15505
Ethanol cannot be dried by anhydrous \(CaCl_2\) due to formation of the following solvated product
1 \(CaCl_2·2C_2H_5OH\)
2 \(2CaCl_2·3C_2H_5OH\)
3 \(CaCl_2·3C_2H_5OH\)
4 \(CaCl_2·C_2H_5OH\)
Explanation:
ALCOHOLS, PHENOLS AND ETHER
15506
Rate of hydration of following will be in order :
1 \(I < II < III\)
2 \(I < III < II\)
3 \(II < I < III\)
4 \(III < II < I\)
Explanation:
ALCOHOLS, PHENOLS AND ETHER
15507
The reaction of \(CH_3OC_2H_5\) with \(HI\) gives
1 \(CH_3I\)
2 \(C_2H_5OH\)
3 \(CH_3I + C_2H_5OH\)
4 \(C_2H_5I + CH_3OH\)
Explanation:
When mixed ethers are used, the formation of alkyl iodide depends on the nature of alkyl groups. Methyl iodide is formed when one group is methyl and the other a primary or secondary alkyl group. Here reaction follows \(\mathrm{S}_{\mathrm{N}}{ }^{2}\) mechanism and because of the steric effect of the larger group, \(I^{-}\) attacks the smaller (methyl) group. \(\mathrm{CH}_{3} \mathrm{OC}_{2} \mathrm{H}_{5}+\mathrm{HI} \rightarrow \mathrm{CH}_{3} \mathrm{I}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) When the substrate is a methyl t-alkyl ether, the products are tertiary alkyl iodide and methanol. Here reaction follows \(\mathrm{S}_{\mathrm{N}}^{1}\) mechanism and formation of products is controlled by the stability of carbocation. since carbocation stability order is \(3^{0}>2^{0}>1^{0}>\mathrm{CH}_{3}\), therefore alkyl halide is always derived from tert-alkyl group. \(\begin{array}{c}\mathrm{CH}_{3} \\\mathrm{CH}_{3}-\mathrm{C}-\mathrm{O}-\mathrm{CH}_{3}+\mathrm{HI} \frac{373 \mathrm{K}}{\mathrm{SNI}} \mathrm{CH}_{3}-\mathrm{C}-\mathrm{I}+\mathrm{CH}_{3} \mathrm{OH} \\\mathrm{CH}_{3}\end{array}\) tert-Butyl methyl ether tert-Butyl iodide
ALCOHOLS, PHENOLS AND ETHER
15508
The number of methoxy groups in a compound can be determined by treating it with
15505
Ethanol cannot be dried by anhydrous \(CaCl_2\) due to formation of the following solvated product
1 \(CaCl_2·2C_2H_5OH\)
2 \(2CaCl_2·3C_2H_5OH\)
3 \(CaCl_2·3C_2H_5OH\)
4 \(CaCl_2·C_2H_5OH\)
Explanation:
ALCOHOLS, PHENOLS AND ETHER
15506
Rate of hydration of following will be in order :
1 \(I < II < III\)
2 \(I < III < II\)
3 \(II < I < III\)
4 \(III < II < I\)
Explanation:
ALCOHOLS, PHENOLS AND ETHER
15507
The reaction of \(CH_3OC_2H_5\) with \(HI\) gives
1 \(CH_3I\)
2 \(C_2H_5OH\)
3 \(CH_3I + C_2H_5OH\)
4 \(C_2H_5I + CH_3OH\)
Explanation:
When mixed ethers are used, the formation of alkyl iodide depends on the nature of alkyl groups. Methyl iodide is formed when one group is methyl and the other a primary or secondary alkyl group. Here reaction follows \(\mathrm{S}_{\mathrm{N}}{ }^{2}\) mechanism and because of the steric effect of the larger group, \(I^{-}\) attacks the smaller (methyl) group. \(\mathrm{CH}_{3} \mathrm{OC}_{2} \mathrm{H}_{5}+\mathrm{HI} \rightarrow \mathrm{CH}_{3} \mathrm{I}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) When the substrate is a methyl t-alkyl ether, the products are tertiary alkyl iodide and methanol. Here reaction follows \(\mathrm{S}_{\mathrm{N}}^{1}\) mechanism and formation of products is controlled by the stability of carbocation. since carbocation stability order is \(3^{0}>2^{0}>1^{0}>\mathrm{CH}_{3}\), therefore alkyl halide is always derived from tert-alkyl group. \(\begin{array}{c}\mathrm{CH}_{3} \\\mathrm{CH}_{3}-\mathrm{C}-\mathrm{O}-\mathrm{CH}_{3}+\mathrm{HI} \frac{373 \mathrm{K}}{\mathrm{SNI}} \mathrm{CH}_{3}-\mathrm{C}-\mathrm{I}+\mathrm{CH}_{3} \mathrm{OH} \\\mathrm{CH}_{3}\end{array}\) tert-Butyl methyl ether tert-Butyl iodide
ALCOHOLS, PHENOLS AND ETHER
15508
The number of methoxy groups in a compound can be determined by treating it with
15505
Ethanol cannot be dried by anhydrous \(CaCl_2\) due to formation of the following solvated product
1 \(CaCl_2·2C_2H_5OH\)
2 \(2CaCl_2·3C_2H_5OH\)
3 \(CaCl_2·3C_2H_5OH\)
4 \(CaCl_2·C_2H_5OH\)
Explanation:
ALCOHOLS, PHENOLS AND ETHER
15506
Rate of hydration of following will be in order :
1 \(I < II < III\)
2 \(I < III < II\)
3 \(II < I < III\)
4 \(III < II < I\)
Explanation:
ALCOHOLS, PHENOLS AND ETHER
15507
The reaction of \(CH_3OC_2H_5\) with \(HI\) gives
1 \(CH_3I\)
2 \(C_2H_5OH\)
3 \(CH_3I + C_2H_5OH\)
4 \(C_2H_5I + CH_3OH\)
Explanation:
When mixed ethers are used, the formation of alkyl iodide depends on the nature of alkyl groups. Methyl iodide is formed when one group is methyl and the other a primary or secondary alkyl group. Here reaction follows \(\mathrm{S}_{\mathrm{N}}{ }^{2}\) mechanism and because of the steric effect of the larger group, \(I^{-}\) attacks the smaller (methyl) group. \(\mathrm{CH}_{3} \mathrm{OC}_{2} \mathrm{H}_{5}+\mathrm{HI} \rightarrow \mathrm{CH}_{3} \mathrm{I}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) When the substrate is a methyl t-alkyl ether, the products are tertiary alkyl iodide and methanol. Here reaction follows \(\mathrm{S}_{\mathrm{N}}^{1}\) mechanism and formation of products is controlled by the stability of carbocation. since carbocation stability order is \(3^{0}>2^{0}>1^{0}>\mathrm{CH}_{3}\), therefore alkyl halide is always derived from tert-alkyl group. \(\begin{array}{c}\mathrm{CH}_{3} \\\mathrm{CH}_{3}-\mathrm{C}-\mathrm{O}-\mathrm{CH}_{3}+\mathrm{HI} \frac{373 \mathrm{K}}{\mathrm{SNI}} \mathrm{CH}_{3}-\mathrm{C}-\mathrm{I}+\mathrm{CH}_{3} \mathrm{OH} \\\mathrm{CH}_{3}\end{array}\) tert-Butyl methyl ether tert-Butyl iodide
ALCOHOLS, PHENOLS AND ETHER
15508
The number of methoxy groups in a compound can be determined by treating it with
15505
Ethanol cannot be dried by anhydrous \(CaCl_2\) due to formation of the following solvated product
1 \(CaCl_2·2C_2H_5OH\)
2 \(2CaCl_2·3C_2H_5OH\)
3 \(CaCl_2·3C_2H_5OH\)
4 \(CaCl_2·C_2H_5OH\)
Explanation:
ALCOHOLS, PHENOLS AND ETHER
15506
Rate of hydration of following will be in order :
1 \(I < II < III\)
2 \(I < III < II\)
3 \(II < I < III\)
4 \(III < II < I\)
Explanation:
ALCOHOLS, PHENOLS AND ETHER
15507
The reaction of \(CH_3OC_2H_5\) with \(HI\) gives
1 \(CH_3I\)
2 \(C_2H_5OH\)
3 \(CH_3I + C_2H_5OH\)
4 \(C_2H_5I + CH_3OH\)
Explanation:
When mixed ethers are used, the formation of alkyl iodide depends on the nature of alkyl groups. Methyl iodide is formed when one group is methyl and the other a primary or secondary alkyl group. Here reaction follows \(\mathrm{S}_{\mathrm{N}}{ }^{2}\) mechanism and because of the steric effect of the larger group, \(I^{-}\) attacks the smaller (methyl) group. \(\mathrm{CH}_{3} \mathrm{OC}_{2} \mathrm{H}_{5}+\mathrm{HI} \rightarrow \mathrm{CH}_{3} \mathrm{I}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) When the substrate is a methyl t-alkyl ether, the products are tertiary alkyl iodide and methanol. Here reaction follows \(\mathrm{S}_{\mathrm{N}}^{1}\) mechanism and formation of products is controlled by the stability of carbocation. since carbocation stability order is \(3^{0}>2^{0}>1^{0}>\mathrm{CH}_{3}\), therefore alkyl halide is always derived from tert-alkyl group. \(\begin{array}{c}\mathrm{CH}_{3} \\\mathrm{CH}_{3}-\mathrm{C}-\mathrm{O}-\mathrm{CH}_{3}+\mathrm{HI} \frac{373 \mathrm{K}}{\mathrm{SNI}} \mathrm{CH}_{3}-\mathrm{C}-\mathrm{I}+\mathrm{CH}_{3} \mathrm{OH} \\\mathrm{CH}_{3}\end{array}\) tert-Butyl methyl ether tert-Butyl iodide
ALCOHOLS, PHENOLS AND ETHER
15508
The number of methoxy groups in a compound can be determined by treating it with
