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ALDEHYDES, KETONES AND CARBOXYLIC ACID

28136 An organic compound of molecular formula $C_{4} H_{10} O$ does not react with sodium. With excess of $H I,$ it gives only one type of alkyl halide. The compound is

1 Ethoxyethane

2

2 -

Methoxypropane

3

1 -

Methoxypropane

4

1 -

Butanol

Explanation:

(a) Since a single alkyl halide is formed on treatment with HI, it must be a symmetrical ether i.e., ethoxyethane.
$C_{2} H_{5} O C_{2} H_{5} + 2 H I \to 2 C_{2} H_{5} I + H_{2} O$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28137 જ્યારે $C H_{2} = C H - C O O H$ is reduced with $L i A l H_{4}$ , the compound obtained will be

1

C H_{3} - C H_{2} - C O O H

2

C H_{2} = C H - C H_{2} O H

3

C H_{3} - C H_{2} - C H_{2} O H

4

C H_{3} - C H_{2} - C H O

Explanation:

(b) $C H_{2} = C H - C O O H \overset{L i A l H_{4}}{\to}$ $C H_{2} = C H - C H_{2} O H + H_{2} O$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28138 In a set of the given reactions, acetic acid yielded a product C.Product C would be $C H_{3} C O O H + P C l_{5} \to A \underset{a n h . A l C l_{3}}{\overset{C_{6} H_{6}}{\to}}$ $B \underset{e t h e r}{\overset{C_{2} H_{5} M g B r}{\to}} C$

1

\begin{matrix} C_{2} H_{5} \\ | \\ C H_{3} - C (O H) C_{6} H_{5} \end{matrix}

2

C H_{3} C H (O H) C_{2} H_{5}

3

C H_{3} C O C_{6} H_{5}

4

C H_{3} C H (O H) C_{6} H_{5}

Explanation:

$C H_{3} C O O H + P C l_{5} \to C H_{3} C O C l \underset{anh . A l C l_{3}}{\overset{C_{6} H_{6}}{\to}}$ $C H_{3} C O C_{6} H_{5} \underset{Ether}{\overset{C_{2} H_{5} M g B r}{\to}}$ $\begin{matrix} C_{2} H_{5} \\ | \\ C H_{3} - C (O H) C_{6} H_{5} \end{matrix}$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28139 Carboxylic acids are more acidic than phenol and alcohol because of

1 Intermolecular hydrogen bonding

2 Formation of dimers

3 Highly acidic hydrogen

4 Resonance stabilization of their conjugate base

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28136 An organic compound of molecular formula $C_{4} H_{10} O$ does not react with sodium. With excess of $H I,$ it gives only one type of alkyl halide. The compound is

1 Ethoxyethane

2

2 -

Methoxypropane

3

1 -

Methoxypropane

4

1 -

Butanol

Explanation:

(a) Since a single alkyl halide is formed on treatment with HI, it must be a symmetrical ether i.e., ethoxyethane.
$C_{2} H_{5} O C_{2} H_{5} + 2 H I \to 2 C_{2} H_{5} I + H_{2} O$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28137 જ્યારે $C H_{2} = C H - C O O H$ is reduced with $L i A l H_{4}$ , the compound obtained will be

1

C H_{3} - C H_{2} - C O O H

2

C H_{2} = C H - C H_{2} O H

3

C H_{3} - C H_{2} - C H_{2} O H

4

C H_{3} - C H_{2} - C H O

Explanation:

(b) $C H_{2} = C H - C O O H \overset{L i A l H_{4}}{\to}$ $C H_{2} = C H - C H_{2} O H + H_{2} O$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28138 In a set of the given reactions, acetic acid yielded a product C.Product C would be $C H_{3} C O O H + P C l_{5} \to A \underset{a n h . A l C l_{3}}{\overset{C_{6} H_{6}}{\to}}$ $B \underset{e t h e r}{\overset{C_{2} H_{5} M g B r}{\to}} C$

1

\begin{matrix} C_{2} H_{5} \\ | \\ C H_{3} - C (O H) C_{6} H_{5} \end{matrix}

2

C H_{3} C H (O H) C_{2} H_{5}

3

C H_{3} C O C_{6} H_{5}

4

C H_{3} C H (O H) C_{6} H_{5}

Explanation:

$C H_{3} C O O H + P C l_{5} \to C H_{3} C O C l \underset{anh . A l C l_{3}}{\overset{C_{6} H_{6}}{\to}}$ $C H_{3} C O C_{6} H_{5} \underset{Ether}{\overset{C_{2} H_{5} M g B r}{\to}}$ $\begin{matrix} C_{2} H_{5} \\ | \\ C H_{3} - C (O H) C_{6} H_{5} \end{matrix}$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28139 Carboxylic acids are more acidic than phenol and alcohol because of

1 Intermolecular hydrogen bonding

2 Formation of dimers

3 Highly acidic hydrogen

4 Resonance stabilization of their conjugate base

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28136 An organic compound of molecular formula $C_{4} H_{10} O$ does not react with sodium. With excess of $H I,$ it gives only one type of alkyl halide. The compound is

1 Ethoxyethane

2

2 -

Methoxypropane

3

1 -

Methoxypropane

4

1 -

Butanol

Explanation:

(a) Since a single alkyl halide is formed on treatment with HI, it must be a symmetrical ether i.e., ethoxyethane.
$C_{2} H_{5} O C_{2} H_{5} + 2 H I \to 2 C_{2} H_{5} I + H_{2} O$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28137 જ્યારે $C H_{2} = C H - C O O H$ is reduced with $L i A l H_{4}$ , the compound obtained will be

1

C H_{3} - C H_{2} - C O O H

2

C H_{2} = C H - C H_{2} O H

3

C H_{3} - C H_{2} - C H_{2} O H

4

C H_{3} - C H_{2} - C H O

Explanation:

(b) $C H_{2} = C H - C O O H \overset{L i A l H_{4}}{\to}$ $C H_{2} = C H - C H_{2} O H + H_{2} O$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28138 In a set of the given reactions, acetic acid yielded a product C.Product C would be $C H_{3} C O O H + P C l_{5} \to A \underset{a n h . A l C l_{3}}{\overset{C_{6} H_{6}}{\to}}$ $B \underset{e t h e r}{\overset{C_{2} H_{5} M g B r}{\to}} C$

1

\begin{matrix} C_{2} H_{5} \\ | \\ C H_{3} - C (O H) C_{6} H_{5} \end{matrix}

2

C H_{3} C H (O H) C_{2} H_{5}

3

C H_{3} C O C_{6} H_{5}

4

C H_{3} C H (O H) C_{6} H_{5}

Explanation:

$C H_{3} C O O H + P C l_{5} \to C H_{3} C O C l \underset{anh . A l C l_{3}}{\overset{C_{6} H_{6}}{\to}}$ $C H_{3} C O C_{6} H_{5} \underset{Ether}{\overset{C_{2} H_{5} M g B r}{\to}}$ $\begin{matrix} C_{2} H_{5} \\ | \\ C H_{3} - C (O H) C_{6} H_{5} \end{matrix}$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28139 Carboxylic acids are more acidic than phenol and alcohol because of

1 Intermolecular hydrogen bonding

2 Formation of dimers

3 Highly acidic hydrogen

4 Resonance stabilization of their conjugate base

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28136 An organic compound of molecular formula $C_{4} H_{10} O$ does not react with sodium. With excess of $H I,$ it gives only one type of alkyl halide. The compound is

1 Ethoxyethane

2

2 -

Methoxypropane

3

1 -

Methoxypropane

4

1 -

Butanol

Explanation:

(a) Since a single alkyl halide is formed on treatment with HI, it must be a symmetrical ether i.e., ethoxyethane.
$C_{2} H_{5} O C_{2} H_{5} + 2 H I \to 2 C_{2} H_{5} I + H_{2} O$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28137 જ્યારે $C H_{2} = C H - C O O H$ is reduced with $L i A l H_{4}$ , the compound obtained will be

1

C H_{3} - C H_{2} - C O O H

2

C H_{2} = C H - C H_{2} O H

3

C H_{3} - C H_{2} - C H_{2} O H

4

C H_{3} - C H_{2} - C H O

Explanation:

(b) $C H_{2} = C H - C O O H \overset{L i A l H_{4}}{\to}$ $C H_{2} = C H - C H_{2} O H + H_{2} O$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28138 In a set of the given reactions, acetic acid yielded a product C.Product C would be $C H_{3} C O O H + P C l_{5} \to A \underset{a n h . A l C l_{3}}{\overset{C_{6} H_{6}}{\to}}$ $B \underset{e t h e r}{\overset{C_{2} H_{5} M g B r}{\to}} C$

1

\begin{matrix} C_{2} H_{5} \\ | \\ C H_{3} - C (O H) C_{6} H_{5} \end{matrix}

2

C H_{3} C H (O H) C_{2} H_{5}

3

C H_{3} C O C_{6} H_{5}

4

C H_{3} C H (O H) C_{6} H_{5}

Explanation:

$C H_{3} C O O H + P C l_{5} \to C H_{3} C O C l \underset{anh . A l C l_{3}}{\overset{C_{6} H_{6}}{\to}}$ $C H_{3} C O C_{6} H_{5} \underset{Ether}{\overset{C_{2} H_{5} M g B r}{\to}}$ $\begin{matrix} C_{2} H_{5} \\ | \\ C H_{3} - C (O H) C_{6} H_{5} \end{matrix}$

ALDEHYDES, KETONES AND CARBOXYLIC ACID

28139 Carboxylic acids are more acidic than phenol and alcohol because of

1 Intermolecular hydrogen bonding

2 Formation of dimers

3 Highly acidic hydrogen

4 Resonance stabilization of their conjugate base