153511 Two electrons $e_{1}$ and $e_{2}$ of mass $m$ and charge $q$ are injected into the perpendicular direction of the magnetic field $B$ such that the kinetic energy of $e_{1}$ is double that the of $e_{2}$. The relation of their frequencies of rotation, $f_{1}$ and $f_{2}$ is

153512 A straight wire is placed in a magnetic field that varies with distance $x$ from origin as $\vec{B}=B_{0}\left(2-\frac{x}{a}\right) \hat{\mathbf{k}}$. Ends of wire are at $(a, 0)$ and $(2 a, 0)$ and it carries a current $I$. If force on wire is $\vec{F}=I B_{0}\left(\frac{k a}{2}\right) \hat{j}$, then value of $k$ is

153513 A particle of charge $1.0 \times 10^{-16} \mathrm{C}$ moves through a uniform magnetic field $\vec{B}=B_{0}(\hat{\mathbf{i}}+4 \hat{\mathbf{j}}) T$. The particle velocity at some instant is $\mathbf{V}=(2 \hat{\mathbf{i}}+4 \hat{\mathbf{j}}) \mathrm{m} \mathrm{s}^{-1}$ and the magnetic force acting on it is $3 \times 10^{-16} \hat{\mathbf{k}} \mathrm{N}$. The magnetic of $B_{0}$ is

153514 A charged particle is moving in a uniform magnetic field penetrates a layer of lead and thereby loss half of its kinetic energy. Then the radius of curvature of its path is.

153511 Two electrons $e_{1}$ and $e_{2}$ of mass $m$ and charge $q$ are injected into the perpendicular direction of the magnetic field $B$ such that the kinetic energy of $e_{1}$ is double that the of $e_{2}$. The relation of their frequencies of rotation, $f_{1}$ and $f_{2}$ is

153512 A straight wire is placed in a magnetic field that varies with distance $x$ from origin as $\vec{B}=B_{0}\left(2-\frac{x}{a}\right) \hat{\mathbf{k}}$. Ends of wire are at $(a, 0)$ and $(2 a, 0)$ and it carries a current $I$. If force on wire is $\vec{F}=I B_{0}\left(\frac{k a}{2}\right) \hat{j}$, then value of $k$ is

153513 A particle of charge $1.0 \times 10^{-16} \mathrm{C}$ moves through a uniform magnetic field $\vec{B}=B_{0}(\hat{\mathbf{i}}+4 \hat{\mathbf{j}}) T$. The particle velocity at some instant is $\mathbf{V}=(2 \hat{\mathbf{i}}+4 \hat{\mathbf{j}}) \mathrm{m} \mathrm{s}^{-1}$ and the magnetic force acting on it is $3 \times 10^{-16} \hat{\mathbf{k}} \mathrm{N}$. The magnetic of $B_{0}$ is

153514 A charged particle is moving in a uniform magnetic field penetrates a layer of lead and thereby loss half of its kinetic energy. Then the radius of curvature of its path is.

153511 Two electrons $e_{1}$ and $e_{2}$ of mass $m$ and charge $q$ are injected into the perpendicular direction of the magnetic field $B$ such that the kinetic energy of $e_{1}$ is double that the of $e_{2}$. The relation of their frequencies of rotation, $f_{1}$ and $f_{2}$ is

153512 A straight wire is placed in a magnetic field that varies with distance $x$ from origin as $\vec{B}=B_{0}\left(2-\frac{x}{a}\right) \hat{\mathbf{k}}$. Ends of wire are at $(a, 0)$ and $(2 a, 0)$ and it carries a current $I$. If force on wire is $\vec{F}=I B_{0}\left(\frac{k a}{2}\right) \hat{j}$, then value of $k$ is

153513 A particle of charge $1.0 \times 10^{-16} \mathrm{C}$ moves through a uniform magnetic field $\vec{B}=B_{0}(\hat{\mathbf{i}}+4 \hat{\mathbf{j}}) T$. The particle velocity at some instant is $\mathbf{V}=(2 \hat{\mathbf{i}}+4 \hat{\mathbf{j}}) \mathrm{m} \mathrm{s}^{-1}$ and the magnetic force acting on it is $3 \times 10^{-16} \hat{\mathbf{k}} \mathrm{N}$. The magnetic of $B_{0}$ is

153514 A charged particle is moving in a uniform magnetic field penetrates a layer of lead and thereby loss half of its kinetic energy. Then the radius of curvature of its path is.

153511 Two electrons $e_{1}$ and $e_{2}$ of mass $m$ and charge $q$ are injected into the perpendicular direction of the magnetic field $B$ such that the kinetic energy of $e_{1}$ is double that the of $e_{2}$. The relation of their frequencies of rotation, $f_{1}$ and $f_{2}$ is

153512 A straight wire is placed in a magnetic field that varies with distance $x$ from origin as $\vec{B}=B_{0}\left(2-\frac{x}{a}\right) \hat{\mathbf{k}}$. Ends of wire are at $(a, 0)$ and $(2 a, 0)$ and it carries a current $I$. If force on wire is $\vec{F}=I B_{0}\left(\frac{k a}{2}\right) \hat{j}$, then value of $k$ is

153513 A particle of charge $1.0 \times 10^{-16} \mathrm{C}$ moves through a uniform magnetic field $\vec{B}=B_{0}(\hat{\mathbf{i}}+4 \hat{\mathbf{j}}) T$. The particle velocity at some instant is $\mathbf{V}=(2 \hat{\mathbf{i}}+4 \hat{\mathbf{j}}) \mathrm{m} \mathrm{s}^{-1}$ and the magnetic force acting on it is $3 \times 10^{-16} \hat{\mathbf{k}} \mathrm{N}$. The magnetic of $B_{0}$ is

153514 A charged particle is moving in a uniform magnetic field penetrates a layer of lead and thereby loss half of its kinetic energy. Then the radius of curvature of its path is.