28853
Number of possible isomers for the complex \([Co(en)_2Cl_2]Cl\) will be \((en =\) ethylenediamine$)$
1 \(1\)
2 \(3\)
3 \(4\)
4 \(2\)
Explanation:
\(\left[\mathrm{Co}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right] \mathrm{Cl}\) Possible isomers - \((i)\) Geometrical isomers \((ii)\) In trans form plane of symmetry present, so trans form is optically inactive but cis is optically active Total number of stereoisomer \(=2+1=3\)
COORDINATION COMPOUNDS
28854
Cobalt \((III)\) chloride forms several octahedral complexes with ammonia. Which of the following will not give test for chloride ions with silver nitrate at \(25\,^o C\) ?
1 \(CoCl_3 \cdot 5NH_3\)
2 \(CoCl_3 \cdot 6NH_3\)
3 \(CoCl_3 \cdot 3NH_3\)
4 \(CoCl_3 \cdot 4NH_3\)
Explanation:
Octahedral complex means it contains '\(6\)' coordinate bond. In \(\mathrm{CoCl}_{3} \cdot 3 \mathrm{NH}_{3}, \mathrm{Cl}\) cannot be outside from coordination sphere
COORDINATION COMPOUNDS
28855
Which of these statements about \([Co(CN)_6]^{3-}\) is true?
1 \([Co(CN)_6]^{3-}\) has four unpaired electrons and will be in a high-spin configuration.
2 \([Co(CN)_6]^{3-}\) has no unpaired electrons and will be in a high-spin configuration.
3 \([Co(CN)_6]^{3-}\) has no unpaired electrons and will be in a low-spin configuration.
4 \([Co(CN)_6]^{3-}\) has four unpaired electrons and will be in a low-spin configuration.
Explanation:
\(\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{-3}\) \(\mathrm{Co}^{+3}=3 \mathrm{d}^{6} 4 \mathrm{s}^{0} 4 \mathrm{p}^{0}\) \(\because\) in presence of strong field ligand, pairing of electrons occurs so in this complex no unpaired electron is present and it is low spin complex.
COORDINATION COMPOUNDS
28856
Among the following complexes the one which shows zero crystal field stabilization energy \((CFSE)\) is
1 \([Mn(H_2O)_6]^{3+}\)
2 \([Fe(H_2O)_6]^{3+}\)
3 \([Co(H_2O)_6]^{2+}\)
4 \([Co(H_2O)_6]^{3+}\)
Explanation:
\(\mathrm{H}_{2} \mathrm{O}\) is a weak field ligand, hence \(\Delta_{o}<\) pairing energy. \(\mathrm{CFSE}=(-0.4 x+0.6 y) \Delta_{o}\) where, \(x\) and \(y\) are no. of electrons occupying \(t_{2 g}\) and es orbitals respectively. For \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) complex ion. \(\mathrm{Fe}^{3+}\left(3 d^{5}\right) =t_{2 \mathrm{g}}^{3} e_{\mathrm{g}}^{2}=-0.4 \times 3+0.6 \times 2\) \(=0.0 \text { or } 0\; \mathrm{Dq}\)
COORDINATION COMPOUNDS
28857
Which of the following complexes is used to be as an anticancer agent?
1 \(mer-[Co(NH_3)_3Cl_3]\)
2 \(cis-[PtCl_2(NH_3)_2]\)
3 \(cis-K_2[PtCl_2Br_2]\)
4 \(Na_2CoCl_4\)
Explanation:
Cis-platin is known as anticancer agent. The formula of cis-platin is \(c i s-\left[P t C l_{2}\left(N H_{3}\right)_{2}\right] .\) Here, the word \(c\) is refers to geometrical isomer of \(\left[P t C l_{2}(N H_3)_{2}\right] .\) It is used as an antitumour agent.
28853
Number of possible isomers for the complex \([Co(en)_2Cl_2]Cl\) will be \((en =\) ethylenediamine$)$
1 \(1\)
2 \(3\)
3 \(4\)
4 \(2\)
Explanation:
\(\left[\mathrm{Co}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right] \mathrm{Cl}\) Possible isomers - \((i)\) Geometrical isomers \((ii)\) In trans form plane of symmetry present, so trans form is optically inactive but cis is optically active Total number of stereoisomer \(=2+1=3\)
COORDINATION COMPOUNDS
28854
Cobalt \((III)\) chloride forms several octahedral complexes with ammonia. Which of the following will not give test for chloride ions with silver nitrate at \(25\,^o C\) ?
1 \(CoCl_3 \cdot 5NH_3\)
2 \(CoCl_3 \cdot 6NH_3\)
3 \(CoCl_3 \cdot 3NH_3\)
4 \(CoCl_3 \cdot 4NH_3\)
Explanation:
Octahedral complex means it contains '\(6\)' coordinate bond. In \(\mathrm{CoCl}_{3} \cdot 3 \mathrm{NH}_{3}, \mathrm{Cl}\) cannot be outside from coordination sphere
COORDINATION COMPOUNDS
28855
Which of these statements about \([Co(CN)_6]^{3-}\) is true?
1 \([Co(CN)_6]^{3-}\) has four unpaired electrons and will be in a high-spin configuration.
2 \([Co(CN)_6]^{3-}\) has no unpaired electrons and will be in a high-spin configuration.
3 \([Co(CN)_6]^{3-}\) has no unpaired electrons and will be in a low-spin configuration.
4 \([Co(CN)_6]^{3-}\) has four unpaired electrons and will be in a low-spin configuration.
Explanation:
\(\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{-3}\) \(\mathrm{Co}^{+3}=3 \mathrm{d}^{6} 4 \mathrm{s}^{0} 4 \mathrm{p}^{0}\) \(\because\) in presence of strong field ligand, pairing of electrons occurs so in this complex no unpaired electron is present and it is low spin complex.
COORDINATION COMPOUNDS
28856
Among the following complexes the one which shows zero crystal field stabilization energy \((CFSE)\) is
1 \([Mn(H_2O)_6]^{3+}\)
2 \([Fe(H_2O)_6]^{3+}\)
3 \([Co(H_2O)_6]^{2+}\)
4 \([Co(H_2O)_6]^{3+}\)
Explanation:
\(\mathrm{H}_{2} \mathrm{O}\) is a weak field ligand, hence \(\Delta_{o}<\) pairing energy. \(\mathrm{CFSE}=(-0.4 x+0.6 y) \Delta_{o}\) where, \(x\) and \(y\) are no. of electrons occupying \(t_{2 g}\) and es orbitals respectively. For \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) complex ion. \(\mathrm{Fe}^{3+}\left(3 d^{5}\right) =t_{2 \mathrm{g}}^{3} e_{\mathrm{g}}^{2}=-0.4 \times 3+0.6 \times 2\) \(=0.0 \text { or } 0\; \mathrm{Dq}\)
COORDINATION COMPOUNDS
28857
Which of the following complexes is used to be as an anticancer agent?
1 \(mer-[Co(NH_3)_3Cl_3]\)
2 \(cis-[PtCl_2(NH_3)_2]\)
3 \(cis-K_2[PtCl_2Br_2]\)
4 \(Na_2CoCl_4\)
Explanation:
Cis-platin is known as anticancer agent. The formula of cis-platin is \(c i s-\left[P t C l_{2}\left(N H_{3}\right)_{2}\right] .\) Here, the word \(c\) is refers to geometrical isomer of \(\left[P t C l_{2}(N H_3)_{2}\right] .\) It is used as an antitumour agent.
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
COORDINATION COMPOUNDS
28853
Number of possible isomers for the complex \([Co(en)_2Cl_2]Cl\) will be \((en =\) ethylenediamine$)$
1 \(1\)
2 \(3\)
3 \(4\)
4 \(2\)
Explanation:
\(\left[\mathrm{Co}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right] \mathrm{Cl}\) Possible isomers - \((i)\) Geometrical isomers \((ii)\) In trans form plane of symmetry present, so trans form is optically inactive but cis is optically active Total number of stereoisomer \(=2+1=3\)
COORDINATION COMPOUNDS
28854
Cobalt \((III)\) chloride forms several octahedral complexes with ammonia. Which of the following will not give test for chloride ions with silver nitrate at \(25\,^o C\) ?
1 \(CoCl_3 \cdot 5NH_3\)
2 \(CoCl_3 \cdot 6NH_3\)
3 \(CoCl_3 \cdot 3NH_3\)
4 \(CoCl_3 \cdot 4NH_3\)
Explanation:
Octahedral complex means it contains '\(6\)' coordinate bond. In \(\mathrm{CoCl}_{3} \cdot 3 \mathrm{NH}_{3}, \mathrm{Cl}\) cannot be outside from coordination sphere
COORDINATION COMPOUNDS
28855
Which of these statements about \([Co(CN)_6]^{3-}\) is true?
1 \([Co(CN)_6]^{3-}\) has four unpaired electrons and will be in a high-spin configuration.
2 \([Co(CN)_6]^{3-}\) has no unpaired electrons and will be in a high-spin configuration.
3 \([Co(CN)_6]^{3-}\) has no unpaired electrons and will be in a low-spin configuration.
4 \([Co(CN)_6]^{3-}\) has four unpaired electrons and will be in a low-spin configuration.
Explanation:
\(\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{-3}\) \(\mathrm{Co}^{+3}=3 \mathrm{d}^{6} 4 \mathrm{s}^{0} 4 \mathrm{p}^{0}\) \(\because\) in presence of strong field ligand, pairing of electrons occurs so in this complex no unpaired electron is present and it is low spin complex.
COORDINATION COMPOUNDS
28856
Among the following complexes the one which shows zero crystal field stabilization energy \((CFSE)\) is
1 \([Mn(H_2O)_6]^{3+}\)
2 \([Fe(H_2O)_6]^{3+}\)
3 \([Co(H_2O)_6]^{2+}\)
4 \([Co(H_2O)_6]^{3+}\)
Explanation:
\(\mathrm{H}_{2} \mathrm{O}\) is a weak field ligand, hence \(\Delta_{o}<\) pairing energy. \(\mathrm{CFSE}=(-0.4 x+0.6 y) \Delta_{o}\) where, \(x\) and \(y\) are no. of electrons occupying \(t_{2 g}\) and es orbitals respectively. For \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) complex ion. \(\mathrm{Fe}^{3+}\left(3 d^{5}\right) =t_{2 \mathrm{g}}^{3} e_{\mathrm{g}}^{2}=-0.4 \times 3+0.6 \times 2\) \(=0.0 \text { or } 0\; \mathrm{Dq}\)
COORDINATION COMPOUNDS
28857
Which of the following complexes is used to be as an anticancer agent?
1 \(mer-[Co(NH_3)_3Cl_3]\)
2 \(cis-[PtCl_2(NH_3)_2]\)
3 \(cis-K_2[PtCl_2Br_2]\)
4 \(Na_2CoCl_4\)
Explanation:
Cis-platin is known as anticancer agent. The formula of cis-platin is \(c i s-\left[P t C l_{2}\left(N H_{3}\right)_{2}\right] .\) Here, the word \(c\) is refers to geometrical isomer of \(\left[P t C l_{2}(N H_3)_{2}\right] .\) It is used as an antitumour agent.
28853
Number of possible isomers for the complex \([Co(en)_2Cl_2]Cl\) will be \((en =\) ethylenediamine$)$
1 \(1\)
2 \(3\)
3 \(4\)
4 \(2\)
Explanation:
\(\left[\mathrm{Co}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right] \mathrm{Cl}\) Possible isomers - \((i)\) Geometrical isomers \((ii)\) In trans form plane of symmetry present, so trans form is optically inactive but cis is optically active Total number of stereoisomer \(=2+1=3\)
COORDINATION COMPOUNDS
28854
Cobalt \((III)\) chloride forms several octahedral complexes with ammonia. Which of the following will not give test for chloride ions with silver nitrate at \(25\,^o C\) ?
1 \(CoCl_3 \cdot 5NH_3\)
2 \(CoCl_3 \cdot 6NH_3\)
3 \(CoCl_3 \cdot 3NH_3\)
4 \(CoCl_3 \cdot 4NH_3\)
Explanation:
Octahedral complex means it contains '\(6\)' coordinate bond. In \(\mathrm{CoCl}_{3} \cdot 3 \mathrm{NH}_{3}, \mathrm{Cl}\) cannot be outside from coordination sphere
COORDINATION COMPOUNDS
28855
Which of these statements about \([Co(CN)_6]^{3-}\) is true?
1 \([Co(CN)_6]^{3-}\) has four unpaired electrons and will be in a high-spin configuration.
2 \([Co(CN)_6]^{3-}\) has no unpaired electrons and will be in a high-spin configuration.
3 \([Co(CN)_6]^{3-}\) has no unpaired electrons and will be in a low-spin configuration.
4 \([Co(CN)_6]^{3-}\) has four unpaired electrons and will be in a low-spin configuration.
Explanation:
\(\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{-3}\) \(\mathrm{Co}^{+3}=3 \mathrm{d}^{6} 4 \mathrm{s}^{0} 4 \mathrm{p}^{0}\) \(\because\) in presence of strong field ligand, pairing of electrons occurs so in this complex no unpaired electron is present and it is low spin complex.
COORDINATION COMPOUNDS
28856
Among the following complexes the one which shows zero crystal field stabilization energy \((CFSE)\) is
1 \([Mn(H_2O)_6]^{3+}\)
2 \([Fe(H_2O)_6]^{3+}\)
3 \([Co(H_2O)_6]^{2+}\)
4 \([Co(H_2O)_6]^{3+}\)
Explanation:
\(\mathrm{H}_{2} \mathrm{O}\) is a weak field ligand, hence \(\Delta_{o}<\) pairing energy. \(\mathrm{CFSE}=(-0.4 x+0.6 y) \Delta_{o}\) where, \(x\) and \(y\) are no. of electrons occupying \(t_{2 g}\) and es orbitals respectively. For \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) complex ion. \(\mathrm{Fe}^{3+}\left(3 d^{5}\right) =t_{2 \mathrm{g}}^{3} e_{\mathrm{g}}^{2}=-0.4 \times 3+0.6 \times 2\) \(=0.0 \text { or } 0\; \mathrm{Dq}\)
COORDINATION COMPOUNDS
28857
Which of the following complexes is used to be as an anticancer agent?
1 \(mer-[Co(NH_3)_3Cl_3]\)
2 \(cis-[PtCl_2(NH_3)_2]\)
3 \(cis-K_2[PtCl_2Br_2]\)
4 \(Na_2CoCl_4\)
Explanation:
Cis-platin is known as anticancer agent. The formula of cis-platin is \(c i s-\left[P t C l_{2}\left(N H_{3}\right)_{2}\right] .\) Here, the word \(c\) is refers to geometrical isomer of \(\left[P t C l_{2}(N H_3)_{2}\right] .\) It is used as an antitumour agent.
28853
Number of possible isomers for the complex \([Co(en)_2Cl_2]Cl\) will be \((en =\) ethylenediamine$)$
1 \(1\)
2 \(3\)
3 \(4\)
4 \(2\)
Explanation:
\(\left[\mathrm{Co}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right] \mathrm{Cl}\) Possible isomers - \((i)\) Geometrical isomers \((ii)\) In trans form plane of symmetry present, so trans form is optically inactive but cis is optically active Total number of stereoisomer \(=2+1=3\)
COORDINATION COMPOUNDS
28854
Cobalt \((III)\) chloride forms several octahedral complexes with ammonia. Which of the following will not give test for chloride ions with silver nitrate at \(25\,^o C\) ?
1 \(CoCl_3 \cdot 5NH_3\)
2 \(CoCl_3 \cdot 6NH_3\)
3 \(CoCl_3 \cdot 3NH_3\)
4 \(CoCl_3 \cdot 4NH_3\)
Explanation:
Octahedral complex means it contains '\(6\)' coordinate bond. In \(\mathrm{CoCl}_{3} \cdot 3 \mathrm{NH}_{3}, \mathrm{Cl}\) cannot be outside from coordination sphere
COORDINATION COMPOUNDS
28855
Which of these statements about \([Co(CN)_6]^{3-}\) is true?
1 \([Co(CN)_6]^{3-}\) has four unpaired electrons and will be in a high-spin configuration.
2 \([Co(CN)_6]^{3-}\) has no unpaired electrons and will be in a high-spin configuration.
3 \([Co(CN)_6]^{3-}\) has no unpaired electrons and will be in a low-spin configuration.
4 \([Co(CN)_6]^{3-}\) has four unpaired electrons and will be in a low-spin configuration.
Explanation:
\(\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{-3}\) \(\mathrm{Co}^{+3}=3 \mathrm{d}^{6} 4 \mathrm{s}^{0} 4 \mathrm{p}^{0}\) \(\because\) in presence of strong field ligand, pairing of electrons occurs so in this complex no unpaired electron is present and it is low spin complex.
COORDINATION COMPOUNDS
28856
Among the following complexes the one which shows zero crystal field stabilization energy \((CFSE)\) is
1 \([Mn(H_2O)_6]^{3+}\)
2 \([Fe(H_2O)_6]^{3+}\)
3 \([Co(H_2O)_6]^{2+}\)
4 \([Co(H_2O)_6]^{3+}\)
Explanation:
\(\mathrm{H}_{2} \mathrm{O}\) is a weak field ligand, hence \(\Delta_{o}<\) pairing energy. \(\mathrm{CFSE}=(-0.4 x+0.6 y) \Delta_{o}\) where, \(x\) and \(y\) are no. of electrons occupying \(t_{2 g}\) and es orbitals respectively. For \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) complex ion. \(\mathrm{Fe}^{3+}\left(3 d^{5}\right) =t_{2 \mathrm{g}}^{3} e_{\mathrm{g}}^{2}=-0.4 \times 3+0.6 \times 2\) \(=0.0 \text { or } 0\; \mathrm{Dq}\)
COORDINATION COMPOUNDS
28857
Which of the following complexes is used to be as an anticancer agent?
1 \(mer-[Co(NH_3)_3Cl_3]\)
2 \(cis-[PtCl_2(NH_3)_2]\)
3 \(cis-K_2[PtCl_2Br_2]\)
4 \(Na_2CoCl_4\)
Explanation:
Cis-platin is known as anticancer agent. The formula of cis-platin is \(c i s-\left[P t C l_{2}\left(N H_{3}\right)_{2}\right] .\) Here, the word \(c\) is refers to geometrical isomer of \(\left[P t C l_{2}(N H_3)_{2}\right] .\) It is used as an antitumour agent.
