Explanation:
(b) \(\frac{\text{weight}\,\text{of}\,Cu}{\text{weight}\,\text{of}\,{{H}_{2}}}=\) \(\frac{\text{Eq}.\,\text{weight}\,\text{of}\,Cu}{\text{Eq}.\,\text{weight}.\,\text{of}\,H}\)
\(\frac{{{\text{Weight}}{\mkern 1mu} {\mkern 1mu} \,{\text{of}}{\mkern 1mu} {\mkern 1mu} \,Cu}}{{0.50}} = \frac{{63.6/2}}{1}\)
\({\text{Weight}}{\mkern 1mu} {\mkern 1mu} {\text{of}}{\mkern 1mu} {\mkern 1mu} Cu = 15.9{\mkern 1mu} \,gm\)