NEET Test Series from KOTA - 10 Papers In MS WORD
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PRACTICAL CHEMISTRY
37447
The equivalent weight of an acid is equal to
1 Molecular weight $×$ acidity
2 Molecular weight $×$ basicity
3 Molecular weight / basicity
4 Molecular weight / acidity
Explanation:
Equivalent mass of an acid is defined as the number of parts by mass of it which contains \(1.008\) parts by mass of replaceable hydrogen or it in the quantity of the acid by mass that supplies one mole of \(H^{+}\) ions. Eq. mass of acid \(=\frac{\text { Molecular mass of the acid }}{\text { Number of replaceable } H \text { atoms }}\) \(=\frac{\text { Molecular mass of the acid }}{\text { Basicity of the acid }}\)
PRACTICAL CHEMISTRY
37448
A metal oxide is reduced by heating it in a stream of hydrogen. It is found that after complete reduction, \(3.15\,g\) of the oxide have yielded \(1.05\) of the metal. We may deduce that
1 The eq. weight of the metal is \(8\)
2 The atomic weight of the metal is \(8\)
3 The atomic weight of the metal is \(4\)
4 The eq. weight of the metal is \(4\)
Explanation:
\(W _{ M }=\) Weight of metal \(W _{ O }=\) Weight of oxygen \(W _{ M }=\) Equilivalent weight of metal \(W _{ M }=1.05 \,g \quad W _{ O }=3.15-1.05=2.10\, g\) Now, \(E _{ M }=\frac{ W _{ M } \times 8}{ W _{ O }}=\frac{1.05 \times 8}{2.10}=4\) So the equivalent weight of the metal is \(4\).
PRACTICAL CHEMISTRY
37449
The molecular weight of a tribasic acid is \( M\). What will be its equivalent weight
1 \(\frac{M}{2}\)
2 \(M\)
3 \(\frac{M}{3}\)
4 \(\sqrt {\frac{M}{3}} \)
Explanation:
Given, the acid is tribase, let its formula by \(H _3 A\). \(H _3 A \rightarrow H ^{+}+ A ^{3-}\) Equivalent weight \(=\frac{\text { Molecular weight }}{\text { valency }}=\frac{M}{3}\)
PRACTICAL CHEMISTRY
37450
Which of the following plot represents the graph of \(pH \) against volume of alkali added in the titration of \(NaOH \) and \(HCl\)
1
2
3
4
Explanation:
\(pH\) first almost remins same than suddenly \(\uparrow\) and then become almost same.
37447
The equivalent weight of an acid is equal to
1 Molecular weight $×$ acidity
2 Molecular weight $×$ basicity
3 Molecular weight / basicity
4 Molecular weight / acidity
Explanation:
Equivalent mass of an acid is defined as the number of parts by mass of it which contains \(1.008\) parts by mass of replaceable hydrogen or it in the quantity of the acid by mass that supplies one mole of \(H^{+}\) ions. Eq. mass of acid \(=\frac{\text { Molecular mass of the acid }}{\text { Number of replaceable } H \text { atoms }}\) \(=\frac{\text { Molecular mass of the acid }}{\text { Basicity of the acid }}\)
PRACTICAL CHEMISTRY
37448
A metal oxide is reduced by heating it in a stream of hydrogen. It is found that after complete reduction, \(3.15\,g\) of the oxide have yielded \(1.05\) of the metal. We may deduce that
1 The eq. weight of the metal is \(8\)
2 The atomic weight of the metal is \(8\)
3 The atomic weight of the metal is \(4\)
4 The eq. weight of the metal is \(4\)
Explanation:
\(W _{ M }=\) Weight of metal \(W _{ O }=\) Weight of oxygen \(W _{ M }=\) Equilivalent weight of metal \(W _{ M }=1.05 \,g \quad W _{ O }=3.15-1.05=2.10\, g\) Now, \(E _{ M }=\frac{ W _{ M } \times 8}{ W _{ O }}=\frac{1.05 \times 8}{2.10}=4\) So the equivalent weight of the metal is \(4\).
PRACTICAL CHEMISTRY
37449
The molecular weight of a tribasic acid is \( M\). What will be its equivalent weight
1 \(\frac{M}{2}\)
2 \(M\)
3 \(\frac{M}{3}\)
4 \(\sqrt {\frac{M}{3}} \)
Explanation:
Given, the acid is tribase, let its formula by \(H _3 A\). \(H _3 A \rightarrow H ^{+}+ A ^{3-}\) Equivalent weight \(=\frac{\text { Molecular weight }}{\text { valency }}=\frac{M}{3}\)
PRACTICAL CHEMISTRY
37450
Which of the following plot represents the graph of \(pH \) against volume of alkali added in the titration of \(NaOH \) and \(HCl\)
1
2
3
4
Explanation:
\(pH\) first almost remins same than suddenly \(\uparrow\) and then become almost same.
37447
The equivalent weight of an acid is equal to
1 Molecular weight $×$ acidity
2 Molecular weight $×$ basicity
3 Molecular weight / basicity
4 Molecular weight / acidity
Explanation:
Equivalent mass of an acid is defined as the number of parts by mass of it which contains \(1.008\) parts by mass of replaceable hydrogen or it in the quantity of the acid by mass that supplies one mole of \(H^{+}\) ions. Eq. mass of acid \(=\frac{\text { Molecular mass of the acid }}{\text { Number of replaceable } H \text { atoms }}\) \(=\frac{\text { Molecular mass of the acid }}{\text { Basicity of the acid }}\)
PRACTICAL CHEMISTRY
37448
A metal oxide is reduced by heating it in a stream of hydrogen. It is found that after complete reduction, \(3.15\,g\) of the oxide have yielded \(1.05\) of the metal. We may deduce that
1 The eq. weight of the metal is \(8\)
2 The atomic weight of the metal is \(8\)
3 The atomic weight of the metal is \(4\)
4 The eq. weight of the metal is \(4\)
Explanation:
\(W _{ M }=\) Weight of metal \(W _{ O }=\) Weight of oxygen \(W _{ M }=\) Equilivalent weight of metal \(W _{ M }=1.05 \,g \quad W _{ O }=3.15-1.05=2.10\, g\) Now, \(E _{ M }=\frac{ W _{ M } \times 8}{ W _{ O }}=\frac{1.05 \times 8}{2.10}=4\) So the equivalent weight of the metal is \(4\).
PRACTICAL CHEMISTRY
37449
The molecular weight of a tribasic acid is \( M\). What will be its equivalent weight
1 \(\frac{M}{2}\)
2 \(M\)
3 \(\frac{M}{3}\)
4 \(\sqrt {\frac{M}{3}} \)
Explanation:
Given, the acid is tribase, let its formula by \(H _3 A\). \(H _3 A \rightarrow H ^{+}+ A ^{3-}\) Equivalent weight \(=\frac{\text { Molecular weight }}{\text { valency }}=\frac{M}{3}\)
PRACTICAL CHEMISTRY
37450
Which of the following plot represents the graph of \(pH \) against volume of alkali added in the titration of \(NaOH \) and \(HCl\)
1
2
3
4
Explanation:
\(pH\) first almost remins same than suddenly \(\uparrow\) and then become almost same.
37447
The equivalent weight of an acid is equal to
1 Molecular weight $×$ acidity
2 Molecular weight $×$ basicity
3 Molecular weight / basicity
4 Molecular weight / acidity
Explanation:
Equivalent mass of an acid is defined as the number of parts by mass of it which contains \(1.008\) parts by mass of replaceable hydrogen or it in the quantity of the acid by mass that supplies one mole of \(H^{+}\) ions. Eq. mass of acid \(=\frac{\text { Molecular mass of the acid }}{\text { Number of replaceable } H \text { atoms }}\) \(=\frac{\text { Molecular mass of the acid }}{\text { Basicity of the acid }}\)
PRACTICAL CHEMISTRY
37448
A metal oxide is reduced by heating it in a stream of hydrogen. It is found that after complete reduction, \(3.15\,g\) of the oxide have yielded \(1.05\) of the metal. We may deduce that
1 The eq. weight of the metal is \(8\)
2 The atomic weight of the metal is \(8\)
3 The atomic weight of the metal is \(4\)
4 The eq. weight of the metal is \(4\)
Explanation:
\(W _{ M }=\) Weight of metal \(W _{ O }=\) Weight of oxygen \(W _{ M }=\) Equilivalent weight of metal \(W _{ M }=1.05 \,g \quad W _{ O }=3.15-1.05=2.10\, g\) Now, \(E _{ M }=\frac{ W _{ M } \times 8}{ W _{ O }}=\frac{1.05 \times 8}{2.10}=4\) So the equivalent weight of the metal is \(4\).
PRACTICAL CHEMISTRY
37449
The molecular weight of a tribasic acid is \( M\). What will be its equivalent weight
1 \(\frac{M}{2}\)
2 \(M\)
3 \(\frac{M}{3}\)
4 \(\sqrt {\frac{M}{3}} \)
Explanation:
Given, the acid is tribase, let its formula by \(H _3 A\). \(H _3 A \rightarrow H ^{+}+ A ^{3-}\) Equivalent weight \(=\frac{\text { Molecular weight }}{\text { valency }}=\frac{M}{3}\)
PRACTICAL CHEMISTRY
37450
Which of the following plot represents the graph of \(pH \) against volume of alkali added in the titration of \(NaOH \) and \(HCl\)
1
2
3
4
Explanation:
\(pH\) first almost remins same than suddenly \(\uparrow\) and then become almost same.
