12704
Which of the following molecular orbital has two nodal planes
1 \({\sigma _{1s}}\)
2 \(\sigma _{2s}^*\)
3 \({\sigma _{2pz}}\)
4 \(\pi _{2px}^*\)
Explanation:
Chemical Bonding and Molecular Structure
11939
As compared to covalent compounds, electrovalent compounds generally have
1 Low melting points and low boiling points
2 Low melting points and high boiling points
3 High melting points and low boiling points
4 High melting points and high boiling points
Explanation:
(d) Electrovalent compounds have high melting point and high boiling point.
Chemical Bonding and Molecular Structure
11940
The interatomic distances in \({H_2}\) and \(C{l_2}\) molecules are \(74\) and \(198\) \(pm\) respectively. The bond length of \(HCl\) is ............. \(\mathrm{pm}\)
1 \(272\)
2 \(136\)
3 \(124\)
4 \(248\)
Explanation:
(b) Middle length of \({H_2} = 74\,pm\) Length of \(H = \frac{{74}}{2} = 37pm\) Middle length of \(C{l_2} = 198\,pm \) Length of \(Cl\)\( = \frac{{198}}{2} = 99\,pm\) Bond length of \(HCl\) = Length of \(H +\) Length of \(Cl = 37 + 99 = 136 \,pm\)
12704
Which of the following molecular orbital has two nodal planes
1 \({\sigma _{1s}}\)
2 \(\sigma _{2s}^*\)
3 \({\sigma _{2pz}}\)
4 \(\pi _{2px}^*\)
Explanation:
Chemical Bonding and Molecular Structure
11939
As compared to covalent compounds, electrovalent compounds generally have
1 Low melting points and low boiling points
2 Low melting points and high boiling points
3 High melting points and low boiling points
4 High melting points and high boiling points
Explanation:
(d) Electrovalent compounds have high melting point and high boiling point.
Chemical Bonding and Molecular Structure
11940
The interatomic distances in \({H_2}\) and \(C{l_2}\) molecules are \(74\) and \(198\) \(pm\) respectively. The bond length of \(HCl\) is ............. \(\mathrm{pm}\)
1 \(272\)
2 \(136\)
3 \(124\)
4 \(248\)
Explanation:
(b) Middle length of \({H_2} = 74\,pm\) Length of \(H = \frac{{74}}{2} = 37pm\) Middle length of \(C{l_2} = 198\,pm \) Length of \(Cl\)\( = \frac{{198}}{2} = 99\,pm\) Bond length of \(HCl\) = Length of \(H +\) Length of \(Cl = 37 + 99 = 136 \,pm\)
12704
Which of the following molecular orbital has two nodal planes
1 \({\sigma _{1s}}\)
2 \(\sigma _{2s}^*\)
3 \({\sigma _{2pz}}\)
4 \(\pi _{2px}^*\)
Explanation:
Chemical Bonding and Molecular Structure
11939
As compared to covalent compounds, electrovalent compounds generally have
1 Low melting points and low boiling points
2 Low melting points and high boiling points
3 High melting points and low boiling points
4 High melting points and high boiling points
Explanation:
(d) Electrovalent compounds have high melting point and high boiling point.
Chemical Bonding and Molecular Structure
11940
The interatomic distances in \({H_2}\) and \(C{l_2}\) molecules are \(74\) and \(198\) \(pm\) respectively. The bond length of \(HCl\) is ............. \(\mathrm{pm}\)
1 \(272\)
2 \(136\)
3 \(124\)
4 \(248\)
Explanation:
(b) Middle length of \({H_2} = 74\,pm\) Length of \(H = \frac{{74}}{2} = 37pm\) Middle length of \(C{l_2} = 198\,pm \) Length of \(Cl\)\( = \frac{{198}}{2} = 99\,pm\) Bond length of \(HCl\) = Length of \(H +\) Length of \(Cl = 37 + 99 = 136 \,pm\)
12704
Which of the following molecular orbital has two nodal planes
1 \({\sigma _{1s}}\)
2 \(\sigma _{2s}^*\)
3 \({\sigma _{2pz}}\)
4 \(\pi _{2px}^*\)
Explanation:
Chemical Bonding and Molecular Structure
11939
As compared to covalent compounds, electrovalent compounds generally have
1 Low melting points and low boiling points
2 Low melting points and high boiling points
3 High melting points and low boiling points
4 High melting points and high boiling points
Explanation:
(d) Electrovalent compounds have high melting point and high boiling point.
Chemical Bonding and Molecular Structure
11940
The interatomic distances in \({H_2}\) and \(C{l_2}\) molecules are \(74\) and \(198\) \(pm\) respectively. The bond length of \(HCl\) is ............. \(\mathrm{pm}\)
1 \(272\)
2 \(136\)
3 \(124\)
4 \(248\)
Explanation:
(b) Middle length of \({H_2} = 74\,pm\) Length of \(H = \frac{{74}}{2} = 37pm\) Middle length of \(C{l_2} = 198\,pm \) Length of \(Cl\)\( = \frac{{198}}{2} = 99\,pm\) Bond length of \(HCl\) = Length of \(H +\) Length of \(Cl = 37 + 99 = 136 \,pm\)