NEET Test Series from KOTA - 10 Papers In MS WORD
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Alternating Current
155074
The maximum value of $\mathrm{AC}$ voltage in a circuit is $707 \mathrm{~V}$. Its rms value is:
1 $70.7 \mathrm{~V}$
2 $100 \mathrm{~V}$
3 $500 \mathrm{~V}$
4 $707 \mathrm{~V}$
Explanation:
C Given that, Maximum voltage of AC circuit $\left(\mathrm{V}_{0}\right)=707 \mathrm{~V}$ As we know, $\mathrm{V}_{\mathrm{rms}}=\frac{\mathrm{V}_{0}}{\sqrt{2}}=\frac{707}{\sqrt{2}}=\frac{707}{1.414}=500 \mathrm{~V}$
Kerala CEE 2004
Alternating Current
155084
A multimeter reads a voltage of a certain AC source as $100 \mathrm{~V}$. What is the peak value of voltage of AC source?
1 $200 \mathrm{~V}$
2 $100 \mathrm{~V}$
3 $141.4 \mathrm{~V}$
4 $400 \mathrm{~V}$
Explanation:
C Given that, Voltage of multimeter, $\mathrm{V}_{\mathrm{rms}}=100 \mathrm{~V}$ The peak value voltage, $\mathrm{V}_{0}=\sqrt{2} \mathrm{~V}_{\text {rms }}$ $=1.414 \times 100=141.4 \mathrm{~V}$
Karnataka CET-2014
Alternating Current
155086
An inductor is connected to an a.c. source when compared to voltage, the current in the lead wires
1 is ahead in phase by $\pi$
2 lags in phase by $\pi$
3 is ahead in phase by $\frac{\pi}{2}$
4 lags in phase by $\frac{\pi}{2}$
Explanation:
D In a purely inductive circuit, Current is, $\mathrm{i}=\mathrm{i}_{0} \sin \left(\omega \mathrm{t}-\frac{\pi}{2}\right)$ Which show that the current lag behind the emf by an angle of $\frac{\pi}{2}$ or emf leads the current by a phase angle of $\frac{\pi}{2}$ or $90^{\circ}$.
J and K CET- 2006
Alternating Current
155034
In an AC circuit containing only capacitance, the current
1 leads the voltage by $180^{\circ}$
2 remains in phase with the voltage
3 leads the voltage by $90^{\circ}$
4 lags the voltage by $90^{\circ}$
Explanation:
C In pure capacitive circuit current lead voltage by $90^{\circ}$.
155074
The maximum value of $\mathrm{AC}$ voltage in a circuit is $707 \mathrm{~V}$. Its rms value is:
1 $70.7 \mathrm{~V}$
2 $100 \mathrm{~V}$
3 $500 \mathrm{~V}$
4 $707 \mathrm{~V}$
Explanation:
C Given that, Maximum voltage of AC circuit $\left(\mathrm{V}_{0}\right)=707 \mathrm{~V}$ As we know, $\mathrm{V}_{\mathrm{rms}}=\frac{\mathrm{V}_{0}}{\sqrt{2}}=\frac{707}{\sqrt{2}}=\frac{707}{1.414}=500 \mathrm{~V}$
Kerala CEE 2004
Alternating Current
155084
A multimeter reads a voltage of a certain AC source as $100 \mathrm{~V}$. What is the peak value of voltage of AC source?
1 $200 \mathrm{~V}$
2 $100 \mathrm{~V}$
3 $141.4 \mathrm{~V}$
4 $400 \mathrm{~V}$
Explanation:
C Given that, Voltage of multimeter, $\mathrm{V}_{\mathrm{rms}}=100 \mathrm{~V}$ The peak value voltage, $\mathrm{V}_{0}=\sqrt{2} \mathrm{~V}_{\text {rms }}$ $=1.414 \times 100=141.4 \mathrm{~V}$
Karnataka CET-2014
Alternating Current
155086
An inductor is connected to an a.c. source when compared to voltage, the current in the lead wires
1 is ahead in phase by $\pi$
2 lags in phase by $\pi$
3 is ahead in phase by $\frac{\pi}{2}$
4 lags in phase by $\frac{\pi}{2}$
Explanation:
D In a purely inductive circuit, Current is, $\mathrm{i}=\mathrm{i}_{0} \sin \left(\omega \mathrm{t}-\frac{\pi}{2}\right)$ Which show that the current lag behind the emf by an angle of $\frac{\pi}{2}$ or emf leads the current by a phase angle of $\frac{\pi}{2}$ or $90^{\circ}$.
J and K CET- 2006
Alternating Current
155034
In an AC circuit containing only capacitance, the current
1 leads the voltage by $180^{\circ}$
2 remains in phase with the voltage
3 leads the voltage by $90^{\circ}$
4 lags the voltage by $90^{\circ}$
Explanation:
C In pure capacitive circuit current lead voltage by $90^{\circ}$.
155074
The maximum value of $\mathrm{AC}$ voltage in a circuit is $707 \mathrm{~V}$. Its rms value is:
1 $70.7 \mathrm{~V}$
2 $100 \mathrm{~V}$
3 $500 \mathrm{~V}$
4 $707 \mathrm{~V}$
Explanation:
C Given that, Maximum voltage of AC circuit $\left(\mathrm{V}_{0}\right)=707 \mathrm{~V}$ As we know, $\mathrm{V}_{\mathrm{rms}}=\frac{\mathrm{V}_{0}}{\sqrt{2}}=\frac{707}{\sqrt{2}}=\frac{707}{1.414}=500 \mathrm{~V}$
Kerala CEE 2004
Alternating Current
155084
A multimeter reads a voltage of a certain AC source as $100 \mathrm{~V}$. What is the peak value of voltage of AC source?
1 $200 \mathrm{~V}$
2 $100 \mathrm{~V}$
3 $141.4 \mathrm{~V}$
4 $400 \mathrm{~V}$
Explanation:
C Given that, Voltage of multimeter, $\mathrm{V}_{\mathrm{rms}}=100 \mathrm{~V}$ The peak value voltage, $\mathrm{V}_{0}=\sqrt{2} \mathrm{~V}_{\text {rms }}$ $=1.414 \times 100=141.4 \mathrm{~V}$
Karnataka CET-2014
Alternating Current
155086
An inductor is connected to an a.c. source when compared to voltage, the current in the lead wires
1 is ahead in phase by $\pi$
2 lags in phase by $\pi$
3 is ahead in phase by $\frac{\pi}{2}$
4 lags in phase by $\frac{\pi}{2}$
Explanation:
D In a purely inductive circuit, Current is, $\mathrm{i}=\mathrm{i}_{0} \sin \left(\omega \mathrm{t}-\frac{\pi}{2}\right)$ Which show that the current lag behind the emf by an angle of $\frac{\pi}{2}$ or emf leads the current by a phase angle of $\frac{\pi}{2}$ or $90^{\circ}$.
J and K CET- 2006
Alternating Current
155034
In an AC circuit containing only capacitance, the current
1 leads the voltage by $180^{\circ}$
2 remains in phase with the voltage
3 leads the voltage by $90^{\circ}$
4 lags the voltage by $90^{\circ}$
Explanation:
C In pure capacitive circuit current lead voltage by $90^{\circ}$.
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Alternating Current
155074
The maximum value of $\mathrm{AC}$ voltage in a circuit is $707 \mathrm{~V}$. Its rms value is:
1 $70.7 \mathrm{~V}$
2 $100 \mathrm{~V}$
3 $500 \mathrm{~V}$
4 $707 \mathrm{~V}$
Explanation:
C Given that, Maximum voltage of AC circuit $\left(\mathrm{V}_{0}\right)=707 \mathrm{~V}$ As we know, $\mathrm{V}_{\mathrm{rms}}=\frac{\mathrm{V}_{0}}{\sqrt{2}}=\frac{707}{\sqrt{2}}=\frac{707}{1.414}=500 \mathrm{~V}$
Kerala CEE 2004
Alternating Current
155084
A multimeter reads a voltage of a certain AC source as $100 \mathrm{~V}$. What is the peak value of voltage of AC source?
1 $200 \mathrm{~V}$
2 $100 \mathrm{~V}$
3 $141.4 \mathrm{~V}$
4 $400 \mathrm{~V}$
Explanation:
C Given that, Voltage of multimeter, $\mathrm{V}_{\mathrm{rms}}=100 \mathrm{~V}$ The peak value voltage, $\mathrm{V}_{0}=\sqrt{2} \mathrm{~V}_{\text {rms }}$ $=1.414 \times 100=141.4 \mathrm{~V}$
Karnataka CET-2014
Alternating Current
155086
An inductor is connected to an a.c. source when compared to voltage, the current in the lead wires
1 is ahead in phase by $\pi$
2 lags in phase by $\pi$
3 is ahead in phase by $\frac{\pi}{2}$
4 lags in phase by $\frac{\pi}{2}$
Explanation:
D In a purely inductive circuit, Current is, $\mathrm{i}=\mathrm{i}_{0} \sin \left(\omega \mathrm{t}-\frac{\pi}{2}\right)$ Which show that the current lag behind the emf by an angle of $\frac{\pi}{2}$ or emf leads the current by a phase angle of $\frac{\pi}{2}$ or $90^{\circ}$.
J and K CET- 2006
Alternating Current
155034
In an AC circuit containing only capacitance, the current
1 leads the voltage by $180^{\circ}$
2 remains in phase with the voltage
3 leads the voltage by $90^{\circ}$
4 lags the voltage by $90^{\circ}$
Explanation:
C In pure capacitive circuit current lead voltage by $90^{\circ}$.
