15612
Suppose the following reactionBenzene \((C_6H_6)\) \(+\,C{{H}_{3}}-CH=C{{H}_{2}}\,\xrightarrow{{{H}^{\oplus }}}A\xrightarrow{{{O}_{2}}}B\) \(\xrightarrow{{{H}^{\oplus }}\,/\,\Delta }C+\)$\begin{matrix}
O \\
|| \\
C{{H}_{3}}-C-C{{H}_{3}} \\
\end{matrix}$The structure of intermediate compound \('B'\) will be
15613
In the following reaction$\begin{matrix}
\begin{matrix}
C{{H}_{3}}\,\,\,\,\,\,\,\, \,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\end{matrix} \\
C{{H}_{3}}-C-CH=C{{H}_{2}} \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}\,\,\,\,\,\,\,\, \,\,\,\, \\
\end{matrix}\,$ $\xrightarrow{{{H}_{2}}O/{{H}^{\oplus }}}$ $\underset{Major\,\,product}{\mathop{A}}\,$ $+$ $\underset{Major\,\,product}{\mathop{B}}\,$The major product is
15612
Suppose the following reactionBenzene \((C_6H_6)\) \(+\,C{{H}_{3}}-CH=C{{H}_{2}}\,\xrightarrow{{{H}^{\oplus }}}A\xrightarrow{{{O}_{2}}}B\) \(\xrightarrow{{{H}^{\oplus }}\,/\,\Delta }C+\)$\begin{matrix}
O \\
|| \\
C{{H}_{3}}-C-C{{H}_{3}} \\
\end{matrix}$The structure of intermediate compound \('B'\) will be
15613
In the following reaction$\begin{matrix}
\begin{matrix}
C{{H}_{3}}\,\,\,\,\,\,\,\, \,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\end{matrix} \\
C{{H}_{3}}-C-CH=C{{H}_{2}} \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}\,\,\,\,\,\,\,\, \,\,\,\, \\
\end{matrix}\,$ $\xrightarrow{{{H}_{2}}O/{{H}^{\oplus }}}$ $\underset{Major\,\,product}{\mathop{A}}\,$ $+$ $\underset{Major\,\,product}{\mathop{B}}\,$The major product is
15612
Suppose the following reactionBenzene \((C_6H_6)\) \(+\,C{{H}_{3}}-CH=C{{H}_{2}}\,\xrightarrow{{{H}^{\oplus }}}A\xrightarrow{{{O}_{2}}}B\) \(\xrightarrow{{{H}^{\oplus }}\,/\,\Delta }C+\)$\begin{matrix}
O \\
|| \\
C{{H}_{3}}-C-C{{H}_{3}} \\
\end{matrix}$The structure of intermediate compound \('B'\) will be
15613
In the following reaction$\begin{matrix}
\begin{matrix}
C{{H}_{3}}\,\,\,\,\,\,\,\, \,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\end{matrix} \\
C{{H}_{3}}-C-CH=C{{H}_{2}} \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}\,\,\,\,\,\,\,\, \,\,\,\, \\
\end{matrix}\,$ $\xrightarrow{{{H}_{2}}O/{{H}^{\oplus }}}$ $\underset{Major\,\,product}{\mathop{A}}\,$ $+$ $\underset{Major\,\,product}{\mathop{B}}\,$The major product is
15612
Suppose the following reactionBenzene \((C_6H_6)\) \(+\,C{{H}_{3}}-CH=C{{H}_{2}}\,\xrightarrow{{{H}^{\oplus }}}A\xrightarrow{{{O}_{2}}}B\) \(\xrightarrow{{{H}^{\oplus }}\,/\,\Delta }C+\)$\begin{matrix}
O \\
|| \\
C{{H}_{3}}-C-C{{H}_{3}} \\
\end{matrix}$The structure of intermediate compound \('B'\) will be
15613
In the following reaction$\begin{matrix}
\begin{matrix}
C{{H}_{3}}\,\,\,\,\,\,\,\, \,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\end{matrix} \\
C{{H}_{3}}-C-CH=C{{H}_{2}} \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}\,\,\,\,\,\,\,\, \,\,\,\, \\
\end{matrix}\,$ $\xrightarrow{{{H}_{2}}O/{{H}^{\oplus }}}$ $\underset{Major\,\,product}{\mathop{A}}\,$ $+$ $\underset{Major\,\,product}{\mathop{B}}\,$The major product is
15612
Suppose the following reactionBenzene \((C_6H_6)\) \(+\,C{{H}_{3}}-CH=C{{H}_{2}}\,\xrightarrow{{{H}^{\oplus }}}A\xrightarrow{{{O}_{2}}}B\) \(\xrightarrow{{{H}^{\oplus }}\,/\,\Delta }C+\)$\begin{matrix}
O \\
|| \\
C{{H}_{3}}-C-C{{H}_{3}} \\
\end{matrix}$The structure of intermediate compound \('B'\) will be
15613
In the following reaction$\begin{matrix}
\begin{matrix}
C{{H}_{3}}\,\,\,\,\,\,\,\, \,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\end{matrix} \\
C{{H}_{3}}-C-CH=C{{H}_{2}} \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}\,\,\,\,\,\,\,\, \,\,\,\, \\
\end{matrix}\,$ $\xrightarrow{{{H}_{2}}O/{{H}^{\oplus }}}$ $\underset{Major\,\,product}{\mathop{A}}\,$ $+$ $\underset{Major\,\,product}{\mathop{B}}\,$The major product is