Explanation:
(a) \(BaC{O_3} \to BaO + C{O_2} \uparrow \)
\(\therefore 197\,gm\,\,BaC{O_3}\) on decompose gives \(= 22.4\) litre \(C{O_2}\)
\(\therefore 1\,gm\,\,BaC{O_3}\) will give = \(\frac{{22.4}}{{197}} = litre\,\,C{O_2}\)
\( = \frac{{22.4 \times 9.85}}{{197}} = 1.12\,\,litre\,\,C{O_2}\)