37494
The strength of a solution \((S)\) in gram/litre, is related to its normality \((N)\) and equivalent weight of solute
1 by the formula
2 \(S = \frac{N}{E}\)
3 \(S = \frac{E}{N}\)
4 \(S = N.E\)
Explanation:
(c) \({\rm{Strength}} = \frac{W}{V} = NE\)
PRACTICAL CHEMISTRY
37495
The normality of \(1\,M\) solution of \({H_3}P{O_4}\) will be.....\(N\)
1 \(1\)
2 \(0.5\)
3 \(2\)
4 \(3\)
Explanation:
(d) As \({H_3}P{O_4}\) can donate \(3{H^ + }\) in the solution, as a result the normality of solution is \(3\,N\), as Molarity $×$ basicity = Normality
PRACTICAL CHEMISTRY
37514
Solubility of iodine in water may be increased by adding
1 Chloroform
2 Potassium iodide
3 Carbon disulphate
4 Sodium Thiosulphate
Explanation:
(b)The solubility of \(I_2\) in water increases by the addition of \(KI\) due to ormation of polyhaldie ion, i.e., \(I_3^ - \) \(KI + {I_2} \to K{I_3}\)
PRACTICAL CHEMISTRY
37496
In the reaction \({I_2} + 2{S_2}O_3^ - \to 2{I^ - } + {S_4}O_6^{2 - };\) the equivalent weight of iodine will be equal to
37494
The strength of a solution \((S)\) in gram/litre, is related to its normality \((N)\) and equivalent weight of solute
1 by the formula
2 \(S = \frac{N}{E}\)
3 \(S = \frac{E}{N}\)
4 \(S = N.E\)
Explanation:
(c) \({\rm{Strength}} = \frac{W}{V} = NE\)
PRACTICAL CHEMISTRY
37495
The normality of \(1\,M\) solution of \({H_3}P{O_4}\) will be.....\(N\)
1 \(1\)
2 \(0.5\)
3 \(2\)
4 \(3\)
Explanation:
(d) As \({H_3}P{O_4}\) can donate \(3{H^ + }\) in the solution, as a result the normality of solution is \(3\,N\), as Molarity $×$ basicity = Normality
PRACTICAL CHEMISTRY
37514
Solubility of iodine in water may be increased by adding
1 Chloroform
2 Potassium iodide
3 Carbon disulphate
4 Sodium Thiosulphate
Explanation:
(b)The solubility of \(I_2\) in water increases by the addition of \(KI\) due to ormation of polyhaldie ion, i.e., \(I_3^ - \) \(KI + {I_2} \to K{I_3}\)
PRACTICAL CHEMISTRY
37496
In the reaction \({I_2} + 2{S_2}O_3^ - \to 2{I^ - } + {S_4}O_6^{2 - };\) the equivalent weight of iodine will be equal to
37494
The strength of a solution \((S)\) in gram/litre, is related to its normality \((N)\) and equivalent weight of solute
1 by the formula
2 \(S = \frac{N}{E}\)
3 \(S = \frac{E}{N}\)
4 \(S = N.E\)
Explanation:
(c) \({\rm{Strength}} = \frac{W}{V} = NE\)
PRACTICAL CHEMISTRY
37495
The normality of \(1\,M\) solution of \({H_3}P{O_4}\) will be.....\(N\)
1 \(1\)
2 \(0.5\)
3 \(2\)
4 \(3\)
Explanation:
(d) As \({H_3}P{O_4}\) can donate \(3{H^ + }\) in the solution, as a result the normality of solution is \(3\,N\), as Molarity $×$ basicity = Normality
PRACTICAL CHEMISTRY
37514
Solubility of iodine in water may be increased by adding
1 Chloroform
2 Potassium iodide
3 Carbon disulphate
4 Sodium Thiosulphate
Explanation:
(b)The solubility of \(I_2\) in water increases by the addition of \(KI\) due to ormation of polyhaldie ion, i.e., \(I_3^ - \) \(KI + {I_2} \to K{I_3}\)
PRACTICAL CHEMISTRY
37496
In the reaction \({I_2} + 2{S_2}O_3^ - \to 2{I^ - } + {S_4}O_6^{2 - };\) the equivalent weight of iodine will be equal to
37494
The strength of a solution \((S)\) in gram/litre, is related to its normality \((N)\) and equivalent weight of solute
1 by the formula
2 \(S = \frac{N}{E}\)
3 \(S = \frac{E}{N}\)
4 \(S = N.E\)
Explanation:
(c) \({\rm{Strength}} = \frac{W}{V} = NE\)
PRACTICAL CHEMISTRY
37495
The normality of \(1\,M\) solution of \({H_3}P{O_4}\) will be.....\(N\)
1 \(1\)
2 \(0.5\)
3 \(2\)
4 \(3\)
Explanation:
(d) As \({H_3}P{O_4}\) can donate \(3{H^ + }\) in the solution, as a result the normality of solution is \(3\,N\), as Molarity $×$ basicity = Normality
PRACTICAL CHEMISTRY
37514
Solubility of iodine in water may be increased by adding
1 Chloroform
2 Potassium iodide
3 Carbon disulphate
4 Sodium Thiosulphate
Explanation:
(b)The solubility of \(I_2\) in water increases by the addition of \(KI\) due to ormation of polyhaldie ion, i.e., \(I_3^ - \) \(KI + {I_2} \to K{I_3}\)
PRACTICAL CHEMISTRY
37496
In the reaction \({I_2} + 2{S_2}O_3^ - \to 2{I^ - } + {S_4}O_6^{2 - };\) the equivalent weight of iodine will be equal to
