155633 A point source of $100 \mathrm{~W}$ emits light with $5 \%$ efficiency. At a distance of $5 \mathrm{~m}$ from the source, the intensity produced by the electric field component is :

155634 A small object at rest, absorbs a light pulse of power $20 \mathrm{~mW}$ and duration $300 \mathrm{~ns}$. Assuming speed of light is $3 \times 10^{8} \mathrm{~m} / \mathrm{s}$, the momentum of the object become equal to:

155636 In a plane electromagnetic wave, the maximum value of the electric field component is $4.4 \mathrm{Vm}^{-}$ ${ }^{1}$. The intensity of the wave is nearly-

155637 About $20 \%$ of the power of a $100 \mathrm{~W}$ bulb is converted to visible radiation Assuming that the radiation is emitted isotropically and neglecting reflection, the average intensity of visible radiation at a distance of $5 \mathrm{~m}$ is $\frac{\alpha}{25 \pi} \mathbf{W} / \mathbf{m}^{2}$.The value of $\alpha$ is

155640 A light bulb of power $100 \mathrm{~W}$ is placed at the centre of a hollow sphere of radius $10 \mathrm{~cm}$. If the $66 \%$ of the energy is converted into light, then the pressure exerted by the light on the surface of the sphere will be:
(Assume the surface of sphere to be perfectly absorbing)

155633 A point source of $100 \mathrm{~W}$ emits light with $5 \%$ efficiency. At a distance of $5 \mathrm{~m}$ from the source, the intensity produced by the electric field component is :

155634 A small object at rest, absorbs a light pulse of power $20 \mathrm{~mW}$ and duration $300 \mathrm{~ns}$. Assuming speed of light is $3 \times 10^{8} \mathrm{~m} / \mathrm{s}$, the momentum of the object become equal to:

155636 In a plane electromagnetic wave, the maximum value of the electric field component is $4.4 \mathrm{Vm}^{-}$ ${ }^{1}$. The intensity of the wave is nearly-

155637 About $20 \%$ of the power of a $100 \mathrm{~W}$ bulb is converted to visible radiation Assuming that the radiation is emitted isotropically and neglecting reflection, the average intensity of visible radiation at a distance of $5 \mathrm{~m}$ is $\frac{\alpha}{25 \pi} \mathbf{W} / \mathbf{m}^{2}$.The value of $\alpha$ is

155640 A light bulb of power $100 \mathrm{~W}$ is placed at the centre of a hollow sphere of radius $10 \mathrm{~cm}$. If the $66 \%$ of the energy is converted into light, then the pressure exerted by the light on the surface of the sphere will be:
(Assume the surface of sphere to be perfectly absorbing)

155633 A point source of $100 \mathrm{~W}$ emits light with $5 \%$ efficiency. At a distance of $5 \mathrm{~m}$ from the source, the intensity produced by the electric field component is :

155634 A small object at rest, absorbs a light pulse of power $20 \mathrm{~mW}$ and duration $300 \mathrm{~ns}$. Assuming speed of light is $3 \times 10^{8} \mathrm{~m} / \mathrm{s}$, the momentum of the object become equal to:

155636 In a plane electromagnetic wave, the maximum value of the electric field component is $4.4 \mathrm{Vm}^{-}$ ${ }^{1}$. The intensity of the wave is nearly-

155637 About $20 \%$ of the power of a $100 \mathrm{~W}$ bulb is converted to visible radiation Assuming that the radiation is emitted isotropically and neglecting reflection, the average intensity of visible radiation at a distance of $5 \mathrm{~m}$ is $\frac{\alpha}{25 \pi} \mathbf{W} / \mathbf{m}^{2}$.The value of $\alpha$ is

155640 A light bulb of power $100 \mathrm{~W}$ is placed at the centre of a hollow sphere of radius $10 \mathrm{~cm}$. If the $66 \%$ of the energy is converted into light, then the pressure exerted by the light on the surface of the sphere will be:
(Assume the surface of sphere to be perfectly absorbing)

155633 A point source of $100 \mathrm{~W}$ emits light with $5 \%$ efficiency. At a distance of $5 \mathrm{~m}$ from the source, the intensity produced by the electric field component is :

155634 A small object at rest, absorbs a light pulse of power $20 \mathrm{~mW}$ and duration $300 \mathrm{~ns}$. Assuming speed of light is $3 \times 10^{8} \mathrm{~m} / \mathrm{s}$, the momentum of the object become equal to:

155636 In a plane electromagnetic wave, the maximum value of the electric field component is $4.4 \mathrm{Vm}^{-}$ ${ }^{1}$. The intensity of the wave is nearly-

155637 About $20 \%$ of the power of a $100 \mathrm{~W}$ bulb is converted to visible radiation Assuming that the radiation is emitted isotropically and neglecting reflection, the average intensity of visible radiation at a distance of $5 \mathrm{~m}$ is $\frac{\alpha}{25 \pi} \mathbf{W} / \mathbf{m}^{2}$.The value of $\alpha$ is

155640 A light bulb of power $100 \mathrm{~W}$ is placed at the centre of a hollow sphere of radius $10 \mathrm{~cm}$. If the $66 \%$ of the energy is converted into light, then the pressure exerted by the light on the surface of the sphere will be:
(Assume the surface of sphere to be perfectly absorbing)

155633 A point source of $100 \mathrm{~W}$ emits light with $5 \%$ efficiency. At a distance of $5 \mathrm{~m}$ from the source, the intensity produced by the electric field component is :

155634 A small object at rest, absorbs a light pulse of power $20 \mathrm{~mW}$ and duration $300 \mathrm{~ns}$. Assuming speed of light is $3 \times 10^{8} \mathrm{~m} / \mathrm{s}$, the momentum of the object become equal to:

155636 In a plane electromagnetic wave, the maximum value of the electric field component is $4.4 \mathrm{Vm}^{-}$ ${ }^{1}$. The intensity of the wave is nearly-

155637 About $20 \%$ of the power of a $100 \mathrm{~W}$ bulb is converted to visible radiation Assuming that the radiation is emitted isotropically and neglecting reflection, the average intensity of visible radiation at a distance of $5 \mathrm{~m}$ is $\frac{\alpha}{25 \pi} \mathbf{W} / \mathbf{m}^{2}$.The value of $\alpha$ is

155640 A light bulb of power $100 \mathrm{~W}$ is placed at the centre of a hollow sphere of radius $10 \mathrm{~cm}$. If the $66 \%$ of the energy is converted into light, then the pressure exerted by the light on the surface of the sphere will be:
(Assume the surface of sphere to be perfectly absorbing)