Explanation:

Magnetic moment \(1.73\, \mathrm{BM}\)
\(\mu=\sqrt{n(n+2)} B \cdot M\)
\(\mathrm{n}=\) no. of unpaired \(e^-\)
\(\mu=1.73\)
\(1.73=\sqrt{n(n+2)} B \cdot M\)
\(n=1\)
\(\left[C o C l_{6}\right]^{4-} \rightarrow C o^{+2} ; d^{7}\)
\(\mathrm{Cl}^ -\) (weak field ligand) unpaired \(e^{-}=3\)
\(\left[C u\left(N H_{3}\right)_{4}\right]^{2+} C u^{+2}-d^{9}\)
\(N H_{3}\) Strong field ligand, hybridisation \(d s p^{2}\) one \(e^{-}\) of \(3 d\)
\(\left[N i(C N)_{4}\right]^{2-} \rightarrow N i^{+2}-d^{8}\) unpaired \(e^{-}=0\)
\(C N^{-}\) - Strong field ligand \(d s p^{2}\)
\(T i C l_{4} \rightarrow T i^{+4} d^{o}\) unpaired \(e^-=z e r o\)

Explanation:

\(\mathrm{AgNO}_{3}+\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4} \mathrm{Cl}_{2}\right] \mathrm{Cl} \longrightarrow \mathrm{AgCl}\)
Excess mole \(=M V_{(lit)}\)
\(=0.01 \times \frac{100}{1000}\)
\(=0.001\)

Explanation:

in the case of high spin complex \(\Delta_{0}\) is small. Thus, the energy required to pair up the fourth electron with the electrons of lower energy \(d-\)orbitals would be higher than that required to place the electrons in the higher \(d-\)orbital. Thus pairing does not occur.
For high spin \(d^4\) octahedral complex,
therefore, Crystal field stabilisation energy
\(=(-3 \times 0.4+1 \times 0.6) \Delta_{0}\)
\(=-(-1.2 \times 0.6) \Delta_{0}\)
\(=-0.6\Delta_{0}\)

Explanation:

Explanation:

Magnetic moment \(1.73\, \mathrm{BM}\)
\(\mu=\sqrt{n(n+2)} B \cdot M\)
\(\mathrm{n}=\) no. of unpaired \(e^-\)
\(\mu=1.73\)
\(1.73=\sqrt{n(n+2)} B \cdot M\)
\(n=1\)
\(\left[C o C l_{6}\right]^{4-} \rightarrow C o^{+2} ; d^{7}\)
\(\mathrm{Cl}^ -\) (weak field ligand) unpaired \(e^{-}=3\)
\(\left[C u\left(N H_{3}\right)_{4}\right]^{2+} C u^{+2}-d^{9}\)
\(N H_{3}\) Strong field ligand, hybridisation \(d s p^{2}\) one \(e^{-}\) of \(3 d\)
\(\left[N i(C N)_{4}\right]^{2-} \rightarrow N i^{+2}-d^{8}\) unpaired \(e^{-}=0\)
\(C N^{-}\) - Strong field ligand \(d s p^{2}\)
\(T i C l_{4} \rightarrow T i^{+4} d^{o}\) unpaired \(e^-=z e r o\)

Explanation:

\(\mathrm{AgNO}_{3}+\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4} \mathrm{Cl}_{2}\right] \mathrm{Cl} \longrightarrow \mathrm{AgCl}\)
Excess mole \(=M V_{(lit)}\)
\(=0.01 \times \frac{100}{1000}\)
\(=0.001\)

Explanation:

in the case of high spin complex \(\Delta_{0}\) is small. Thus, the energy required to pair up the fourth electron with the electrons of lower energy \(d-\)orbitals would be higher than that required to place the electrons in the higher \(d-\)orbital. Thus pairing does not occur.
For high spin \(d^4\) octahedral complex,
therefore, Crystal field stabilisation energy
\(=(-3 \times 0.4+1 \times 0.6) \Delta_{0}\)
\(=-(-1.2 \times 0.6) \Delta_{0}\)
\(=-0.6\Delta_{0}\)

Explanation:

Explanation:

Magnetic moment \(1.73\, \mathrm{BM}\)
\(\mu=\sqrt{n(n+2)} B \cdot M\)
\(\mathrm{n}=\) no. of unpaired \(e^-\)
\(\mu=1.73\)
\(1.73=\sqrt{n(n+2)} B \cdot M\)
\(n=1\)
\(\left[C o C l_{6}\right]^{4-} \rightarrow C o^{+2} ; d^{7}\)
\(\mathrm{Cl}^ -\) (weak field ligand) unpaired \(e^{-}=3\)
\(\left[C u\left(N H_{3}\right)_{4}\right]^{2+} C u^{+2}-d^{9}\)
\(N H_{3}\) Strong field ligand, hybridisation \(d s p^{2}\) one \(e^{-}\) of \(3 d\)
\(\left[N i(C N)_{4}\right]^{2-} \rightarrow N i^{+2}-d^{8}\) unpaired \(e^{-}=0\)
\(C N^{-}\) - Strong field ligand \(d s p^{2}\)
\(T i C l_{4} \rightarrow T i^{+4} d^{o}\) unpaired \(e^-=z e r o\)

Explanation:

\(\mathrm{AgNO}_{3}+\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4} \mathrm{Cl}_{2}\right] \mathrm{Cl} \longrightarrow \mathrm{AgCl}\)
Excess mole \(=M V_{(lit)}\)
\(=0.01 \times \frac{100}{1000}\)
\(=0.001\)

Explanation:

in the case of high spin complex \(\Delta_{0}\) is small. Thus, the energy required to pair up the fourth electron with the electrons of lower energy \(d-\)orbitals would be higher than that required to place the electrons in the higher \(d-\)orbital. Thus pairing does not occur.
For high spin \(d^4\) octahedral complex,
therefore, Crystal field stabilisation energy
\(=(-3 \times 0.4+1 \times 0.6) \Delta_{0}\)
\(=-(-1.2 \times 0.6) \Delta_{0}\)
\(=-0.6\Delta_{0}\)

Explanation:

Explanation:

Magnetic moment \(1.73\, \mathrm{BM}\)
\(\mu=\sqrt{n(n+2)} B \cdot M\)
\(\mathrm{n}=\) no. of unpaired \(e^-\)
\(\mu=1.73\)
\(1.73=\sqrt{n(n+2)} B \cdot M\)
\(n=1\)
\(\left[C o C l_{6}\right]^{4-} \rightarrow C o^{+2} ; d^{7}\)
\(\mathrm{Cl}^ -\) (weak field ligand) unpaired \(e^{-}=3\)
\(\left[C u\left(N H_{3}\right)_{4}\right]^{2+} C u^{+2}-d^{9}\)
\(N H_{3}\) Strong field ligand, hybridisation \(d s p^{2}\) one \(e^{-}\) of \(3 d\)
\(\left[N i(C N)_{4}\right]^{2-} \rightarrow N i^{+2}-d^{8}\) unpaired \(e^{-}=0\)
\(C N^{-}\) - Strong field ligand \(d s p^{2}\)
\(T i C l_{4} \rightarrow T i^{+4} d^{o}\) unpaired \(e^-=z e r o\)

Explanation:

\(\mathrm{AgNO}_{3}+\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4} \mathrm{Cl}_{2}\right] \mathrm{Cl} \longrightarrow \mathrm{AgCl}\)
Excess mole \(=M V_{(lit)}\)
\(=0.01 \times \frac{100}{1000}\)
\(=0.001\)

Explanation:

in the case of high spin complex \(\Delta_{0}\) is small. Thus, the energy required to pair up the fourth electron with the electrons of lower energy \(d-\)orbitals would be higher than that required to place the electrons in the higher \(d-\)orbital. Thus pairing does not occur.
For high spin \(d^4\) octahedral complex,
therefore, Crystal field stabilisation energy
\(=(-3 \times 0.4+1 \times 0.6) \Delta_{0}\)
\(=-(-1.2 \times 0.6) \Delta_{0}\)
\(=-0.6\Delta_{0}\)

Explanation: