QBManager

COORDINATION COMPOUNDS

28875 Which of the following complex ions is not expected to absorb visible light?

1

[N i (C N)_{4}]^{2 -}

2

[C r (N H_{3})_{6}]^{3 +}

3

[F e (H_{2} O)_{6}]^{2 +}

4

[N i (H_{2} O)_{6}]^{2 +}

COORDINATION COMPOUNDS

28876 Crystal field stabilization energy for high spin $d^{4}$ octahedral complex is

1

- 1.8 Δ_{o}

2

- 1.6 Δ_{o} + P

3

- 1.2 Δ_{o}

4

- 0.6 Δ_{o}

Explanation:

Key ldea In case of high spin complex, $Δ_{0}$ is small. Thus, the energy required to pair up the fourth electron with the
electrons of lower energy d-orbitals would be higher than that required to place the electrons in the higher d-orbital.
Thus, pairing does not occur.
For high spin $d^{4}$ octahedral complex Crystal fleld stabilisation energy
$= (- 3 \times 0.4 + 1 \times 0.6) Δ_{0}$
$= (- 1.2 + 0.6) Δ_{0} = - 0.6 Δ_{0}$

COORDINATION COMPOUNDS

28877 The existance of two different coloured complexes with the composition of $[C o (N H_{3})_{4} C l_{2}]^{+}$ is due to

1 linkage isomerism

2 ionization isomerism.

3 coordination isomerism

4 geometrical isomerism

Explanation:

Complexes of $[M A_{4} B_{2}]$ type exhibit geometrical isomerism. The complex $[Co {({NH}_{3})}_{4} {Cl}_{2}] + i s a [M A_{4} B_{2}]$ type complex and thus, fulfills the conditions that are necessary to exhibit geometrical isomerism. Hence, it has two geometrical isomers of different colours as: The structure of the geometrical isomers is as For linkage isomerism, presence of ambidentate ligand is necessary. For coordination isomerism, both the cation and anion of the complex must be complex ions. For lonisation isomerism, an nion different to the ligands must be present outside the coordination sphere. All these conditions are not satisfled by this complex. Hence, it does not exhibit other given isomerisms. 345-s479

COORDINATION COMPOUNDS

28962 $C u^{2 +}$ shows a coordination number of

1

2

only

2

2

or

4

3

4

only

4

4

or

6

COORDINATION COMPOUNDS

28875 Which of the following complex ions is not expected to absorb visible light?

1

[N i (C N)_{4}]^{2 -}

2

[C r (N H_{3})_{6}]^{3 +}

3

[F e (H_{2} O)_{6}]^{2 +}

4

[N i (H_{2} O)_{6}]^{2 +}

COORDINATION COMPOUNDS

28876 Crystal field stabilization energy for high spin $d^{4}$ octahedral complex is

1

- 1.8 Δ_{o}

2

- 1.6 Δ_{o} + P

3

- 1.2 Δ_{o}

4

- 0.6 Δ_{o}

Explanation:

Key ldea In case of high spin complex, $Δ_{0}$ is small. Thus, the energy required to pair up the fourth electron with the
electrons of lower energy d-orbitals would be higher than that required to place the electrons in the higher d-orbital.
Thus, pairing does not occur.
For high spin $d^{4}$ octahedral complex Crystal fleld stabilisation energy
$= (- 3 \times 0.4 + 1 \times 0.6) Δ_{0}$
$= (- 1.2 + 0.6) Δ_{0} = - 0.6 Δ_{0}$

COORDINATION COMPOUNDS

28877 The existance of two different coloured complexes with the composition of $[C o (N H_{3})_{4} C l_{2}]^{+}$ is due to

1 linkage isomerism

2 ionization isomerism.

3 coordination isomerism

4 geometrical isomerism

Explanation:

Complexes of $[M A_{4} B_{2}]$ type exhibit geometrical isomerism. The complex $[Co {({NH}_{3})}_{4} {Cl}_{2}] + i s a [M A_{4} B_{2}]$ type complex and thus, fulfills the conditions that are necessary to exhibit geometrical isomerism. Hence, it has two geometrical isomers of different colours as: The structure of the geometrical isomers is as For linkage isomerism, presence of ambidentate ligand is necessary. For coordination isomerism, both the cation and anion of the complex must be complex ions. For lonisation isomerism, an nion different to the ligands must be present outside the coordination sphere. All these conditions are not satisfled by this complex. Hence, it does not exhibit other given isomerisms. 345-s479

COORDINATION COMPOUNDS

28962 $C u^{2 +}$ shows a coordination number of

1

2

only

2

2

or

4

3

4

only

4

4

or

6

COORDINATION COMPOUNDS

28875 Which of the following complex ions is not expected to absorb visible light?

1

[N i (C N)_{4}]^{2 -}

2

[C r (N H_{3})_{6}]^{3 +}

3

[F e (H_{2} O)_{6}]^{2 +}

4

[N i (H_{2} O)_{6}]^{2 +}

COORDINATION COMPOUNDS

28876 Crystal field stabilization energy for high spin $d^{4}$ octahedral complex is

1

- 1.8 Δ_{o}

2

- 1.6 Δ_{o} + P

3

- 1.2 Δ_{o}

4

- 0.6 Δ_{o}

Explanation:

Key ldea In case of high spin complex, $Δ_{0}$ is small. Thus, the energy required to pair up the fourth electron with the
electrons of lower energy d-orbitals would be higher than that required to place the electrons in the higher d-orbital.
Thus, pairing does not occur.
For high spin $d^{4}$ octahedral complex Crystal fleld stabilisation energy
$= (- 3 \times 0.4 + 1 \times 0.6) Δ_{0}$
$= (- 1.2 + 0.6) Δ_{0} = - 0.6 Δ_{0}$

COORDINATION COMPOUNDS

28877 The existance of two different coloured complexes with the composition of $[C o (N H_{3})_{4} C l_{2}]^{+}$ is due to

1 linkage isomerism

2 ionization isomerism.

3 coordination isomerism

4 geometrical isomerism

Explanation:

Complexes of $[M A_{4} B_{2}]$ type exhibit geometrical isomerism. The complex $[Co {({NH}_{3})}_{4} {Cl}_{2}] + i s a [M A_{4} B_{2}]$ type complex and thus, fulfills the conditions that are necessary to exhibit geometrical isomerism. Hence, it has two geometrical isomers of different colours as: The structure of the geometrical isomers is as For linkage isomerism, presence of ambidentate ligand is necessary. For coordination isomerism, both the cation and anion of the complex must be complex ions. For lonisation isomerism, an nion different to the ligands must be present outside the coordination sphere. All these conditions are not satisfled by this complex. Hence, it does not exhibit other given isomerisms. 345-s479

COORDINATION COMPOUNDS

28962 $C u^{2 +}$ shows a coordination number of

1

2

only

2

2

or

4

3

4

only

4

4

or

6

COORDINATION COMPOUNDS

28875 Which of the following complex ions is not expected to absorb visible light?

1

[N i (C N)_{4}]^{2 -}

2

[C r (N H_{3})_{6}]^{3 +}

3

[F e (H_{2} O)_{6}]^{2 +}

4

[N i (H_{2} O)_{6}]^{2 +}

COORDINATION COMPOUNDS

28876 Crystal field stabilization energy for high spin $d^{4}$ octahedral complex is

1

- 1.8 Δ_{o}

2

- 1.6 Δ_{o} + P

3

- 1.2 Δ_{o}

4

- 0.6 Δ_{o}

Explanation:

Key ldea In case of high spin complex, $Δ_{0}$ is small. Thus, the energy required to pair up the fourth electron with the
electrons of lower energy d-orbitals would be higher than that required to place the electrons in the higher d-orbital.
Thus, pairing does not occur.
For high spin $d^{4}$ octahedral complex Crystal fleld stabilisation energy
$= (- 3 \times 0.4 + 1 \times 0.6) Δ_{0}$
$= (- 1.2 + 0.6) Δ_{0} = - 0.6 Δ_{0}$

COORDINATION COMPOUNDS

28877 The existance of two different coloured complexes with the composition of $[C o (N H_{3})_{4} C l_{2}]^{+}$ is due to

1 linkage isomerism

2 ionization isomerism.

3 coordination isomerism

4 geometrical isomerism

Explanation:

Complexes of $[M A_{4} B_{2}]$ type exhibit geometrical isomerism. The complex $[Co {({NH}_{3})}_{4} {Cl}_{2}] + i s a [M A_{4} B_{2}]$ type complex and thus, fulfills the conditions that are necessary to exhibit geometrical isomerism. Hence, it has two geometrical isomers of different colours as: The structure of the geometrical isomers is as For linkage isomerism, presence of ambidentate ligand is necessary. For coordination isomerism, both the cation and anion of the complex must be complex ions. For lonisation isomerism, an nion different to the ligands must be present outside the coordination sphere. All these conditions are not satisfled by this complex. Hence, it does not exhibit other given isomerisms. 345-s479

COORDINATION COMPOUNDS

28962 $C u^{2 +}$ shows a coordination number of

1

2

only

2

2

or

4

3

4

only

4

4

or

6

Explanation:

Explanation:

Explanation:

Explanation:

Question Bank Series

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation: