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Ionic Equilibrium

32482 Which is not a electrophile

1

A l C l_{3}

2

B F_{3}

3

(C H_{3})_{3} C^{+}

4

N H_{3}

Explanation:

(d)Electron donating species called nucleophile. $N H_{3}$ have a lone pair of electron.

Ionic Equilibrium

32878 The $p H$ of $\frac{N}{100}$ $H C l$ would be approximately

1

1

2

1.5

3

2

4

2.5

Explanation:

(c) $0.01 M H C l = 10^{- 2} M [H^{+}], p H = 2$ .

Ionic Equilibrium

32480 The conjugate base of $N {H_{2}}^{-}$ is

1

N H_{3}

2

N H^{2 -}

3

N H_{4}^{+}

4

{N_{3}}^{-}

Explanation:

(b) $N H_{2}^{-}$ $⇌$ $N H^{- 2} + H^{+}$
Conjugate acid, base pair.

Ionic Equilibrium

32483 Ammonia gas dissolves in water to give $N H_{4} O H .$ In this reaction water acts as

1 An acid

2 A base

3 A salt

4 A conjugate base

Explanation:

(a) $H_{2} O$ acts as acid as it provides $H^{+}$ to $N H_{3}$ .

Ionic Equilibrium

32482 Which is not a electrophile

1

A l C l_{3}

2

B F_{3}

3

(C H_{3})_{3} C^{+}

4

N H_{3}

Explanation:

(d)Electron donating species called nucleophile. $N H_{3}$ have a lone pair of electron.

Ionic Equilibrium

32878 The $p H$ of $\frac{N}{100}$ $H C l$ would be approximately

1

1

2

1.5

3

2

4

2.5

Explanation:

(c) $0.01 M H C l = 10^{- 2} M [H^{+}], p H = 2$ .

Ionic Equilibrium

32480 The conjugate base of $N {H_{2}}^{-}$ is

1

N H_{3}

2

N H^{2 -}

3

N H_{4}^{+}

4

{N_{3}}^{-}

Explanation:

(b) $N H_{2}^{-}$ $⇌$ $N H^{- 2} + H^{+}$
Conjugate acid, base pair.

Ionic Equilibrium

32483 Ammonia gas dissolves in water to give $N H_{4} O H .$ In this reaction water acts as

1 An acid

2 A base

3 A salt

4 A conjugate base

Explanation:

(a) $H_{2} O$ acts as acid as it provides $H^{+}$ to $N H_{3}$ .

Ionic Equilibrium

32482 Which is not a electrophile

1

A l C l_{3}

2

B F_{3}

3

(C H_{3})_{3} C^{+}

4

N H_{3}

Explanation:

(d)Electron donating species called nucleophile. $N H_{3}$ have a lone pair of electron.

Ionic Equilibrium

32878 The $p H$ of $\frac{N}{100}$ $H C l$ would be approximately

1

1

2

1.5

3

2

4

2.5

Explanation:

(c) $0.01 M H C l = 10^{- 2} M [H^{+}], p H = 2$ .

Ionic Equilibrium

32480 The conjugate base of $N {H_{2}}^{-}$ is

1

N H_{3}

2

N H^{2 -}

3

N H_{4}^{+}

4

{N_{3}}^{-}

Explanation:

(b) $N H_{2}^{-}$ $⇌$ $N H^{- 2} + H^{+}$
Conjugate acid, base pair.

Ionic Equilibrium

32483 Ammonia gas dissolves in water to give $N H_{4} O H .$ In this reaction water acts as

1 An acid

2 A base

3 A salt

4 A conjugate base

Explanation:

(a) $H_{2} O$ acts as acid as it provides $H^{+}$ to $N H_{3}$ .

Ionic Equilibrium

32482 Which is not a electrophile

1

A l C l_{3}

2

B F_{3}

3

(C H_{3})_{3} C^{+}

4

N H_{3}

Explanation:

(d)Electron donating species called nucleophile. $N H_{3}$ have a lone pair of electron.

Ionic Equilibrium

32878 The $p H$ of $\frac{N}{100}$ $H C l$ would be approximately

1

1

2

1.5

3

2

4

2.5

Explanation:

(c) $0.01 M H C l = 10^{- 2} M [H^{+}], p H = 2$ .

Ionic Equilibrium

32480 The conjugate base of $N {H_{2}}^{-}$ is

1

N H_{3}

2

N H^{2 -}

3

N H_{4}^{+}

4

{N_{3}}^{-}

Explanation:

(b) $N H_{2}^{-}$ $⇌$ $N H^{- 2} + H^{+}$
Conjugate acid, base pair.

Ionic Equilibrium

32483 Ammonia gas dissolves in water to give $N H_{4} O H .$ In this reaction water acts as

1 An acid

2 A base

3 A salt

4 A conjugate base

Explanation:

(a) $H_{2} O$ acts as acid as it provides $H^{+}$ to $N H_{3}$ .