154392
Current $I$ is flowing in a coil of area $A$ and number of turns is $\mathrm{N}$, then magnetic moment of the coil is $M$ equal to
1 NIA
2 $\mathrm{NI} / \mathrm{A}$
3 $\mathrm{NI} / \sqrt{\mathrm{A}}$
4 $\mathrm{N}^{2} \mathrm{AI}$
Explanation:
A If there are ' $\mathrm{N}$ ' turns in a coil, ' $\mathrm{I}$ ' is the current flowing and $\mathrm{A}$ is the area of the coil. Then, the magnetic dipole moment of the coil is equal to NIA.
BITSAT-2008
Magnetism and Matter
154394
If a magnetic substance is kept in a magnetic field, then which of the following substances is thrown out?
1 Paramagnetic
2 Ferromagnetic
3 Diamagnetic
4 Anti-ferromagnetic
Explanation:
C Magnetic substance when kept in a magnetic field is feebly repelled or thrown out if the substance is diamagnetic.
MHT-CET 2007
Magnetism and Matter
154395
The magnetism of a magnet is due to
1 the earth
2 cosmic rays
3 the spin motion of electrons
4 pressure of big magnet inside the earth
Explanation:
C The magnetism of the magnet is due to the spin motion of electrons. Each electron in an atom is revolving in on orbit around the nucleus. The revolving electron is equivalent to a tiny loop of current. Therefore, it possesses some orbital magnetic dipole Moment $\mathrm{M}=$ current $\times$ area of the loop. In addition to the orbital motion, every electron is assumed to have a spin motion around its axis. Therefore, another dipole magnetic moment called spin magnet $\mathrm{Ms}$ is also associated with electron. The vector sum of $\mathrm{M}_{\mathrm{I}}$ and $\mathrm{M}_{\mathrm{s}}$ provides the net magnetic dipole moment $\mathrm{M}$ to the atom. $\mathrm{M}_{\mathrm{s}}$ is much greater than $\mathrm{M}_{\mathrm{I}}$, therefore, magnetism of magnet is the due to spin motion of electrons.
MHT-CET 2007
Magnetism and Matter
154396
On applying an external magnetic field to a ferromagnetic substance, domains
1 align in the direction of magnetic field
2 align in the direction opposite to magnetic field
3 remain unaffected
4 None of these
Explanation:
A When applying an external magnetic field to a ferromagnetic material domains align in the direction of magnetic field. So, option (a) is correct
154392
Current $I$ is flowing in a coil of area $A$ and number of turns is $\mathrm{N}$, then magnetic moment of the coil is $M$ equal to
1 NIA
2 $\mathrm{NI} / \mathrm{A}$
3 $\mathrm{NI} / \sqrt{\mathrm{A}}$
4 $\mathrm{N}^{2} \mathrm{AI}$
Explanation:
A If there are ' $\mathrm{N}$ ' turns in a coil, ' $\mathrm{I}$ ' is the current flowing and $\mathrm{A}$ is the area of the coil. Then, the magnetic dipole moment of the coil is equal to NIA.
BITSAT-2008
Magnetism and Matter
154394
If a magnetic substance is kept in a magnetic field, then which of the following substances is thrown out?
1 Paramagnetic
2 Ferromagnetic
3 Diamagnetic
4 Anti-ferromagnetic
Explanation:
C Magnetic substance when kept in a magnetic field is feebly repelled or thrown out if the substance is diamagnetic.
MHT-CET 2007
Magnetism and Matter
154395
The magnetism of a magnet is due to
1 the earth
2 cosmic rays
3 the spin motion of electrons
4 pressure of big magnet inside the earth
Explanation:
C The magnetism of the magnet is due to the spin motion of electrons. Each electron in an atom is revolving in on orbit around the nucleus. The revolving electron is equivalent to a tiny loop of current. Therefore, it possesses some orbital magnetic dipole Moment $\mathrm{M}=$ current $\times$ area of the loop. In addition to the orbital motion, every electron is assumed to have a spin motion around its axis. Therefore, another dipole magnetic moment called spin magnet $\mathrm{Ms}$ is also associated with electron. The vector sum of $\mathrm{M}_{\mathrm{I}}$ and $\mathrm{M}_{\mathrm{s}}$ provides the net magnetic dipole moment $\mathrm{M}$ to the atom. $\mathrm{M}_{\mathrm{s}}$ is much greater than $\mathrm{M}_{\mathrm{I}}$, therefore, magnetism of magnet is the due to spin motion of electrons.
MHT-CET 2007
Magnetism and Matter
154396
On applying an external magnetic field to a ferromagnetic substance, domains
1 align in the direction of magnetic field
2 align in the direction opposite to magnetic field
3 remain unaffected
4 None of these
Explanation:
A When applying an external magnetic field to a ferromagnetic material domains align in the direction of magnetic field. So, option (a) is correct
154392
Current $I$ is flowing in a coil of area $A$ and number of turns is $\mathrm{N}$, then magnetic moment of the coil is $M$ equal to
1 NIA
2 $\mathrm{NI} / \mathrm{A}$
3 $\mathrm{NI} / \sqrt{\mathrm{A}}$
4 $\mathrm{N}^{2} \mathrm{AI}$
Explanation:
A If there are ' $\mathrm{N}$ ' turns in a coil, ' $\mathrm{I}$ ' is the current flowing and $\mathrm{A}$ is the area of the coil. Then, the magnetic dipole moment of the coil is equal to NIA.
BITSAT-2008
Magnetism and Matter
154394
If a magnetic substance is kept in a magnetic field, then which of the following substances is thrown out?
1 Paramagnetic
2 Ferromagnetic
3 Diamagnetic
4 Anti-ferromagnetic
Explanation:
C Magnetic substance when kept in a magnetic field is feebly repelled or thrown out if the substance is diamagnetic.
MHT-CET 2007
Magnetism and Matter
154395
The magnetism of a magnet is due to
1 the earth
2 cosmic rays
3 the spin motion of electrons
4 pressure of big magnet inside the earth
Explanation:
C The magnetism of the magnet is due to the spin motion of electrons. Each electron in an atom is revolving in on orbit around the nucleus. The revolving electron is equivalent to a tiny loop of current. Therefore, it possesses some orbital magnetic dipole Moment $\mathrm{M}=$ current $\times$ area of the loop. In addition to the orbital motion, every electron is assumed to have a spin motion around its axis. Therefore, another dipole magnetic moment called spin magnet $\mathrm{Ms}$ is also associated with electron. The vector sum of $\mathrm{M}_{\mathrm{I}}$ and $\mathrm{M}_{\mathrm{s}}$ provides the net magnetic dipole moment $\mathrm{M}$ to the atom. $\mathrm{M}_{\mathrm{s}}$ is much greater than $\mathrm{M}_{\mathrm{I}}$, therefore, magnetism of magnet is the due to spin motion of electrons.
MHT-CET 2007
Magnetism and Matter
154396
On applying an external magnetic field to a ferromagnetic substance, domains
1 align in the direction of magnetic field
2 align in the direction opposite to magnetic field
3 remain unaffected
4 None of these
Explanation:
A When applying an external magnetic field to a ferromagnetic material domains align in the direction of magnetic field. So, option (a) is correct
NEET Test Series from KOTA - 10 Papers In MS WORD
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Magnetism and Matter
154392
Current $I$ is flowing in a coil of area $A$ and number of turns is $\mathrm{N}$, then magnetic moment of the coil is $M$ equal to
1 NIA
2 $\mathrm{NI} / \mathrm{A}$
3 $\mathrm{NI} / \sqrt{\mathrm{A}}$
4 $\mathrm{N}^{2} \mathrm{AI}$
Explanation:
A If there are ' $\mathrm{N}$ ' turns in a coil, ' $\mathrm{I}$ ' is the current flowing and $\mathrm{A}$ is the area of the coil. Then, the magnetic dipole moment of the coil is equal to NIA.
BITSAT-2008
Magnetism and Matter
154394
If a magnetic substance is kept in a magnetic field, then which of the following substances is thrown out?
1 Paramagnetic
2 Ferromagnetic
3 Diamagnetic
4 Anti-ferromagnetic
Explanation:
C Magnetic substance when kept in a magnetic field is feebly repelled or thrown out if the substance is diamagnetic.
MHT-CET 2007
Magnetism and Matter
154395
The magnetism of a magnet is due to
1 the earth
2 cosmic rays
3 the spin motion of electrons
4 pressure of big magnet inside the earth
Explanation:
C The magnetism of the magnet is due to the spin motion of electrons. Each electron in an atom is revolving in on orbit around the nucleus. The revolving electron is equivalent to a tiny loop of current. Therefore, it possesses some orbital magnetic dipole Moment $\mathrm{M}=$ current $\times$ area of the loop. In addition to the orbital motion, every electron is assumed to have a spin motion around its axis. Therefore, another dipole magnetic moment called spin magnet $\mathrm{Ms}$ is also associated with electron. The vector sum of $\mathrm{M}_{\mathrm{I}}$ and $\mathrm{M}_{\mathrm{s}}$ provides the net magnetic dipole moment $\mathrm{M}$ to the atom. $\mathrm{M}_{\mathrm{s}}$ is much greater than $\mathrm{M}_{\mathrm{I}}$, therefore, magnetism of magnet is the due to spin motion of electrons.
MHT-CET 2007
Magnetism and Matter
154396
On applying an external magnetic field to a ferromagnetic substance, domains
1 align in the direction of magnetic field
2 align in the direction opposite to magnetic field
3 remain unaffected
4 None of these
Explanation:
A When applying an external magnetic field to a ferromagnetic material domains align in the direction of magnetic field. So, option (a) is correct
