PRACTICAL CHEMISTRY
37460
The equivalent weight of a divalent metal is \(31.82\). The weight of a single atom is
1 \(63.64\)
2 \(\frac{{63.64}}{{6.02 \times {{10}^{23}}}}\)
3 \(32.77 \times 6.02 \times {10^{23}}\)
4 \(63.64 \times 6.02 \times {10^{23}}\)
Explanation:
(b)\(2 \times 31.82\),
\(\therefore \)wt of one atom \( = \frac{{2 \times 31.82}}{N} = \frac{{63.64}}{N}\)