153273 The magnetic field at a point midway between two parallel long wires carrying currents in the same direction is $10 \mu \mathrm{T}$. If the direction of the smaller current among them is reserved, the field becomes $30 \mu \mathrm{T}$. The ratio of the larger to the smaller current in them is

153274 Two long parallel wires carry currents $i_{1}$ and $i_{2}$ such that $i_{1}>i_{2}$. When the currents are in the same direction, the magnetic field at a point midway between the wires is $6 \times 10^{-6} \mathrm{~T}$. If the direction of $i_{2}$ is reversed, the field becomes $3 \times$ $10^{-5} \mathrm{~T}$. The ratio $\frac{i_{1}}{i_{2}}$ is

153275 A circular coil of 5 turns and of $10 \mathrm{~cm}$ mean diameter is connected to a voltage source. If the resistance of the coil is $10 \Omega$, the voltage of the source so as to nullify the horizontal component of earth's magnetic field of 30 A turn $m^{1}$ at the centre of the coil should be

153276 A solenoid $600 \mathrm{~mm}$ long has 50 turns on it and is wound on an iron rod of $7.5 \mathrm{~mm}$ radius. Find the flux through the solenoid when the current in it is $3 \mathrm{~A}$. The relative permeability of iron is 600 :

153273 The magnetic field at a point midway between two parallel long wires carrying currents in the same direction is $10 \mu \mathrm{T}$. If the direction of the smaller current among them is reserved, the field becomes $30 \mu \mathrm{T}$. The ratio of the larger to the smaller current in them is

153274 Two long parallel wires carry currents $i_{1}$ and $i_{2}$ such that $i_{1}>i_{2}$. When the currents are in the same direction, the magnetic field at a point midway between the wires is $6 \times 10^{-6} \mathrm{~T}$. If the direction of $i_{2}$ is reversed, the field becomes $3 \times$ $10^{-5} \mathrm{~T}$. The ratio $\frac{i_{1}}{i_{2}}$ is

153275 A circular coil of 5 turns and of $10 \mathrm{~cm}$ mean diameter is connected to a voltage source. If the resistance of the coil is $10 \Omega$, the voltage of the source so as to nullify the horizontal component of earth's magnetic field of 30 A turn $m^{1}$ at the centre of the coil should be

153276 A solenoid $600 \mathrm{~mm}$ long has 50 turns on it and is wound on an iron rod of $7.5 \mathrm{~mm}$ radius. Find the flux through the solenoid when the current in it is $3 \mathrm{~A}$. The relative permeability of iron is 600 :

153273 The magnetic field at a point midway between two parallel long wires carrying currents in the same direction is $10 \mu \mathrm{T}$. If the direction of the smaller current among them is reserved, the field becomes $30 \mu \mathrm{T}$. The ratio of the larger to the smaller current in them is

153274 Two long parallel wires carry currents $i_{1}$ and $i_{2}$ such that $i_{1}>i_{2}$. When the currents are in the same direction, the magnetic field at a point midway between the wires is $6 \times 10^{-6} \mathrm{~T}$. If the direction of $i_{2}$ is reversed, the field becomes $3 \times$ $10^{-5} \mathrm{~T}$. The ratio $\frac{i_{1}}{i_{2}}$ is

153275 A circular coil of 5 turns and of $10 \mathrm{~cm}$ mean diameter is connected to a voltage source. If the resistance of the coil is $10 \Omega$, the voltage of the source so as to nullify the horizontal component of earth's magnetic field of 30 A turn $m^{1}$ at the centre of the coil should be

153276 A solenoid $600 \mathrm{~mm}$ long has 50 turns on it and is wound on an iron rod of $7.5 \mathrm{~mm}$ radius. Find the flux through the solenoid when the current in it is $3 \mathrm{~A}$. The relative permeability of iron is 600 :

153273 The magnetic field at a point midway between two parallel long wires carrying currents in the same direction is $10 \mu \mathrm{T}$. If the direction of the smaller current among them is reserved, the field becomes $30 \mu \mathrm{T}$. The ratio of the larger to the smaller current in them is

153274 Two long parallel wires carry currents $i_{1}$ and $i_{2}$ such that $i_{1}>i_{2}$. When the currents are in the same direction, the magnetic field at a point midway between the wires is $6 \times 10^{-6} \mathrm{~T}$. If the direction of $i_{2}$ is reversed, the field becomes $3 \times$ $10^{-5} \mathrm{~T}$. The ratio $\frac{i_{1}}{i_{2}}$ is

153275 A circular coil of 5 turns and of $10 \mathrm{~cm}$ mean diameter is connected to a voltage source. If the resistance of the coil is $10 \Omega$, the voltage of the source so as to nullify the horizontal component of earth's magnetic field of 30 A turn $m^{1}$ at the centre of the coil should be

153276 A solenoid $600 \mathrm{~mm}$ long has 50 turns on it and is wound on an iron rod of $7.5 \mathrm{~mm}$ radius. Find the flux through the solenoid when the current in it is $3 \mathrm{~A}$. The relative permeability of iron is 600 :