ALDEHYDES, KETONES AND CARBOXYLIC ACID
28173
In the reaction,\(C{H_3}COOH\xrightarrow{{LiAl{H_4}}}A\xrightarrow{{PC{l_5}}} \) \(B\xrightarrow{{Alc.\,KOH}}C,\)the product \(C\) is :
1 Acetaldehyde
2 Acetylene
3 Ethylene
4 Acetyl chloride
Explanation:
$\begin{array}{*{20}{c}}
{\,\,\,O} \\
{\,\,\,||} \\
{C{H_3} - C - OH}
\end{array}$ $\xrightarrow[{{\text{ Reduction }}}]{{LiAl{H_4}}}{\text{C}}{{\text{H}}_3} - {\text{C}}{{\text{H}}_2} - {\text{OH}}$ $\xrightarrow{{{\text{PC}}{{\text{l}}_5}}}{\text{C}}{{\text{H}}_3} - {\text{C}}{{\text{H}}_2} - {\text{Cl}}$ $\xrightarrow[{{\text{ Dehydrohalogenation }}}]{{{\text{Alc}}.{\text{KOH}}}}$ $\mathrm{CH}_{2}=\mathrm{CH}_{2}$ (Ethylene)
