155107
If wattless current flows in the $\mathrm{AC}$ circuit, then the circuit is :
1 Purely Resistive circuit
2 Purely Inductive circuit
3 LCR series circuit
4 RC series circuit only
Explanation:
B If wattless current flows in the AC circuit then the circuit is purely inductive circuit. $\theta =\pi / 2$ $\cos \pi / 2 =0$ Average power $=0$
JEE Main-25.06.2022
Alternating Current
155108
To increase the resonant frequency in series LCR circuit,
1 Source frequency should be increased
2 Another resistance should be added in series with the first resistance
3 Another capacitor should be added in series with the first capacitor
4 The source frequency should be decreased
Explanation:
C Resonant frequency $=\frac{1}{\sqrt{\mathrm{LC}}}=\omega_{0}$ If we decrease $C, \omega_{0}$ would increase Another capacitor should be added in series
JEE Main-25.07.2022
Alternating Current
155109
In a $R C$ circuit. where $R$ is resistance and $C$ is capacitance which of the following has the dimension of time.
1 $\mathrm{R} / \mathrm{C}$
2 $\mathrm{C} / \mathrm{R}$
3 $\sqrt{\mathrm{RC}}$
4 $\mathrm{RC}$
Explanation:
D In RC circuit, $\mathrm{RC}=\frac{\mathrm{V}}{\mathrm{I}} \times \frac{\mathrm{q}}{\mathrm{V}} {\left[\because \mathrm{R}=\frac{\mathrm{V}}{\mathrm{I}} \text { and } \mathrm{q}=\mathrm{CV}\right]}$ $\mathrm{RC}=\frac{\mathrm{q}}{\mathrm{I}} \quad\left[\mathrm{I}=\frac{\mathrm{q}}{\mathrm{t}}\right]$ $\mathrm{RC}=\mathrm{t}$ Hence, RC will have same dimensional formula of time.
TS EAMCET 18.07.2022
Alternating Current
155123
When a pure resistor is connected to an $\mathrm{AC}$ source, the phase difference between the voltage and the current through the resistor is
1 $90^{\circ}$
2 $180^{\circ}$
3 $45^{\circ}$
4 $0^{\circ}$
Explanation:
D Let us consider a pure resistive circuit shown in figure given below - Applying KVL in loop, $\mathrm{V}_{\mathrm{S}}=\mathrm{V}_{\mathrm{R}}=\mathrm{I}_{\mathrm{S}} \mathrm{R}$ From phasor diagram we can see that current and voltage both are in phase. Hence phase difference between them are $0^{\circ}$.
AP EAMCET (18.09.2020) Shift-II
Alternating Current
155128
With the gradual increase in frequency of an a.c. supply, the impedance of an L-C-R series circuit
1 remains constant.
2 decreases.
3 first decreases, becomes minimum and then increases.
4 increases.
Explanation:
C In an LCR circuit the impendence and current depend upon the frequency (f). According to question if frequency is increases then $X_{L}=\omega \mathrm{L}$ will increases and $\mathrm{X}_{\mathrm{C}}=\frac{1}{\omega \mathrm{C}}$ is decreased. So, impedance of the circuit first decreases then increases after reaching a minimum value.
155107
If wattless current flows in the $\mathrm{AC}$ circuit, then the circuit is :
1 Purely Resistive circuit
2 Purely Inductive circuit
3 LCR series circuit
4 RC series circuit only
Explanation:
B If wattless current flows in the AC circuit then the circuit is purely inductive circuit. $\theta =\pi / 2$ $\cos \pi / 2 =0$ Average power $=0$
JEE Main-25.06.2022
Alternating Current
155108
To increase the resonant frequency in series LCR circuit,
1 Source frequency should be increased
2 Another resistance should be added in series with the first resistance
3 Another capacitor should be added in series with the first capacitor
4 The source frequency should be decreased
Explanation:
C Resonant frequency $=\frac{1}{\sqrt{\mathrm{LC}}}=\omega_{0}$ If we decrease $C, \omega_{0}$ would increase Another capacitor should be added in series
JEE Main-25.07.2022
Alternating Current
155109
In a $R C$ circuit. where $R$ is resistance and $C$ is capacitance which of the following has the dimension of time.
1 $\mathrm{R} / \mathrm{C}$
2 $\mathrm{C} / \mathrm{R}$
3 $\sqrt{\mathrm{RC}}$
4 $\mathrm{RC}$
Explanation:
D In RC circuit, $\mathrm{RC}=\frac{\mathrm{V}}{\mathrm{I}} \times \frac{\mathrm{q}}{\mathrm{V}} {\left[\because \mathrm{R}=\frac{\mathrm{V}}{\mathrm{I}} \text { and } \mathrm{q}=\mathrm{CV}\right]}$ $\mathrm{RC}=\frac{\mathrm{q}}{\mathrm{I}} \quad\left[\mathrm{I}=\frac{\mathrm{q}}{\mathrm{t}}\right]$ $\mathrm{RC}=\mathrm{t}$ Hence, RC will have same dimensional formula of time.
TS EAMCET 18.07.2022
Alternating Current
155123
When a pure resistor is connected to an $\mathrm{AC}$ source, the phase difference between the voltage and the current through the resistor is
1 $90^{\circ}$
2 $180^{\circ}$
3 $45^{\circ}$
4 $0^{\circ}$
Explanation:
D Let us consider a pure resistive circuit shown in figure given below - Applying KVL in loop, $\mathrm{V}_{\mathrm{S}}=\mathrm{V}_{\mathrm{R}}=\mathrm{I}_{\mathrm{S}} \mathrm{R}$ From phasor diagram we can see that current and voltage both are in phase. Hence phase difference between them are $0^{\circ}$.
AP EAMCET (18.09.2020) Shift-II
Alternating Current
155128
With the gradual increase in frequency of an a.c. supply, the impedance of an L-C-R series circuit
1 remains constant.
2 decreases.
3 first decreases, becomes minimum and then increases.
4 increases.
Explanation:
C In an LCR circuit the impendence and current depend upon the frequency (f). According to question if frequency is increases then $X_{L}=\omega \mathrm{L}$ will increases and $\mathrm{X}_{\mathrm{C}}=\frac{1}{\omega \mathrm{C}}$ is decreased. So, impedance of the circuit first decreases then increases after reaching a minimum value.
155107
If wattless current flows in the $\mathrm{AC}$ circuit, then the circuit is :
1 Purely Resistive circuit
2 Purely Inductive circuit
3 LCR series circuit
4 RC series circuit only
Explanation:
B If wattless current flows in the AC circuit then the circuit is purely inductive circuit. $\theta =\pi / 2$ $\cos \pi / 2 =0$ Average power $=0$
JEE Main-25.06.2022
Alternating Current
155108
To increase the resonant frequency in series LCR circuit,
1 Source frequency should be increased
2 Another resistance should be added in series with the first resistance
3 Another capacitor should be added in series with the first capacitor
4 The source frequency should be decreased
Explanation:
C Resonant frequency $=\frac{1}{\sqrt{\mathrm{LC}}}=\omega_{0}$ If we decrease $C, \omega_{0}$ would increase Another capacitor should be added in series
JEE Main-25.07.2022
Alternating Current
155109
In a $R C$ circuit. where $R$ is resistance and $C$ is capacitance which of the following has the dimension of time.
1 $\mathrm{R} / \mathrm{C}$
2 $\mathrm{C} / \mathrm{R}$
3 $\sqrt{\mathrm{RC}}$
4 $\mathrm{RC}$
Explanation:
D In RC circuit, $\mathrm{RC}=\frac{\mathrm{V}}{\mathrm{I}} \times \frac{\mathrm{q}}{\mathrm{V}} {\left[\because \mathrm{R}=\frac{\mathrm{V}}{\mathrm{I}} \text { and } \mathrm{q}=\mathrm{CV}\right]}$ $\mathrm{RC}=\frac{\mathrm{q}}{\mathrm{I}} \quad\left[\mathrm{I}=\frac{\mathrm{q}}{\mathrm{t}}\right]$ $\mathrm{RC}=\mathrm{t}$ Hence, RC will have same dimensional formula of time.
TS EAMCET 18.07.2022
Alternating Current
155123
When a pure resistor is connected to an $\mathrm{AC}$ source, the phase difference between the voltage and the current through the resistor is
1 $90^{\circ}$
2 $180^{\circ}$
3 $45^{\circ}$
4 $0^{\circ}$
Explanation:
D Let us consider a pure resistive circuit shown in figure given below - Applying KVL in loop, $\mathrm{V}_{\mathrm{S}}=\mathrm{V}_{\mathrm{R}}=\mathrm{I}_{\mathrm{S}} \mathrm{R}$ From phasor diagram we can see that current and voltage both are in phase. Hence phase difference between them are $0^{\circ}$.
AP EAMCET (18.09.2020) Shift-II
Alternating Current
155128
With the gradual increase in frequency of an a.c. supply, the impedance of an L-C-R series circuit
1 remains constant.
2 decreases.
3 first decreases, becomes minimum and then increases.
4 increases.
Explanation:
C In an LCR circuit the impendence and current depend upon the frequency (f). According to question if frequency is increases then $X_{L}=\omega \mathrm{L}$ will increases and $\mathrm{X}_{\mathrm{C}}=\frac{1}{\omega \mathrm{C}}$ is decreased. So, impedance of the circuit first decreases then increases after reaching a minimum value.
NEET Test Series from KOTA - 10 Papers In MS WORD
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Alternating Current
155107
If wattless current flows in the $\mathrm{AC}$ circuit, then the circuit is :
1 Purely Resistive circuit
2 Purely Inductive circuit
3 LCR series circuit
4 RC series circuit only
Explanation:
B If wattless current flows in the AC circuit then the circuit is purely inductive circuit. $\theta =\pi / 2$ $\cos \pi / 2 =0$ Average power $=0$
JEE Main-25.06.2022
Alternating Current
155108
To increase the resonant frequency in series LCR circuit,
1 Source frequency should be increased
2 Another resistance should be added in series with the first resistance
3 Another capacitor should be added in series with the first capacitor
4 The source frequency should be decreased
Explanation:
C Resonant frequency $=\frac{1}{\sqrt{\mathrm{LC}}}=\omega_{0}$ If we decrease $C, \omega_{0}$ would increase Another capacitor should be added in series
JEE Main-25.07.2022
Alternating Current
155109
In a $R C$ circuit. where $R$ is resistance and $C$ is capacitance which of the following has the dimension of time.
1 $\mathrm{R} / \mathrm{C}$
2 $\mathrm{C} / \mathrm{R}$
3 $\sqrt{\mathrm{RC}}$
4 $\mathrm{RC}$
Explanation:
D In RC circuit, $\mathrm{RC}=\frac{\mathrm{V}}{\mathrm{I}} \times \frac{\mathrm{q}}{\mathrm{V}} {\left[\because \mathrm{R}=\frac{\mathrm{V}}{\mathrm{I}} \text { and } \mathrm{q}=\mathrm{CV}\right]}$ $\mathrm{RC}=\frac{\mathrm{q}}{\mathrm{I}} \quad\left[\mathrm{I}=\frac{\mathrm{q}}{\mathrm{t}}\right]$ $\mathrm{RC}=\mathrm{t}$ Hence, RC will have same dimensional formula of time.
TS EAMCET 18.07.2022
Alternating Current
155123
When a pure resistor is connected to an $\mathrm{AC}$ source, the phase difference between the voltage and the current through the resistor is
1 $90^{\circ}$
2 $180^{\circ}$
3 $45^{\circ}$
4 $0^{\circ}$
Explanation:
D Let us consider a pure resistive circuit shown in figure given below - Applying KVL in loop, $\mathrm{V}_{\mathrm{S}}=\mathrm{V}_{\mathrm{R}}=\mathrm{I}_{\mathrm{S}} \mathrm{R}$ From phasor diagram we can see that current and voltage both are in phase. Hence phase difference between them are $0^{\circ}$.
AP EAMCET (18.09.2020) Shift-II
Alternating Current
155128
With the gradual increase in frequency of an a.c. supply, the impedance of an L-C-R series circuit
1 remains constant.
2 decreases.
3 first decreases, becomes minimum and then increases.
4 increases.
Explanation:
C In an LCR circuit the impendence and current depend upon the frequency (f). According to question if frequency is increases then $X_{L}=\omega \mathrm{L}$ will increases and $\mathrm{X}_{\mathrm{C}}=\frac{1}{\omega \mathrm{C}}$ is decreased. So, impedance of the circuit first decreases then increases after reaching a minimum value.
155107
If wattless current flows in the $\mathrm{AC}$ circuit, then the circuit is :
1 Purely Resistive circuit
2 Purely Inductive circuit
3 LCR series circuit
4 RC series circuit only
Explanation:
B If wattless current flows in the AC circuit then the circuit is purely inductive circuit. $\theta =\pi / 2$ $\cos \pi / 2 =0$ Average power $=0$
JEE Main-25.06.2022
Alternating Current
155108
To increase the resonant frequency in series LCR circuit,
1 Source frequency should be increased
2 Another resistance should be added in series with the first resistance
3 Another capacitor should be added in series with the first capacitor
4 The source frequency should be decreased
Explanation:
C Resonant frequency $=\frac{1}{\sqrt{\mathrm{LC}}}=\omega_{0}$ If we decrease $C, \omega_{0}$ would increase Another capacitor should be added in series
JEE Main-25.07.2022
Alternating Current
155109
In a $R C$ circuit. where $R$ is resistance and $C$ is capacitance which of the following has the dimension of time.
1 $\mathrm{R} / \mathrm{C}$
2 $\mathrm{C} / \mathrm{R}$
3 $\sqrt{\mathrm{RC}}$
4 $\mathrm{RC}$
Explanation:
D In RC circuit, $\mathrm{RC}=\frac{\mathrm{V}}{\mathrm{I}} \times \frac{\mathrm{q}}{\mathrm{V}} {\left[\because \mathrm{R}=\frac{\mathrm{V}}{\mathrm{I}} \text { and } \mathrm{q}=\mathrm{CV}\right]}$ $\mathrm{RC}=\frac{\mathrm{q}}{\mathrm{I}} \quad\left[\mathrm{I}=\frac{\mathrm{q}}{\mathrm{t}}\right]$ $\mathrm{RC}=\mathrm{t}$ Hence, RC will have same dimensional formula of time.
TS EAMCET 18.07.2022
Alternating Current
155123
When a pure resistor is connected to an $\mathrm{AC}$ source, the phase difference between the voltage and the current through the resistor is
1 $90^{\circ}$
2 $180^{\circ}$
3 $45^{\circ}$
4 $0^{\circ}$
Explanation:
D Let us consider a pure resistive circuit shown in figure given below - Applying KVL in loop, $\mathrm{V}_{\mathrm{S}}=\mathrm{V}_{\mathrm{R}}=\mathrm{I}_{\mathrm{S}} \mathrm{R}$ From phasor diagram we can see that current and voltage both are in phase. Hence phase difference between them are $0^{\circ}$.
AP EAMCET (18.09.2020) Shift-II
Alternating Current
155128
With the gradual increase in frequency of an a.c. supply, the impedance of an L-C-R series circuit
1 remains constant.
2 decreases.
3 first decreases, becomes minimum and then increases.
4 increases.
Explanation:
C In an LCR circuit the impendence and current depend upon the frequency (f). According to question if frequency is increases then $X_{L}=\omega \mathrm{L}$ will increases and $\mathrm{X}_{\mathrm{C}}=\frac{1}{\omega \mathrm{C}}$ is decreased. So, impedance of the circuit first decreases then increases after reaching a minimum value.
