155721
The energy of infrared waves is greater than that of
1 visible light
2 ultraviolet waves
3 X-rays
4 gamma rays
5 micro waves
Explanation:
E The wavelength of microwaves is greater than infrared waves. $\mathrm{E} \propto \frac{1}{\lambda}$ So, energy of infrared waves is greater than that of microwaves.
Kerala CEE 2012
Electromagnetic Wave
155725
The frequency of $X$-rays, $\gamma$-rays and ultraviolet rays are respectively $a, b$ and $c$ then:
1 a $ \lt $ b, b $>$ c
2 $a>b, b>c$
3 a $>$ b, b $ \lt $ c
4 a $ \lt $ b, b $ \lt $ c
5 $a=b=c$
Explanation:
A As we know that, energy is directly proportional to the frequency of the rays. Here, $\gamma$-rays has more energy than the $\mathrm{X}$-ray as well as ultraviolet rays. Thus, the frequency of X-rays, $\gamma$-rays and ultraviolet rays will be in following manner, $b>a>c$ Hence, $a \lt b, b>c$
Kerala CEE 2005
Electromagnetic Wave
155730
The wave length of the short radio waves, micro waves, ultraviolet waves are $\lambda_{1}, \lambda_{2}$ and $\lambda_{3}$ respectively. Arrange them in decreasing order.
1 $\lambda_{1}, \lambda_{3}, \lambda_{2}$
2 $\lambda_{1}, \lambda_{2}, \lambda_{3}$
3 $\lambda_{2}, \lambda_{1}, \lambda_{3}$
4 $\lambda_{3}, \lambda_{2}, \lambda_{1}$
Explanation:
B - Short radio waves wavelength range $=1 \times 10^{-1} \mathrm{~m}$ to $1 \times 10^{4} \mathrm{~m}$ - Microwaves wavelength range $=1 \times 10^{-3} \mathrm{~m}$ to $3 \times 10^{-1} \mathrm{~m}$ - Ultraviolet waves wavelength range $=1 \times 10^{-8} \mathrm{~m}$ to $4 \times 10^{-8} \mathrm{~m}$ So, decreasing order is $\lambda_{1}, \lambda_{2}, \lambda_{3}$.
GUJCET 2014
Electromagnetic Wave
155734
Which of the following statements is true?
1 If wavelength of light increases then frequency also increases
2 If energy increases then frequency also increases
3 Frequency of red light is greater than frequency of blue light
4 If energy increases then frequency decreases
Explanation:
B The relation between the energy (E) and the frequency $(v)$ of a photon is expressed by the equation, $\mathrm{E}=\mathrm{h} v$ Where, $\mathrm{h}$ is Plank's constant. $\therefore \quad$ E $\propto v$ Thus, energy increases then frequency also increase.
NEET Test Series from KOTA - 10 Papers In MS WORD
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Electromagnetic Wave
155721
The energy of infrared waves is greater than that of
1 visible light
2 ultraviolet waves
3 X-rays
4 gamma rays
5 micro waves
Explanation:
E The wavelength of microwaves is greater than infrared waves. $\mathrm{E} \propto \frac{1}{\lambda}$ So, energy of infrared waves is greater than that of microwaves.
Kerala CEE 2012
Electromagnetic Wave
155725
The frequency of $X$-rays, $\gamma$-rays and ultraviolet rays are respectively $a, b$ and $c$ then:
1 a $ \lt $ b, b $>$ c
2 $a>b, b>c$
3 a $>$ b, b $ \lt $ c
4 a $ \lt $ b, b $ \lt $ c
5 $a=b=c$
Explanation:
A As we know that, energy is directly proportional to the frequency of the rays. Here, $\gamma$-rays has more energy than the $\mathrm{X}$-ray as well as ultraviolet rays. Thus, the frequency of X-rays, $\gamma$-rays and ultraviolet rays will be in following manner, $b>a>c$ Hence, $a \lt b, b>c$
Kerala CEE 2005
Electromagnetic Wave
155730
The wave length of the short radio waves, micro waves, ultraviolet waves are $\lambda_{1}, \lambda_{2}$ and $\lambda_{3}$ respectively. Arrange them in decreasing order.
1 $\lambda_{1}, \lambda_{3}, \lambda_{2}$
2 $\lambda_{1}, \lambda_{2}, \lambda_{3}$
3 $\lambda_{2}, \lambda_{1}, \lambda_{3}$
4 $\lambda_{3}, \lambda_{2}, \lambda_{1}$
Explanation:
B - Short radio waves wavelength range $=1 \times 10^{-1} \mathrm{~m}$ to $1 \times 10^{4} \mathrm{~m}$ - Microwaves wavelength range $=1 \times 10^{-3} \mathrm{~m}$ to $3 \times 10^{-1} \mathrm{~m}$ - Ultraviolet waves wavelength range $=1 \times 10^{-8} \mathrm{~m}$ to $4 \times 10^{-8} \mathrm{~m}$ So, decreasing order is $\lambda_{1}, \lambda_{2}, \lambda_{3}$.
GUJCET 2014
Electromagnetic Wave
155734
Which of the following statements is true?
1 If wavelength of light increases then frequency also increases
2 If energy increases then frequency also increases
3 Frequency of red light is greater than frequency of blue light
4 If energy increases then frequency decreases
Explanation:
B The relation between the energy (E) and the frequency $(v)$ of a photon is expressed by the equation, $\mathrm{E}=\mathrm{h} v$ Where, $\mathrm{h}$ is Plank's constant. $\therefore \quad$ E $\propto v$ Thus, energy increases then frequency also increase.
155721
The energy of infrared waves is greater than that of
1 visible light
2 ultraviolet waves
3 X-rays
4 gamma rays
5 micro waves
Explanation:
E The wavelength of microwaves is greater than infrared waves. $\mathrm{E} \propto \frac{1}{\lambda}$ So, energy of infrared waves is greater than that of microwaves.
Kerala CEE 2012
Electromagnetic Wave
155725
The frequency of $X$-rays, $\gamma$-rays and ultraviolet rays are respectively $a, b$ and $c$ then:
1 a $ \lt $ b, b $>$ c
2 $a>b, b>c$
3 a $>$ b, b $ \lt $ c
4 a $ \lt $ b, b $ \lt $ c
5 $a=b=c$
Explanation:
A As we know that, energy is directly proportional to the frequency of the rays. Here, $\gamma$-rays has more energy than the $\mathrm{X}$-ray as well as ultraviolet rays. Thus, the frequency of X-rays, $\gamma$-rays and ultraviolet rays will be in following manner, $b>a>c$ Hence, $a \lt b, b>c$
Kerala CEE 2005
Electromagnetic Wave
155730
The wave length of the short radio waves, micro waves, ultraviolet waves are $\lambda_{1}, \lambda_{2}$ and $\lambda_{3}$ respectively. Arrange them in decreasing order.
1 $\lambda_{1}, \lambda_{3}, \lambda_{2}$
2 $\lambda_{1}, \lambda_{2}, \lambda_{3}$
3 $\lambda_{2}, \lambda_{1}, \lambda_{3}$
4 $\lambda_{3}, \lambda_{2}, \lambda_{1}$
Explanation:
B - Short radio waves wavelength range $=1 \times 10^{-1} \mathrm{~m}$ to $1 \times 10^{4} \mathrm{~m}$ - Microwaves wavelength range $=1 \times 10^{-3} \mathrm{~m}$ to $3 \times 10^{-1} \mathrm{~m}$ - Ultraviolet waves wavelength range $=1 \times 10^{-8} \mathrm{~m}$ to $4 \times 10^{-8} \mathrm{~m}$ So, decreasing order is $\lambda_{1}, \lambda_{2}, \lambda_{3}$.
GUJCET 2014
Electromagnetic Wave
155734
Which of the following statements is true?
1 If wavelength of light increases then frequency also increases
2 If energy increases then frequency also increases
3 Frequency of red light is greater than frequency of blue light
4 If energy increases then frequency decreases
Explanation:
B The relation between the energy (E) and the frequency $(v)$ of a photon is expressed by the equation, $\mathrm{E}=\mathrm{h} v$ Where, $\mathrm{h}$ is Plank's constant. $\therefore \quad$ E $\propto v$ Thus, energy increases then frequency also increase.
155721
The energy of infrared waves is greater than that of
1 visible light
2 ultraviolet waves
3 X-rays
4 gamma rays
5 micro waves
Explanation:
E The wavelength of microwaves is greater than infrared waves. $\mathrm{E} \propto \frac{1}{\lambda}$ So, energy of infrared waves is greater than that of microwaves.
Kerala CEE 2012
Electromagnetic Wave
155725
The frequency of $X$-rays, $\gamma$-rays and ultraviolet rays are respectively $a, b$ and $c$ then:
1 a $ \lt $ b, b $>$ c
2 $a>b, b>c$
3 a $>$ b, b $ \lt $ c
4 a $ \lt $ b, b $ \lt $ c
5 $a=b=c$
Explanation:
A As we know that, energy is directly proportional to the frequency of the rays. Here, $\gamma$-rays has more energy than the $\mathrm{X}$-ray as well as ultraviolet rays. Thus, the frequency of X-rays, $\gamma$-rays and ultraviolet rays will be in following manner, $b>a>c$ Hence, $a \lt b, b>c$
Kerala CEE 2005
Electromagnetic Wave
155730
The wave length of the short radio waves, micro waves, ultraviolet waves are $\lambda_{1}, \lambda_{2}$ and $\lambda_{3}$ respectively. Arrange them in decreasing order.
1 $\lambda_{1}, \lambda_{3}, \lambda_{2}$
2 $\lambda_{1}, \lambda_{2}, \lambda_{3}$
3 $\lambda_{2}, \lambda_{1}, \lambda_{3}$
4 $\lambda_{3}, \lambda_{2}, \lambda_{1}$
Explanation:
B - Short radio waves wavelength range $=1 \times 10^{-1} \mathrm{~m}$ to $1 \times 10^{4} \mathrm{~m}$ - Microwaves wavelength range $=1 \times 10^{-3} \mathrm{~m}$ to $3 \times 10^{-1} \mathrm{~m}$ - Ultraviolet waves wavelength range $=1 \times 10^{-8} \mathrm{~m}$ to $4 \times 10^{-8} \mathrm{~m}$ So, decreasing order is $\lambda_{1}, \lambda_{2}, \lambda_{3}$.
GUJCET 2014
Electromagnetic Wave
155734
Which of the following statements is true?
1 If wavelength of light increases then frequency also increases
2 If energy increases then frequency also increases
3 Frequency of red light is greater than frequency of blue light
4 If energy increases then frequency decreases
Explanation:
B The relation between the energy (E) and the frequency $(v)$ of a photon is expressed by the equation, $\mathrm{E}=\mathrm{h} v$ Where, $\mathrm{h}$ is Plank's constant. $\therefore \quad$ E $\propto v$ Thus, energy increases then frequency also increase.
