155145
A circuit when connected to an AC source of 12 $\mathrm{V}$ gives a current of $0.2 \mathrm{~A}$. The same circuit when connected to a DC source of $12 \mathrm{~V}$, gives a current of $0.4 \mathrm{~A}$. The circuit is
1 series LR
2 series RC
3 series LC
4 series LCR
Explanation:
A For AC source, $\mathrm{i}_{\text {rms }}=0.2$ We know that, $i_{\text {rms }}=\frac{V_{\text {rms }}}{Z}$ Or $\quad$ Impendence $(Z)=\frac{12}{0.2}=60 \Omega$ For DC source, $\mathrm{I}=0.4=\frac{\mathrm{V}}{\mathrm{R}}=\frac{12}{\mathrm{R}}$ Resistance $(R)=\frac{12}{0.4}=\frac{120}{4}=30 \Omega$ Since, there is current in steady state of DC circuit so there is no capacitor in the circuit and as $\mathrm{Z}>\mathrm{R}$ So, second component other than resistor is inductor So the circuit is series LR circuit.
NEET- (Odisha) 2019
Alternating Current
155146
An alternating emf source of $100 \mathrm{~V}$ at $50 \mathrm{~Hz}$ is connected to a circuit of resistance $(10 \pi) \Omega$ and inductance of $0.173 \mathrm{H}$. What is the phase difference between current and emf
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Alternating Current
155145
A circuit when connected to an AC source of 12 $\mathrm{V}$ gives a current of $0.2 \mathrm{~A}$. The same circuit when connected to a DC source of $12 \mathrm{~V}$, gives a current of $0.4 \mathrm{~A}$. The circuit is
1 series LR
2 series RC
3 series LC
4 series LCR
Explanation:
A For AC source, $\mathrm{i}_{\text {rms }}=0.2$ We know that, $i_{\text {rms }}=\frac{V_{\text {rms }}}{Z}$ Or $\quad$ Impendence $(Z)=\frac{12}{0.2}=60 \Omega$ For DC source, $\mathrm{I}=0.4=\frac{\mathrm{V}}{\mathrm{R}}=\frac{12}{\mathrm{R}}$ Resistance $(R)=\frac{12}{0.4}=\frac{120}{4}=30 \Omega$ Since, there is current in steady state of DC circuit so there is no capacitor in the circuit and as $\mathrm{Z}>\mathrm{R}$ So, second component other than resistor is inductor So the circuit is series LR circuit.
NEET- (Odisha) 2019
Alternating Current
155146
An alternating emf source of $100 \mathrm{~V}$ at $50 \mathrm{~Hz}$ is connected to a circuit of resistance $(10 \pi) \Omega$ and inductance of $0.173 \mathrm{H}$. What is the phase difference between current and emf
155145
A circuit when connected to an AC source of 12 $\mathrm{V}$ gives a current of $0.2 \mathrm{~A}$. The same circuit when connected to a DC source of $12 \mathrm{~V}$, gives a current of $0.4 \mathrm{~A}$. The circuit is
1 series LR
2 series RC
3 series LC
4 series LCR
Explanation:
A For AC source, $\mathrm{i}_{\text {rms }}=0.2$ We know that, $i_{\text {rms }}=\frac{V_{\text {rms }}}{Z}$ Or $\quad$ Impendence $(Z)=\frac{12}{0.2}=60 \Omega$ For DC source, $\mathrm{I}=0.4=\frac{\mathrm{V}}{\mathrm{R}}=\frac{12}{\mathrm{R}}$ Resistance $(R)=\frac{12}{0.4}=\frac{120}{4}=30 \Omega$ Since, there is current in steady state of DC circuit so there is no capacitor in the circuit and as $\mathrm{Z}>\mathrm{R}$ So, second component other than resistor is inductor So the circuit is series LR circuit.
NEET- (Odisha) 2019
Alternating Current
155146
An alternating emf source of $100 \mathrm{~V}$ at $50 \mathrm{~Hz}$ is connected to a circuit of resistance $(10 \pi) \Omega$ and inductance of $0.173 \mathrm{H}$. What is the phase difference between current and emf
155145
A circuit when connected to an AC source of 12 $\mathrm{V}$ gives a current of $0.2 \mathrm{~A}$. The same circuit when connected to a DC source of $12 \mathrm{~V}$, gives a current of $0.4 \mathrm{~A}$. The circuit is
1 series LR
2 series RC
3 series LC
4 series LCR
Explanation:
A For AC source, $\mathrm{i}_{\text {rms }}=0.2$ We know that, $i_{\text {rms }}=\frac{V_{\text {rms }}}{Z}$ Or $\quad$ Impendence $(Z)=\frac{12}{0.2}=60 \Omega$ For DC source, $\mathrm{I}=0.4=\frac{\mathrm{V}}{\mathrm{R}}=\frac{12}{\mathrm{R}}$ Resistance $(R)=\frac{12}{0.4}=\frac{120}{4}=30 \Omega$ Since, there is current in steady state of DC circuit so there is no capacitor in the circuit and as $\mathrm{Z}>\mathrm{R}$ So, second component other than resistor is inductor So the circuit is series LR circuit.
NEET- (Odisha) 2019
Alternating Current
155146
An alternating emf source of $100 \mathrm{~V}$ at $50 \mathrm{~Hz}$ is connected to a circuit of resistance $(10 \pi) \Omega$ and inductance of $0.173 \mathrm{H}$. What is the phase difference between current and emf
