(b) The compound which has same composition but give different ions in solution, show ionization. So \([Co{(N{H_3})_5}Br]\)\(SO_4^{}\) is ionization isomer. \([Co{(N{H_3})_5}Br]S{O_4}\)\( \rightleftharpoons \) \({[Co{(N{H_3})_5}Br]^{2 + }} + SO_4^{2 - }\) \([Co{(N{H_3})_5}S{O_4}]Br\)\( \rightleftharpoons \) \({[Co(N{H_3})S{O_4}]^ + } + B{r^ - }\).
COORDINATION COMPOUNDS
28678
\({[Ti{({H_2}O)_6}]^{ + 3}}\) is paramagnetic in nature due to
1 One unpaired \({e^ - }\)
2 Two unpaired \({e^ - }\)
3 Three unpaired \({e^ - }\)
4 No unpaired \({e^ - }\)
Explanation:
\(T i^{3+}\) ion has \(d\) electrons and is paramagnetic in nature.
(b) The compound which has same composition but give different ions in solution, show ionization. So \([Co{(N{H_3})_5}Br]\)\(SO_4^{}\) is ionization isomer. \([Co{(N{H_3})_5}Br]S{O_4}\)\( \rightleftharpoons \) \({[Co{(N{H_3})_5}Br]^{2 + }} + SO_4^{2 - }\) \([Co{(N{H_3})_5}S{O_4}]Br\)\( \rightleftharpoons \) \({[Co(N{H_3})S{O_4}]^ + } + B{r^ - }\).
COORDINATION COMPOUNDS
28678
\({[Ti{({H_2}O)_6}]^{ + 3}}\) is paramagnetic in nature due to
1 One unpaired \({e^ - }\)
2 Two unpaired \({e^ - }\)
3 Three unpaired \({e^ - }\)
4 No unpaired \({e^ - }\)
Explanation:
\(T i^{3+}\) ion has \(d\) electrons and is paramagnetic in nature.
(b) The compound which has same composition but give different ions in solution, show ionization. So \([Co{(N{H_3})_5}Br]\)\(SO_4^{}\) is ionization isomer. \([Co{(N{H_3})_5}Br]S{O_4}\)\( \rightleftharpoons \) \({[Co{(N{H_3})_5}Br]^{2 + }} + SO_4^{2 - }\) \([Co{(N{H_3})_5}S{O_4}]Br\)\( \rightleftharpoons \) \({[Co(N{H_3})S{O_4}]^ + } + B{r^ - }\).
COORDINATION COMPOUNDS
28678
\({[Ti{({H_2}O)_6}]^{ + 3}}\) is paramagnetic in nature due to
1 One unpaired \({e^ - }\)
2 Two unpaired \({e^ - }\)
3 Three unpaired \({e^ - }\)
4 No unpaired \({e^ - }\)
Explanation:
\(T i^{3+}\) ion has \(d\) electrons and is paramagnetic in nature.
(b) The compound which has same composition but give different ions in solution, show ionization. So \([Co{(N{H_3})_5}Br]\)\(SO_4^{}\) is ionization isomer. \([Co{(N{H_3})_5}Br]S{O_4}\)\( \rightleftharpoons \) \({[Co{(N{H_3})_5}Br]^{2 + }} + SO_4^{2 - }\) \([Co{(N{H_3})_5}S{O_4}]Br\)\( \rightleftharpoons \) \({[Co(N{H_3})S{O_4}]^ + } + B{r^ - }\).
COORDINATION COMPOUNDS
28678
\({[Ti{({H_2}O)_6}]^{ + 3}}\) is paramagnetic in nature due to
1 One unpaired \({e^ - }\)
2 Two unpaired \({e^ - }\)
3 Three unpaired \({e^ - }\)
4 No unpaired \({e^ - }\)
Explanation:
\(T i^{3+}\) ion has \(d\) electrons and is paramagnetic in nature.