbonate reacts with salicylic acid to form :

1 \(C_6H_5ONa\)

2

3

4

28256 In the given reaction :\([X]\) will be :

28257 Arrange these esters in decreasing order of case of esterfication with \(C{H_3}OH/{H^ \oplus }\) :\((I)\) $\begin{array}{*{20}{c}}
  {C{H_3} - CH - COOH} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3}\,\,\,\,\,\,\,} 
\end{array}$\((II)\)  $\begin{array}{*{20}{c}}
  {C{H_3} - CH - C{H_2} - COOH} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
\end{array}$\((III)\) $\begin{array}{*{20}{c}}
  \,\,{C{H_3}} \\ 
  {|\,\,\,\,\,\,\,\,} \\ 
  {C{H_3} - C - COOH} \\ 
  {|\,\,\,\,\,\,} \\ 
  \,\,{C{H_3}\,} 
\end{array}$\((IV)\) \((CH_3-CH_2)_3C-COOH\)

28258 Arrange following compounds in decreasing order of reactivity for hydrolysis reaction :

28259 In the given reaction sequence :\(CH_3-CH_2-OH\) \(\mathop {\xrightarrow{{(i)\,KMn{O_4}/\mathop O\limits^\Theta  H/\Delta }}}\limits_{(ii)\,{H^ \oplus }} (A)\mathop {\xrightarrow{{(i)\,SOC{l_2}}}}\limits_{(ii)\,N{H_3}/\Delta } (B)\) \(\xrightarrow{{B{r_2}/KOH}}(C)\)\((C)\) will be :

28255 Sodium bicarbonate reacts with salicylic acid to form :

1 \(C_6H_5ONa\)

2

3

4

28256 In the given reaction :\([X]\) will be :

28257 Arrange these esters in decreasing order of case of esterfication with \(C{H_3}OH/{H^ \oplus }\) :\((I)\) $\begin{array}{*{20}{c}}
  {C{H_3} - CH - COOH} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3}\,\,\,\,\,\,\,} 
\end{array}$\((II)\)  $\begin{array}{*{20}{c}}
  {C{H_3} - CH - C{H_2} - COOH} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
\end{array}$\((III)\) $\begin{array}{*{20}{c}}
  \,\,{C{H_3}} \\ 
  {|\,\,\,\,\,\,\,\,} \\ 
  {C{H_3} - C - COOH} \\ 
  {|\,\,\,\,\,\,} \\ 
  \,\,{C{H_3}\,} 
\end{array}$\((IV)\) \((CH_3-CH_2)_3C-COOH\)

28258 Arrange following compounds in decreasing order of reactivity for hydrolysis reaction :

28259 In the given reaction sequence :\(CH_3-CH_2-OH\) \(\mathop {\xrightarrow{{(i)\,KMn{O_4}/\mathop O\limits^\Theta  H/\Delta }}}\limits_{(ii)\,{H^ \oplus }} (A)\mathop {\xrightarrow{{(i)\,SOC{l_2}}}}\limits_{(ii)\,N{H_3}/\Delta } (B)\) \(\xrightarrow{{B{r_2}/KOH}}(C)\)\((C)\) will be :

28255 Sodium bicarbonate reacts with salicylic acid to form :

1 \(C_6H_5ONa\)

2

3

4

28256 In the given reaction :\([X]\) will be :

28257 Arrange these esters in decreasing order of case of esterfication with \(C{H_3}OH/{H^ \oplus }\) :\((I)\) $\begin{array}{*{20}{c}}
  {C{H_3} - CH - COOH} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3}\,\,\,\,\,\,\,} 
\end{array}$\((II)\)  $\begin{array}{*{20}{c}}
  {C{H_3} - CH - C{H_2} - COOH} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
\end{array}$\((III)\) $\begin{array}{*{20}{c}}
  \,\,{C{H_3}} \\ 
  {|\,\,\,\,\,\,\,\,} \\ 
  {C{H_3} - C - COOH} \\ 
  {|\,\,\,\,\,\,} \\ 
  \,\,{C{H_3}\,} 
\end{array}$\((IV)\) \((CH_3-CH_2)_3C-COOH\)

28258 Arrange following compounds in decreasing order of reactivity for hydrolysis reaction :

28259 In the given reaction sequence :\(CH_3-CH_2-OH\) \(\mathop {\xrightarrow{{(i)\,KMn{O_4}/\mathop O\limits^\Theta  H/\Delta }}}\limits_{(ii)\,{H^ \oplus }} (A)\mathop {\xrightarrow{{(i)\,SOC{l_2}}}}\limits_{(ii)\,N{H_3}/\Delta } (B)\) \(\xrightarrow{{B{r_2}/KOH}}(C)\)\((C)\) will be :

28255 Sodium bicarbonate reacts with salicylic acid to form :

1 \(C_6H_5ONa\)

2

3

4

28256 In the given reaction :\([X]\) will be :

28257 Arrange these esters in decreasing order of case of esterfication with \(C{H_3}OH/{H^ \oplus }\) :\((I)\) $\begin{array}{*{20}{c}}
  {C{H_3} - CH - COOH} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3}\,\,\,\,\,\,\,} 
\end{array}$\((II)\)  $\begin{array}{*{20}{c}}
  {C{H_3} - CH - C{H_2} - COOH} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
\end{array}$\((III)\) $\begin{array}{*{20}{c}}
  \,\,{C{H_3}} \\ 
  {|\,\,\,\,\,\,\,\,} \\ 
  {C{H_3} - C - COOH} \\ 
  {|\,\,\,\,\,\,} \\ 
  \,\,{C{H_3}\,} 
\end{array}$\((IV)\) \((CH_3-CH_2)_3C-COOH\)

28258 Arrange following compounds in decreasing order of reactivity for hydrolysis reaction :

28259 In the given reaction sequence :\(CH_3-CH_2-OH\) \(\mathop {\xrightarrow{{(i)\,KMn{O_4}/\mathop O\limits^\Theta  H/\Delta }}}\limits_{(ii)\,{H^ \oplus }} (A)\mathop {\xrightarrow{{(i)\,SOC{l_2}}}}\limits_{(ii)\,N{H_3}/\Delta } (B)\) \(\xrightarrow{{B{r_2}/KOH}}(C)\)\((C)\) will be :

28255 Sodium bicarbonate reacts with salicylic acid to form :

1 \(C_6H_5ONa\)

2

3

4

28256 In the given reaction :\([X]\) will be :

28257 Arrange these esters in decreasing order of case of esterfication with \(C{H_3}OH/{H^ \oplus }\) :\((I)\) $\begin{array}{*{20}{c}}
  {C{H_3} - CH - COOH} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3}\,\,\,\,\,\,\,} 
\end{array}$\((II)\)  $\begin{array}{*{20}{c}}
  {C{H_3} - CH - C{H_2} - COOH} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
\end{array}$\((III)\) $\begin{array}{*{20}{c}}
  \,\,{C{H_3}} \\ 
  {|\,\,\,\,\,\,\,\,} \\ 
  {C{H_3} - C - COOH} \\ 
  {|\,\,\,\,\,\,} \\ 
  \,\,{C{H_3}\,} 
\end{array}$\((IV)\) \((CH_3-CH_2)_3C-COOH\)

28258 Arrange following compounds in decreasing order of reactivity for hydrolysis reaction :

28259 In the given reaction sequence :\(CH_3-CH_2-OH\) \(\mathop {\xrightarrow{{(i)\,KMn{O_4}/\mathop O\limits^\Theta  H/\Delta }}}\limits_{(ii)\,{H^ \oplus }} (A)\mathop {\xrightarrow{{(i)\,SOC{l_2}}}}\limits_{(ii)\,N{H_3}/\Delta } (B)\) \(\xrightarrow{{B{r_2}/KOH}}(C)\)\((C)\) will be :