28136
An organic compound of molecular formula \({C_4}{H_{10}}O\) does not react with sodium. With excess of \(HI,\) it gives only one type of alkyl halide. The compound is
1 Ethoxyethane
2 \(2-\)Methoxypropane
3 \(1-\)Methoxypropane
4 \(1-\)Butanol
Explanation:
(a) Since a single alkyl halide is formed on treatment with HI, it must be a symmetrical ether i.e., ethoxyethane. \({C_2}{H_5}O{C_2}{H_5} + 2HI \to 2{C_2}{H_5}I + {H_2}O\)
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28137
જ્યારે \(C{H_2} = CH - COOH\) is reduced with \(LiAl{H_4}\), the compound obtained will be
28138
In a set of the given reactions, acetic acid yielded a product C.Product C would be\(C{H_3}COOH + PC{l_5} \to A\mathop {\xrightarrow{{{C_6}{H_6}}}}\limits_{anh.\,AlC{l_3}} \) \(B\mathop {\xrightarrow{{{C_2}{H_5}MgBr}}}\limits_{ether} C\)
28136
An organic compound of molecular formula \({C_4}{H_{10}}O\) does not react with sodium. With excess of \(HI,\) it gives only one type of alkyl halide. The compound is
1 Ethoxyethane
2 \(2-\)Methoxypropane
3 \(1-\)Methoxypropane
4 \(1-\)Butanol
Explanation:
(a) Since a single alkyl halide is formed on treatment with HI, it must be a symmetrical ether i.e., ethoxyethane. \({C_2}{H_5}O{C_2}{H_5} + 2HI \to 2{C_2}{H_5}I + {H_2}O\)
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28137
જ્યારે \(C{H_2} = CH - COOH\) is reduced with \(LiAl{H_4}\), the compound obtained will be
28138
In a set of the given reactions, acetic acid yielded a product C.Product C would be\(C{H_3}COOH + PC{l_5} \to A\mathop {\xrightarrow{{{C_6}{H_6}}}}\limits_{anh.\,AlC{l_3}} \) \(B\mathop {\xrightarrow{{{C_2}{H_5}MgBr}}}\limits_{ether} C\)
28136
An organic compound of molecular formula \({C_4}{H_{10}}O\) does not react with sodium. With excess of \(HI,\) it gives only one type of alkyl halide. The compound is
1 Ethoxyethane
2 \(2-\)Methoxypropane
3 \(1-\)Methoxypropane
4 \(1-\)Butanol
Explanation:
(a) Since a single alkyl halide is formed on treatment with HI, it must be a symmetrical ether i.e., ethoxyethane. \({C_2}{H_5}O{C_2}{H_5} + 2HI \to 2{C_2}{H_5}I + {H_2}O\)
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28137
જ્યારે \(C{H_2} = CH - COOH\) is reduced with \(LiAl{H_4}\), the compound obtained will be
28138
In a set of the given reactions, acetic acid yielded a product C.Product C would be\(C{H_3}COOH + PC{l_5} \to A\mathop {\xrightarrow{{{C_6}{H_6}}}}\limits_{anh.\,AlC{l_3}} \) \(B\mathop {\xrightarrow{{{C_2}{H_5}MgBr}}}\limits_{ether} C\)
28136
An organic compound of molecular formula \({C_4}{H_{10}}O\) does not react with sodium. With excess of \(HI,\) it gives only one type of alkyl halide. The compound is
1 Ethoxyethane
2 \(2-\)Methoxypropane
3 \(1-\)Methoxypropane
4 \(1-\)Butanol
Explanation:
(a) Since a single alkyl halide is formed on treatment with HI, it must be a symmetrical ether i.e., ethoxyethane. \({C_2}{H_5}O{C_2}{H_5} + 2HI \to 2{C_2}{H_5}I + {H_2}O\)
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28137
જ્યારે \(C{H_2} = CH - COOH\) is reduced with \(LiAl{H_4}\), the compound obtained will be
28138
In a set of the given reactions, acetic acid yielded a product C.Product C would be\(C{H_3}COOH + PC{l_5} \to A\mathop {\xrightarrow{{{C_6}{H_6}}}}\limits_{anh.\,AlC{l_3}} \) \(B\mathop {\xrightarrow{{{C_2}{H_5}MgBr}}}\limits_{ether} C\)