03. Magnetism, Magnetic Properties and Magnetisation
Magnetism and Matter

154426 The ratio of magnetic field and magnetic moment at the centre of a current carrying circular loop is $X$. When both the current and radius is doubled the ratio will be

1 $\frac{X}{8}$
2 $\frac{X}{4}$
3 $\frac{X}{2}$
4 $2 \mathrm{X}$
Magnetism and Matter

154434 Two bar magnets $A$ and $B$ are placed one over the other and are allowed to vibrate in a vibration magnetometer. They make 20 oscillations per minute when the similar poles of $A$ and $B$ are on the same side, while they make 15 oscillations per minute when their opposite poles lie on the same side. If $M_{A}$ and $M_{B}$ are the magnetic moments of $A$ and $B$ and if $M_{A}>M_{B}$ the ratio of $M_{A}$ and $M_{B}$ is

1 $4: 3$
2 $25: 7$
3 $7: 5$
4 $25: 16$
Magnetism and Matter

154435 A deflection magnetometer is adjusted and a magnet of magnetic moment $M$ is placed on it in the usual manner and the observed deflection is $\theta$. The period of oscillation of the needle before settling of the deflection is $T$. When the magnet is removed, the period of oscillation of the needle is $T_{0}$ before settling to $0^{\circ}-0^{\circ}$. If the earth's induced magnetic field is $B_{H}$, the relation between $T$ and $T_{0}$ is

1 $\mathrm{T}^{2}=\mathrm{T}_{0}^{2} \cos \theta$
2 $\mathrm{T}^{2}=\frac{\mathrm{T}_{0}^{2}}{\cos \theta}$
3 $\mathrm{T}=\mathrm{T}_{0} \cos \theta$
4 $\mathrm{T}=\frac{\mathrm{T}_{0}}{\cos \theta}$
Magnetism and Matter

154436 Two short bar magnets have their magnetic moments $1.2 \mathrm{Am}^{2}$ and $1.0 \mathrm{Am}^{2}$. They are placed on a horizontal table parallel to each other at a distance of $20 \mathrm{~cm}$ between their centres, such that their north poles pointing towards geographic south. They have common magnetic equatorial line. Horizontal component of earth's field is $3.6 \times 10^{-5} \mathrm{~T}$. Then, the resultant horizontal magnetic induction at mid point of the line joining their centers is
$\left(\frac{\boldsymbol{\mu}_{\mathbf{0}}}{\mathbf{4 \pi}}=10^{-7} \mathrm{~N} / \mathbf{m}\right)$

1 $3.6 \times 10^{-5} \mathrm{~T}$
2 $1.84 \times 10^{-4} \mathrm{~T}$
3 $2.56 \times 10^{-4} \mathrm{~T}$
4 $5.8 \times 10^{-5} \mathrm{~T}$
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Magnetism and Matter

154426 The ratio of magnetic field and magnetic moment at the centre of a current carrying circular loop is $X$. When both the current and radius is doubled the ratio will be

1 $\frac{X}{8}$
2 $\frac{X}{4}$
3 $\frac{X}{2}$
4 $2 \mathrm{X}$
Magnetism and Matter

154434 Two bar magnets $A$ and $B$ are placed one over the other and are allowed to vibrate in a vibration magnetometer. They make 20 oscillations per minute when the similar poles of $A$ and $B$ are on the same side, while they make 15 oscillations per minute when their opposite poles lie on the same side. If $M_{A}$ and $M_{B}$ are the magnetic moments of $A$ and $B$ and if $M_{A}>M_{B}$ the ratio of $M_{A}$ and $M_{B}$ is

1 $4: 3$
2 $25: 7$
3 $7: 5$
4 $25: 16$
Magnetism and Matter

154435 A deflection magnetometer is adjusted and a magnet of magnetic moment $M$ is placed on it in the usual manner and the observed deflection is $\theta$. The period of oscillation of the needle before settling of the deflection is $T$. When the magnet is removed, the period of oscillation of the needle is $T_{0}$ before settling to $0^{\circ}-0^{\circ}$. If the earth's induced magnetic field is $B_{H}$, the relation between $T$ and $T_{0}$ is

1 $\mathrm{T}^{2}=\mathrm{T}_{0}^{2} \cos \theta$
2 $\mathrm{T}^{2}=\frac{\mathrm{T}_{0}^{2}}{\cos \theta}$
3 $\mathrm{T}=\mathrm{T}_{0} \cos \theta$
4 $\mathrm{T}=\frac{\mathrm{T}_{0}}{\cos \theta}$
Magnetism and Matter

154436 Two short bar magnets have their magnetic moments $1.2 \mathrm{Am}^{2}$ and $1.0 \mathrm{Am}^{2}$. They are placed on a horizontal table parallel to each other at a distance of $20 \mathrm{~cm}$ between their centres, such that their north poles pointing towards geographic south. They have common magnetic equatorial line. Horizontal component of earth's field is $3.6 \times 10^{-5} \mathrm{~T}$. Then, the resultant horizontal magnetic induction at mid point of the line joining their centers is
$\left(\frac{\boldsymbol{\mu}_{\mathbf{0}}}{\mathbf{4 \pi}}=10^{-7} \mathrm{~N} / \mathbf{m}\right)$

1 $3.6 \times 10^{-5} \mathrm{~T}$
2 $1.84 \times 10^{-4} \mathrm{~T}$
3 $2.56 \times 10^{-4} \mathrm{~T}$
4 $5.8 \times 10^{-5} \mathrm{~T}$
Magnetism and Matter

154426 The ratio of magnetic field and magnetic moment at the centre of a current carrying circular loop is $X$. When both the current and radius is doubled the ratio will be

1 $\frac{X}{8}$
2 $\frac{X}{4}$
3 $\frac{X}{2}$
4 $2 \mathrm{X}$
Magnetism and Matter

154434 Two bar magnets $A$ and $B$ are placed one over the other and are allowed to vibrate in a vibration magnetometer. They make 20 oscillations per minute when the similar poles of $A$ and $B$ are on the same side, while they make 15 oscillations per minute when their opposite poles lie on the same side. If $M_{A}$ and $M_{B}$ are the magnetic moments of $A$ and $B$ and if $M_{A}>M_{B}$ the ratio of $M_{A}$ and $M_{B}$ is

1 $4: 3$
2 $25: 7$
3 $7: 5$
4 $25: 16$
Magnetism and Matter

154435 A deflection magnetometer is adjusted and a magnet of magnetic moment $M$ is placed on it in the usual manner and the observed deflection is $\theta$. The period of oscillation of the needle before settling of the deflection is $T$. When the magnet is removed, the period of oscillation of the needle is $T_{0}$ before settling to $0^{\circ}-0^{\circ}$. If the earth's induced magnetic field is $B_{H}$, the relation between $T$ and $T_{0}$ is

1 $\mathrm{T}^{2}=\mathrm{T}_{0}^{2} \cos \theta$
2 $\mathrm{T}^{2}=\frac{\mathrm{T}_{0}^{2}}{\cos \theta}$
3 $\mathrm{T}=\mathrm{T}_{0} \cos \theta$
4 $\mathrm{T}=\frac{\mathrm{T}_{0}}{\cos \theta}$
Magnetism and Matter

154436 Two short bar magnets have their magnetic moments $1.2 \mathrm{Am}^{2}$ and $1.0 \mathrm{Am}^{2}$. They are placed on a horizontal table parallel to each other at a distance of $20 \mathrm{~cm}$ between their centres, such that their north poles pointing towards geographic south. They have common magnetic equatorial line. Horizontal component of earth's field is $3.6 \times 10^{-5} \mathrm{~T}$. Then, the resultant horizontal magnetic induction at mid point of the line joining their centers is
$\left(\frac{\boldsymbol{\mu}_{\mathbf{0}}}{\mathbf{4 \pi}}=10^{-7} \mathrm{~N} / \mathbf{m}\right)$

1 $3.6 \times 10^{-5} \mathrm{~T}$
2 $1.84 \times 10^{-4} \mathrm{~T}$
3 $2.56 \times 10^{-4} \mathrm{~T}$
4 $5.8 \times 10^{-5} \mathrm{~T}$
Magnetism and Matter

154426 The ratio of magnetic field and magnetic moment at the centre of a current carrying circular loop is $X$. When both the current and radius is doubled the ratio will be

1 $\frac{X}{8}$
2 $\frac{X}{4}$
3 $\frac{X}{2}$
4 $2 \mathrm{X}$
Magnetism and Matter

154434 Two bar magnets $A$ and $B$ are placed one over the other and are allowed to vibrate in a vibration magnetometer. They make 20 oscillations per minute when the similar poles of $A$ and $B$ are on the same side, while they make 15 oscillations per minute when their opposite poles lie on the same side. If $M_{A}$ and $M_{B}$ are the magnetic moments of $A$ and $B$ and if $M_{A}>M_{B}$ the ratio of $M_{A}$ and $M_{B}$ is

1 $4: 3$
2 $25: 7$
3 $7: 5$
4 $25: 16$
Magnetism and Matter

154435 A deflection magnetometer is adjusted and a magnet of magnetic moment $M$ is placed on it in the usual manner and the observed deflection is $\theta$. The period of oscillation of the needle before settling of the deflection is $T$. When the magnet is removed, the period of oscillation of the needle is $T_{0}$ before settling to $0^{\circ}-0^{\circ}$. If the earth's induced magnetic field is $B_{H}$, the relation between $T$ and $T_{0}$ is

1 $\mathrm{T}^{2}=\mathrm{T}_{0}^{2} \cos \theta$
2 $\mathrm{T}^{2}=\frac{\mathrm{T}_{0}^{2}}{\cos \theta}$
3 $\mathrm{T}=\mathrm{T}_{0} \cos \theta$
4 $\mathrm{T}=\frac{\mathrm{T}_{0}}{\cos \theta}$
Magnetism and Matter

154436 Two short bar magnets have their magnetic moments $1.2 \mathrm{Am}^{2}$ and $1.0 \mathrm{Am}^{2}$. They are placed on a horizontal table parallel to each other at a distance of $20 \mathrm{~cm}$ between their centres, such that their north poles pointing towards geographic south. They have common magnetic equatorial line. Horizontal component of earth's field is $3.6 \times 10^{-5} \mathrm{~T}$. Then, the resultant horizontal magnetic induction at mid point of the line joining their centers is
$\left(\frac{\boldsymbol{\mu}_{\mathbf{0}}}{\mathbf{4 \pi}}=10^{-7} \mathrm{~N} / \mathbf{m}\right)$

1 $3.6 \times 10^{-5} \mathrm{~T}$
2 $1.84 \times 10^{-4} \mathrm{~T}$
3 $2.56 \times 10^{-4} \mathrm{~T}$
4 $5.8 \times 10^{-5} \mathrm{~T}$