26630
The following reagent converts \({C_6}{H_5}COCHO\) to \({C_6}{H_5}CHOHCOONa\)
1 \(Aq.\) \(NaOH\)
2 \(Acidic\) \(N{a_2}{S_2}{O_3}\)
3 \(N{a_2}Cr{O_4}/{H_2}S{O_4}\)
4 \(NaN{O_2}/HCl\)
Explanation:
It's Obvious.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26631
Benzyl alcohol and sodium benzoate is obtained by the action of sodium hydroxide on benzaldehyde. This reaction is known as
1 Perkin’s reaction
2 Cannizzaro’s reaction
3 Sandmeyer’s reaction
4 Claisen condensation
Explanation:
(b) Benzaldehyde on treatment with \(50\%\) aqueous or ethanolic alkali solution undergoes Cannizzaro’s reaction like \(HCHO\) (no \(\alpha \)-hydrogen atom) i.e., one molecule is oxidised and one is reduced with the formation of benzoic acid and benzyl alcohol respectively. \(2{C_6}{H_5}CHO\xrightarrow{{NaOH}}{C_6}{H_5}C{H_2}OH + {C_6}{H_5}COONa\)
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26632
To distinguish between formaldehyde and acetaldehyde, we require
1 Tollen's reagent
2 Fehling's solution
3 Schiff's reagent
4 Caustic soda solution
Explanation:
(d) \(2HCHO\mathop {\xrightarrow{{NaOH}}}\limits_{Conc.} C{H_3}OH + HCOONa\) It is aldol condensation reaction. \(2C{H_3}CHO\mathop {\xrightarrow{{NaOH}}}\limits_{dil} C{H_3} - \mathop {\mathop {CH}\limits^{|\,\,\,\,\,\,} }\limits^{OH} - C{H_2} - CHO\) It is aldol condensation reaction.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26633
Which of the following does not give iodoform test
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26630
The following reagent converts \({C_6}{H_5}COCHO\) to \({C_6}{H_5}CHOHCOONa\)
1 \(Aq.\) \(NaOH\)
2 \(Acidic\) \(N{a_2}{S_2}{O_3}\)
3 \(N{a_2}Cr{O_4}/{H_2}S{O_4}\)
4 \(NaN{O_2}/HCl\)
Explanation:
It's Obvious.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26631
Benzyl alcohol and sodium benzoate is obtained by the action of sodium hydroxide on benzaldehyde. This reaction is known as
1 Perkin’s reaction
2 Cannizzaro’s reaction
3 Sandmeyer’s reaction
4 Claisen condensation
Explanation:
(b) Benzaldehyde on treatment with \(50\%\) aqueous or ethanolic alkali solution undergoes Cannizzaro’s reaction like \(HCHO\) (no \(\alpha \)-hydrogen atom) i.e., one molecule is oxidised and one is reduced with the formation of benzoic acid and benzyl alcohol respectively. \(2{C_6}{H_5}CHO\xrightarrow{{NaOH}}{C_6}{H_5}C{H_2}OH + {C_6}{H_5}COONa\)
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26632
To distinguish between formaldehyde and acetaldehyde, we require
1 Tollen's reagent
2 Fehling's solution
3 Schiff's reagent
4 Caustic soda solution
Explanation:
(d) \(2HCHO\mathop {\xrightarrow{{NaOH}}}\limits_{Conc.} C{H_3}OH + HCOONa\) It is aldol condensation reaction. \(2C{H_3}CHO\mathop {\xrightarrow{{NaOH}}}\limits_{dil} C{H_3} - \mathop {\mathop {CH}\limits^{|\,\,\,\,\,\,} }\limits^{OH} - C{H_2} - CHO\) It is aldol condensation reaction.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26633
Which of the following does not give iodoform test
26630
The following reagent converts \({C_6}{H_5}COCHO\) to \({C_6}{H_5}CHOHCOONa\)
1 \(Aq.\) \(NaOH\)
2 \(Acidic\) \(N{a_2}{S_2}{O_3}\)
3 \(N{a_2}Cr{O_4}/{H_2}S{O_4}\)
4 \(NaN{O_2}/HCl\)
Explanation:
It's Obvious.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26631
Benzyl alcohol and sodium benzoate is obtained by the action of sodium hydroxide on benzaldehyde. This reaction is known as
1 Perkin’s reaction
2 Cannizzaro’s reaction
3 Sandmeyer’s reaction
4 Claisen condensation
Explanation:
(b) Benzaldehyde on treatment with \(50\%\) aqueous or ethanolic alkali solution undergoes Cannizzaro’s reaction like \(HCHO\) (no \(\alpha \)-hydrogen atom) i.e., one molecule is oxidised and one is reduced with the formation of benzoic acid and benzyl alcohol respectively. \(2{C_6}{H_5}CHO\xrightarrow{{NaOH}}{C_6}{H_5}C{H_2}OH + {C_6}{H_5}COONa\)
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26632
To distinguish between formaldehyde and acetaldehyde, we require
1 Tollen's reagent
2 Fehling's solution
3 Schiff's reagent
4 Caustic soda solution
Explanation:
(d) \(2HCHO\mathop {\xrightarrow{{NaOH}}}\limits_{Conc.} C{H_3}OH + HCOONa\) It is aldol condensation reaction. \(2C{H_3}CHO\mathop {\xrightarrow{{NaOH}}}\limits_{dil} C{H_3} - \mathop {\mathop {CH}\limits^{|\,\,\,\,\,\,} }\limits^{OH} - C{H_2} - CHO\) It is aldol condensation reaction.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26633
Which of the following does not give iodoform test
26630
The following reagent converts \({C_6}{H_5}COCHO\) to \({C_6}{H_5}CHOHCOONa\)
1 \(Aq.\) \(NaOH\)
2 \(Acidic\) \(N{a_2}{S_2}{O_3}\)
3 \(N{a_2}Cr{O_4}/{H_2}S{O_4}\)
4 \(NaN{O_2}/HCl\)
Explanation:
It's Obvious.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26631
Benzyl alcohol and sodium benzoate is obtained by the action of sodium hydroxide on benzaldehyde. This reaction is known as
1 Perkin’s reaction
2 Cannizzaro’s reaction
3 Sandmeyer’s reaction
4 Claisen condensation
Explanation:
(b) Benzaldehyde on treatment with \(50\%\) aqueous or ethanolic alkali solution undergoes Cannizzaro’s reaction like \(HCHO\) (no \(\alpha \)-hydrogen atom) i.e., one molecule is oxidised and one is reduced with the formation of benzoic acid and benzyl alcohol respectively. \(2{C_6}{H_5}CHO\xrightarrow{{NaOH}}{C_6}{H_5}C{H_2}OH + {C_6}{H_5}COONa\)
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26632
To distinguish between formaldehyde and acetaldehyde, we require
1 Tollen's reagent
2 Fehling's solution
3 Schiff's reagent
4 Caustic soda solution
Explanation:
(d) \(2HCHO\mathop {\xrightarrow{{NaOH}}}\limits_{Conc.} C{H_3}OH + HCOONa\) It is aldol condensation reaction. \(2C{H_3}CHO\mathop {\xrightarrow{{NaOH}}}\limits_{dil} C{H_3} - \mathop {\mathop {CH}\limits^{|\,\,\,\,\,\,} }\limits^{OH} - C{H_2} - CHO\) It is aldol condensation reaction.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
26633
Which of the following does not give iodoform test