\(H _2+ I _2=2 HI\) \(K _{ C }\) for a reaction \(aA + bB \rightleftharpoons cC + dD\) \(\Rightarrow \frac{[ C ]^{ c }[ D ]^{ d }}{[ A ]^{ a }[ B ]^{ b }}\) So here \(K _{ C }=\frac{[ HI ]^2}{\left[ H _2\right]\left[ I _2\right]}\)
Chemical Equilibrium
33476
Partial pressures of \(A\), \(B\), \(C\) and \(D\) on the basis of gaseous system \(A + 2B\) \(\rightleftharpoons\) \(C + 3D\) are \(A = 0.20\); \( B = 0.10\); \(C = 0.30\) and \(D = 0.50\, atm\). The numerical value of equilibrium constant is
33477
For the reaction \(A + 2B\) \(\rightleftharpoons\) \(C\), the expression for equilibrium constant is
1 \(\frac{{[A]{{[B]}^2}}}{{[C]}}\)
2 \(\frac{{[A][B]}}{{[C]}}\)
3 \(\frac{{[C]}}{{[A]{{[B]}^2}}}\)
4 \(\frac{{[C]}}{{2[B][A]}}\)
Explanation:
Equilibrium constants for this reaction is \(\frac{[ C ]}{[ A ][ B ]^2}\)
Chemical Equilibrium
33478
\(2\) moles of \(PC{l_5}\) were heated in a closed vessel of \(2\) litre capacity. At equilibrium, \(40\%\) of \(PC{l_5}\) is dissociated into \(PC{l_3}\) and \(C{l_2}\). The value of equilibrium constant is
\(H _2+ I _2=2 HI\) \(K _{ C }\) for a reaction \(aA + bB \rightleftharpoons cC + dD\) \(\Rightarrow \frac{[ C ]^{ c }[ D ]^{ d }}{[ A ]^{ a }[ B ]^{ b }}\) So here \(K _{ C }=\frac{[ HI ]^2}{\left[ H _2\right]\left[ I _2\right]}\)
Chemical Equilibrium
33476
Partial pressures of \(A\), \(B\), \(C\) and \(D\) on the basis of gaseous system \(A + 2B\) \(\rightleftharpoons\) \(C + 3D\) are \(A = 0.20\); \( B = 0.10\); \(C = 0.30\) and \(D = 0.50\, atm\). The numerical value of equilibrium constant is
33477
For the reaction \(A + 2B\) \(\rightleftharpoons\) \(C\), the expression for equilibrium constant is
1 \(\frac{{[A]{{[B]}^2}}}{{[C]}}\)
2 \(\frac{{[A][B]}}{{[C]}}\)
3 \(\frac{{[C]}}{{[A]{{[B]}^2}}}\)
4 \(\frac{{[C]}}{{2[B][A]}}\)
Explanation:
Equilibrium constants for this reaction is \(\frac{[ C ]}{[ A ][ B ]^2}\)
Chemical Equilibrium
33478
\(2\) moles of \(PC{l_5}\) were heated in a closed vessel of \(2\) litre capacity. At equilibrium, \(40\%\) of \(PC{l_5}\) is dissociated into \(PC{l_3}\) and \(C{l_2}\). The value of equilibrium constant is
\(H _2+ I _2=2 HI\) \(K _{ C }\) for a reaction \(aA + bB \rightleftharpoons cC + dD\) \(\Rightarrow \frac{[ C ]^{ c }[ D ]^{ d }}{[ A ]^{ a }[ B ]^{ b }}\) So here \(K _{ C }=\frac{[ HI ]^2}{\left[ H _2\right]\left[ I _2\right]}\)
Chemical Equilibrium
33476
Partial pressures of \(A\), \(B\), \(C\) and \(D\) on the basis of gaseous system \(A + 2B\) \(\rightleftharpoons\) \(C + 3D\) are \(A = 0.20\); \( B = 0.10\); \(C = 0.30\) and \(D = 0.50\, atm\). The numerical value of equilibrium constant is
33477
For the reaction \(A + 2B\) \(\rightleftharpoons\) \(C\), the expression for equilibrium constant is
1 \(\frac{{[A]{{[B]}^2}}}{{[C]}}\)
2 \(\frac{{[A][B]}}{{[C]}}\)
3 \(\frac{{[C]}}{{[A]{{[B]}^2}}}\)
4 \(\frac{{[C]}}{{2[B][A]}}\)
Explanation:
Equilibrium constants for this reaction is \(\frac{[ C ]}{[ A ][ B ]^2}\)
Chemical Equilibrium
33478
\(2\) moles of \(PC{l_5}\) were heated in a closed vessel of \(2\) litre capacity. At equilibrium, \(40\%\) of \(PC{l_5}\) is dissociated into \(PC{l_3}\) and \(C{l_2}\). The value of equilibrium constant is
\(H _2+ I _2=2 HI\) \(K _{ C }\) for a reaction \(aA + bB \rightleftharpoons cC + dD\) \(\Rightarrow \frac{[ C ]^{ c }[ D ]^{ d }}{[ A ]^{ a }[ B ]^{ b }}\) So here \(K _{ C }=\frac{[ HI ]^2}{\left[ H _2\right]\left[ I _2\right]}\)
Chemical Equilibrium
33476
Partial pressures of \(A\), \(B\), \(C\) and \(D\) on the basis of gaseous system \(A + 2B\) \(\rightleftharpoons\) \(C + 3D\) are \(A = 0.20\); \( B = 0.10\); \(C = 0.30\) and \(D = 0.50\, atm\). The numerical value of equilibrium constant is
33477
For the reaction \(A + 2B\) \(\rightleftharpoons\) \(C\), the expression for equilibrium constant is
1 \(\frac{{[A]{{[B]}^2}}}{{[C]}}\)
2 \(\frac{{[A][B]}}{{[C]}}\)
3 \(\frac{{[C]}}{{[A]{{[B]}^2}}}\)
4 \(\frac{{[C]}}{{2[B][A]}}\)
Explanation:
Equilibrium constants for this reaction is \(\frac{[ C ]}{[ A ][ B ]^2}\)
Chemical Equilibrium
33478
\(2\) moles of \(PC{l_5}\) were heated in a closed vessel of \(2\) litre capacity. At equilibrium, \(40\%\) of \(PC{l_5}\) is dissociated into \(PC{l_3}\) and \(C{l_2}\). The value of equilibrium constant is
\(H _2+ I _2=2 HI\) \(K _{ C }\) for a reaction \(aA + bB \rightleftharpoons cC + dD\) \(\Rightarrow \frac{[ C ]^{ c }[ D ]^{ d }}{[ A ]^{ a }[ B ]^{ b }}\) So here \(K _{ C }=\frac{[ HI ]^2}{\left[ H _2\right]\left[ I _2\right]}\)
Chemical Equilibrium
33476
Partial pressures of \(A\), \(B\), \(C\) and \(D\) on the basis of gaseous system \(A + 2B\) \(\rightleftharpoons\) \(C + 3D\) are \(A = 0.20\); \( B = 0.10\); \(C = 0.30\) and \(D = 0.50\, atm\). The numerical value of equilibrium constant is
33477
For the reaction \(A + 2B\) \(\rightleftharpoons\) \(C\), the expression for equilibrium constant is
1 \(\frac{{[A]{{[B]}^2}}}{{[C]}}\)
2 \(\frac{{[A][B]}}{{[C]}}\)
3 \(\frac{{[C]}}{{[A]{{[B]}^2}}}\)
4 \(\frac{{[C]}}{{2[B][A]}}\)
Explanation:
Equilibrium constants for this reaction is \(\frac{[ C ]}{[ A ][ B ]^2}\)
Chemical Equilibrium
33478
\(2\) moles of \(PC{l_5}\) were heated in a closed vessel of \(2\) litre capacity. At equilibrium, \(40\%\) of \(PC{l_5}\) is dissociated into \(PC{l_3}\) and \(C{l_2}\). The value of equilibrium constant is