37468
\(2\,N - HCl\) will have the same molar concentration as.......\(N - {H_2}S{O_4}\)
1 \(0.5\)
2 \(1\)
3 \(2\)
4 \(4 \)
Explanation:
It’s obvious.
PRACTICAL CHEMISTRY
37469
Which of the following pair does not distinguish by passing \({H_2}S\)
1 \(Hg,\) \(Pb\)
2 \(Cd,\)\(Pb\)
3 \(As,\) \(Cu\)
4 \(Zn,\) \(Mn\)
Explanation:
Both \(Hg ^{+2}\) and \(Pb ^{+2}\) give black ppt. with \(H _2S\) in group \(IIA\).
PRACTICAL CHEMISTRY
37470
If \(100\, ml\) of \(1 \,N\) sulphuric acid were mixed with \(100\, ml\) of \(1 \,M\) sodium hydroxide, the solution will be
1 \(Acidic\)
2 \(Basic\)
3 \(Neutral\)
4 \(Slightly \,acidic\)
Explanation:
The complete neutralization of a strong acid ( \(H _2 SO _4\) ) and strong base ( \(NaOH\) ) has a \(pH\) equal to \(7\).
PRACTICAL CHEMISTRY
37471
\(100\) \(c{m^3}\) of \(0.1 \,N\) \(HCl\) solution is mixed with \(100\) \(c{m^3}\) of \( 0.2\, N\) \(NaOH\) solution. The resulting solution is
1 \(0.1 \,N\) and the solution is basic
2 \(0.05 \,N\) and the solution is basic
3 \(0.1 \,N\) and the solution is acidic
4 \(0.05 \,N\) and the solution is acidic
Explanation:
(b) Acid = \(0.1 \times 100 = 10\) Base = \(0.2 \times 100 = 20\) solution will be basic. \(0.1\,N\) of \(HCl\) is neutralised by \(0.1 \,N\) of \(NaOH\) and the remaining \(0.1\,N\) of \(NaOH\) is in \(200\) \(c{m^3}\)of solution. resulting normality = \(0.05 \,N\), basic.
PRACTICAL CHEMISTRY
37472
For preparing \(0.1 \,N\) solution of a compound from its impure sample, of which the percentage purity is known, the weight of the substance required will be
1 Less than the theoretical weight
2 More than the theoretical weight
3 Same as theoretical weight
4 None of these
Explanation:
The sample contains impurity. The impurity won't contribute to the normality of the solution. So, we need to take more amount of sample than the theoretical weight so that the theoretical weight of compound equals weight of compound in the sample.
37468
\(2\,N - HCl\) will have the same molar concentration as.......\(N - {H_2}S{O_4}\)
1 \(0.5\)
2 \(1\)
3 \(2\)
4 \(4 \)
Explanation:
It’s obvious.
PRACTICAL CHEMISTRY
37469
Which of the following pair does not distinguish by passing \({H_2}S\)
1 \(Hg,\) \(Pb\)
2 \(Cd,\)\(Pb\)
3 \(As,\) \(Cu\)
4 \(Zn,\) \(Mn\)
Explanation:
Both \(Hg ^{+2}\) and \(Pb ^{+2}\) give black ppt. with \(H _2S\) in group \(IIA\).
PRACTICAL CHEMISTRY
37470
If \(100\, ml\) of \(1 \,N\) sulphuric acid were mixed with \(100\, ml\) of \(1 \,M\) sodium hydroxide, the solution will be
1 \(Acidic\)
2 \(Basic\)
3 \(Neutral\)
4 \(Slightly \,acidic\)
Explanation:
The complete neutralization of a strong acid ( \(H _2 SO _4\) ) and strong base ( \(NaOH\) ) has a \(pH\) equal to \(7\).
PRACTICAL CHEMISTRY
37471
\(100\) \(c{m^3}\) of \(0.1 \,N\) \(HCl\) solution is mixed with \(100\) \(c{m^3}\) of \( 0.2\, N\) \(NaOH\) solution. The resulting solution is
1 \(0.1 \,N\) and the solution is basic
2 \(0.05 \,N\) and the solution is basic
3 \(0.1 \,N\) and the solution is acidic
4 \(0.05 \,N\) and the solution is acidic
Explanation:
(b) Acid = \(0.1 \times 100 = 10\) Base = \(0.2 \times 100 = 20\) solution will be basic. \(0.1\,N\) of \(HCl\) is neutralised by \(0.1 \,N\) of \(NaOH\) and the remaining \(0.1\,N\) of \(NaOH\) is in \(200\) \(c{m^3}\)of solution. resulting normality = \(0.05 \,N\), basic.
PRACTICAL CHEMISTRY
37472
For preparing \(0.1 \,N\) solution of a compound from its impure sample, of which the percentage purity is known, the weight of the substance required will be
1 Less than the theoretical weight
2 More than the theoretical weight
3 Same as theoretical weight
4 None of these
Explanation:
The sample contains impurity. The impurity won't contribute to the normality of the solution. So, we need to take more amount of sample than the theoretical weight so that the theoretical weight of compound equals weight of compound in the sample.
37468
\(2\,N - HCl\) will have the same molar concentration as.......\(N - {H_2}S{O_4}\)
1 \(0.5\)
2 \(1\)
3 \(2\)
4 \(4 \)
Explanation:
It’s obvious.
PRACTICAL CHEMISTRY
37469
Which of the following pair does not distinguish by passing \({H_2}S\)
1 \(Hg,\) \(Pb\)
2 \(Cd,\)\(Pb\)
3 \(As,\) \(Cu\)
4 \(Zn,\) \(Mn\)
Explanation:
Both \(Hg ^{+2}\) and \(Pb ^{+2}\) give black ppt. with \(H _2S\) in group \(IIA\).
PRACTICAL CHEMISTRY
37470
If \(100\, ml\) of \(1 \,N\) sulphuric acid were mixed with \(100\, ml\) of \(1 \,M\) sodium hydroxide, the solution will be
1 \(Acidic\)
2 \(Basic\)
3 \(Neutral\)
4 \(Slightly \,acidic\)
Explanation:
The complete neutralization of a strong acid ( \(H _2 SO _4\) ) and strong base ( \(NaOH\) ) has a \(pH\) equal to \(7\).
PRACTICAL CHEMISTRY
37471
\(100\) \(c{m^3}\) of \(0.1 \,N\) \(HCl\) solution is mixed with \(100\) \(c{m^3}\) of \( 0.2\, N\) \(NaOH\) solution. The resulting solution is
1 \(0.1 \,N\) and the solution is basic
2 \(0.05 \,N\) and the solution is basic
3 \(0.1 \,N\) and the solution is acidic
4 \(0.05 \,N\) and the solution is acidic
Explanation:
(b) Acid = \(0.1 \times 100 = 10\) Base = \(0.2 \times 100 = 20\) solution will be basic. \(0.1\,N\) of \(HCl\) is neutralised by \(0.1 \,N\) of \(NaOH\) and the remaining \(0.1\,N\) of \(NaOH\) is in \(200\) \(c{m^3}\)of solution. resulting normality = \(0.05 \,N\), basic.
PRACTICAL CHEMISTRY
37472
For preparing \(0.1 \,N\) solution of a compound from its impure sample, of which the percentage purity is known, the weight of the substance required will be
1 Less than the theoretical weight
2 More than the theoretical weight
3 Same as theoretical weight
4 None of these
Explanation:
The sample contains impurity. The impurity won't contribute to the normality of the solution. So, we need to take more amount of sample than the theoretical weight so that the theoretical weight of compound equals weight of compound in the sample.
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PRACTICAL CHEMISTRY
37468
\(2\,N - HCl\) will have the same molar concentration as.......\(N - {H_2}S{O_4}\)
1 \(0.5\)
2 \(1\)
3 \(2\)
4 \(4 \)
Explanation:
It’s obvious.
PRACTICAL CHEMISTRY
37469
Which of the following pair does not distinguish by passing \({H_2}S\)
1 \(Hg,\) \(Pb\)
2 \(Cd,\)\(Pb\)
3 \(As,\) \(Cu\)
4 \(Zn,\) \(Mn\)
Explanation:
Both \(Hg ^{+2}\) and \(Pb ^{+2}\) give black ppt. with \(H _2S\) in group \(IIA\).
PRACTICAL CHEMISTRY
37470
If \(100\, ml\) of \(1 \,N\) sulphuric acid were mixed with \(100\, ml\) of \(1 \,M\) sodium hydroxide, the solution will be
1 \(Acidic\)
2 \(Basic\)
3 \(Neutral\)
4 \(Slightly \,acidic\)
Explanation:
The complete neutralization of a strong acid ( \(H _2 SO _4\) ) and strong base ( \(NaOH\) ) has a \(pH\) equal to \(7\).
PRACTICAL CHEMISTRY
37471
\(100\) \(c{m^3}\) of \(0.1 \,N\) \(HCl\) solution is mixed with \(100\) \(c{m^3}\) of \( 0.2\, N\) \(NaOH\) solution. The resulting solution is
1 \(0.1 \,N\) and the solution is basic
2 \(0.05 \,N\) and the solution is basic
3 \(0.1 \,N\) and the solution is acidic
4 \(0.05 \,N\) and the solution is acidic
Explanation:
(b) Acid = \(0.1 \times 100 = 10\) Base = \(0.2 \times 100 = 20\) solution will be basic. \(0.1\,N\) of \(HCl\) is neutralised by \(0.1 \,N\) of \(NaOH\) and the remaining \(0.1\,N\) of \(NaOH\) is in \(200\) \(c{m^3}\)of solution. resulting normality = \(0.05 \,N\), basic.
PRACTICAL CHEMISTRY
37472
For preparing \(0.1 \,N\) solution of a compound from its impure sample, of which the percentage purity is known, the weight of the substance required will be
1 Less than the theoretical weight
2 More than the theoretical weight
3 Same as theoretical weight
4 None of these
Explanation:
The sample contains impurity. The impurity won't contribute to the normality of the solution. So, we need to take more amount of sample than the theoretical weight so that the theoretical weight of compound equals weight of compound in the sample.
37468
\(2\,N - HCl\) will have the same molar concentration as.......\(N - {H_2}S{O_4}\)
1 \(0.5\)
2 \(1\)
3 \(2\)
4 \(4 \)
Explanation:
It’s obvious.
PRACTICAL CHEMISTRY
37469
Which of the following pair does not distinguish by passing \({H_2}S\)
1 \(Hg,\) \(Pb\)
2 \(Cd,\)\(Pb\)
3 \(As,\) \(Cu\)
4 \(Zn,\) \(Mn\)
Explanation:
Both \(Hg ^{+2}\) and \(Pb ^{+2}\) give black ppt. with \(H _2S\) in group \(IIA\).
PRACTICAL CHEMISTRY
37470
If \(100\, ml\) of \(1 \,N\) sulphuric acid were mixed with \(100\, ml\) of \(1 \,M\) sodium hydroxide, the solution will be
1 \(Acidic\)
2 \(Basic\)
3 \(Neutral\)
4 \(Slightly \,acidic\)
Explanation:
The complete neutralization of a strong acid ( \(H _2 SO _4\) ) and strong base ( \(NaOH\) ) has a \(pH\) equal to \(7\).
PRACTICAL CHEMISTRY
37471
\(100\) \(c{m^3}\) of \(0.1 \,N\) \(HCl\) solution is mixed with \(100\) \(c{m^3}\) of \( 0.2\, N\) \(NaOH\) solution. The resulting solution is
1 \(0.1 \,N\) and the solution is basic
2 \(0.05 \,N\) and the solution is basic
3 \(0.1 \,N\) and the solution is acidic
4 \(0.05 \,N\) and the solution is acidic
Explanation:
(b) Acid = \(0.1 \times 100 = 10\) Base = \(0.2 \times 100 = 20\) solution will be basic. \(0.1\,N\) of \(HCl\) is neutralised by \(0.1 \,N\) of \(NaOH\) and the remaining \(0.1\,N\) of \(NaOH\) is in \(200\) \(c{m^3}\)of solution. resulting normality = \(0.05 \,N\), basic.
PRACTICAL CHEMISTRY
37472
For preparing \(0.1 \,N\) solution of a compound from its impure sample, of which the percentage purity is known, the weight of the substance required will be
1 Less than the theoretical weight
2 More than the theoretical weight
3 Same as theoretical weight
4 None of these
Explanation:
The sample contains impurity. The impurity won't contribute to the normality of the solution. So, we need to take more amount of sample than the theoretical weight so that the theoretical weight of compound equals weight of compound in the sample.