06. Measuring Instrument (Meter Bridge, Galvanometer, Ammeter, Voltmeter, Potentiometer)
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Current Electricity

152849 In the experiment to determine the internal resistance of a cell $\left(E_{1}\right)$ using potentiometer, the resistance drawn from the resistance box is ' $R$ '. The potential difference across the balancing length of the wire is equal to the terminal potential difference $(\mathrm{V})$ of the cell. The value of internal resistance $(r)$ of the cell is

1 $\mathrm{R}\left(\frac{\mathrm{E}_{1}}{\mathrm{~V}}-1\right)$
2 $\mathrm{R}\left(\frac{\mathrm{V}}{\mathrm{E}_{1}}-1\right)$
3 $\mathrm{R}\left(\frac{\mathrm{E}_{1}}{\mathrm{~V}}+1\right)$
4 $\mathrm{R}\left(\frac{\mathrm{V}}{\mathrm{E}_{1}}+1\right)$
MHT-CET 2020
Current Electricity

152850 A galvanometer of resistance $100 \Omega$ is connected to battery of $2 \mathrm{~V}$, with a resistance of $1900 \Omega$ in series. The deflection obtained is 30 divisions. To reduce this deflection by 10 divisions, the additional resistance required to be connected in series is

1 $1500 \Omega$
2 $500 \Omega$
3 $2000\Omega$
4 $1000 \Omega$
MHT-CET 2020
Current Electricity

152851 A potentiometer wire of length ' $L$ ' and a resistance ' $r$ ' are connected in series with a battery of E.M.F. ' $E_{0}$ ' and a resistance ' $r_{1}$ '. A cell of unknown E.M.F. ' $E$ ' is balanced at a length ' $\ell$ ' of the potentiometer wire. The unknown E.M.F. $E$ is given by

1 $\frac{E_{0} \ell}{L}$
2 $\frac{\mathrm{E}_{0} \mathrm{r}}{\left(\mathrm{r}+\mathrm{r}_{1}\right)} \cdot \frac{\ell}{\mathrm{L}}$
3 $\frac{\mathrm{LE}_{0} \mathrm{r}}{\ell \mathrm{r}_{1}}$
4 $\frac{\mathrm{LE}_{0} \mathrm{r}}{\left(\mathrm{r}+\mathrm{r}_{1}\right) \ell}$
MHT-CET 2020
Current Electricity

152853 The deflection in the galvanometer falls to $\left(\frac{1}{5}\right)^{\text {th }}$ when $4 \Omega$ resistance is connected in parallel with it. What will be the deflection if an additional resistance of $2 \Omega$ is connected in parallel with the above shunted galvanometer?

1 $\frac{1}{13}^{\text {th }}$ of the original deflection.
2 $\frac{1}{8}^{\text {th }}$ of the original deflection.
3 $\frac{1}{4}^{\text {th }}$ of the original deflection.
4 $\frac{1}{6}^{\text {th }}$ of the original deflection.
MHT-CET 2020
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Current Electricity

152849 In the experiment to determine the internal resistance of a cell $\left(E_{1}\right)$ using potentiometer, the resistance drawn from the resistance box is ' $R$ '. The potential difference across the balancing length of the wire is equal to the terminal potential difference $(\mathrm{V})$ of the cell. The value of internal resistance $(r)$ of the cell is

1 $\mathrm{R}\left(\frac{\mathrm{E}_{1}}{\mathrm{~V}}-1\right)$
2 $\mathrm{R}\left(\frac{\mathrm{V}}{\mathrm{E}_{1}}-1\right)$
3 $\mathrm{R}\left(\frac{\mathrm{E}_{1}}{\mathrm{~V}}+1\right)$
4 $\mathrm{R}\left(\frac{\mathrm{V}}{\mathrm{E}_{1}}+1\right)$
MHT-CET 2020
Current Electricity

152850 A galvanometer of resistance $100 \Omega$ is connected to battery of $2 \mathrm{~V}$, with a resistance of $1900 \Omega$ in series. The deflection obtained is 30 divisions. To reduce this deflection by 10 divisions, the additional resistance required to be connected in series is

1 $1500 \Omega$
2 $500 \Omega$
3 $2000\Omega$
4 $1000 \Omega$
MHT-CET 2020
Current Electricity

152851 A potentiometer wire of length ' $L$ ' and a resistance ' $r$ ' are connected in series with a battery of E.M.F. ' $E_{0}$ ' and a resistance ' $r_{1}$ '. A cell of unknown E.M.F. ' $E$ ' is balanced at a length ' $\ell$ ' of the potentiometer wire. The unknown E.M.F. $E$ is given by

1 $\frac{E_{0} \ell}{L}$
2 $\frac{\mathrm{E}_{0} \mathrm{r}}{\left(\mathrm{r}+\mathrm{r}_{1}\right)} \cdot \frac{\ell}{\mathrm{L}}$
3 $\frac{\mathrm{LE}_{0} \mathrm{r}}{\ell \mathrm{r}_{1}}$
4 $\frac{\mathrm{LE}_{0} \mathrm{r}}{\left(\mathrm{r}+\mathrm{r}_{1}\right) \ell}$
MHT-CET 2020
Current Electricity

152853 The deflection in the galvanometer falls to $\left(\frac{1}{5}\right)^{\text {th }}$ when $4 \Omega$ resistance is connected in parallel with it. What will be the deflection if an additional resistance of $2 \Omega$ is connected in parallel with the above shunted galvanometer?

1 $\frac{1}{13}^{\text {th }}$ of the original deflection.
2 $\frac{1}{8}^{\text {th }}$ of the original deflection.
3 $\frac{1}{4}^{\text {th }}$ of the original deflection.
4 $\frac{1}{6}^{\text {th }}$ of the original deflection.
MHT-CET 2020
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Current Electricity

152849 In the experiment to determine the internal resistance of a cell $\left(E_{1}\right)$ using potentiometer, the resistance drawn from the resistance box is ' $R$ '. The potential difference across the balancing length of the wire is equal to the terminal potential difference $(\mathrm{V})$ of the cell. The value of internal resistance $(r)$ of the cell is

1 $\mathrm{R}\left(\frac{\mathrm{E}_{1}}{\mathrm{~V}}-1\right)$
2 $\mathrm{R}\left(\frac{\mathrm{V}}{\mathrm{E}_{1}}-1\right)$
3 $\mathrm{R}\left(\frac{\mathrm{E}_{1}}{\mathrm{~V}}+1\right)$
4 $\mathrm{R}\left(\frac{\mathrm{V}}{\mathrm{E}_{1}}+1\right)$
MHT-CET 2020
Current Electricity

152850 A galvanometer of resistance $100 \Omega$ is connected to battery of $2 \mathrm{~V}$, with a resistance of $1900 \Omega$ in series. The deflection obtained is 30 divisions. To reduce this deflection by 10 divisions, the additional resistance required to be connected in series is

1 $1500 \Omega$
2 $500 \Omega$
3 $2000\Omega$
4 $1000 \Omega$
MHT-CET 2020
Current Electricity

152851 A potentiometer wire of length ' $L$ ' and a resistance ' $r$ ' are connected in series with a battery of E.M.F. ' $E_{0}$ ' and a resistance ' $r_{1}$ '. A cell of unknown E.M.F. ' $E$ ' is balanced at a length ' $\ell$ ' of the potentiometer wire. The unknown E.M.F. $E$ is given by

1 $\frac{E_{0} \ell}{L}$
2 $\frac{\mathrm{E}_{0} \mathrm{r}}{\left(\mathrm{r}+\mathrm{r}_{1}\right)} \cdot \frac{\ell}{\mathrm{L}}$
3 $\frac{\mathrm{LE}_{0} \mathrm{r}}{\ell \mathrm{r}_{1}}$
4 $\frac{\mathrm{LE}_{0} \mathrm{r}}{\left(\mathrm{r}+\mathrm{r}_{1}\right) \ell}$
MHT-CET 2020
Current Electricity

152853 The deflection in the galvanometer falls to $\left(\frac{1}{5}\right)^{\text {th }}$ when $4 \Omega$ resistance is connected in parallel with it. What will be the deflection if an additional resistance of $2 \Omega$ is connected in parallel with the above shunted galvanometer?

1 $\frac{1}{13}^{\text {th }}$ of the original deflection.
2 $\frac{1}{8}^{\text {th }}$ of the original deflection.
3 $\frac{1}{4}^{\text {th }}$ of the original deflection.
4 $\frac{1}{6}^{\text {th }}$ of the original deflection.
MHT-CET 2020
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Current Electricity

152849 In the experiment to determine the internal resistance of a cell $\left(E_{1}\right)$ using potentiometer, the resistance drawn from the resistance box is ' $R$ '. The potential difference across the balancing length of the wire is equal to the terminal potential difference $(\mathrm{V})$ of the cell. The value of internal resistance $(r)$ of the cell is

1 $\mathrm{R}\left(\frac{\mathrm{E}_{1}}{\mathrm{~V}}-1\right)$
2 $\mathrm{R}\left(\frac{\mathrm{V}}{\mathrm{E}_{1}}-1\right)$
3 $\mathrm{R}\left(\frac{\mathrm{E}_{1}}{\mathrm{~V}}+1\right)$
4 $\mathrm{R}\left(\frac{\mathrm{V}}{\mathrm{E}_{1}}+1\right)$
MHT-CET 2020
Current Electricity

152850 A galvanometer of resistance $100 \Omega$ is connected to battery of $2 \mathrm{~V}$, with a resistance of $1900 \Omega$ in series. The deflection obtained is 30 divisions. To reduce this deflection by 10 divisions, the additional resistance required to be connected in series is

1 $1500 \Omega$
2 $500 \Omega$
3 $2000\Omega$
4 $1000 \Omega$
MHT-CET 2020
Current Electricity

152851 A potentiometer wire of length ' $L$ ' and a resistance ' $r$ ' are connected in series with a battery of E.M.F. ' $E_{0}$ ' and a resistance ' $r_{1}$ '. A cell of unknown E.M.F. ' $E$ ' is balanced at a length ' $\ell$ ' of the potentiometer wire. The unknown E.M.F. $E$ is given by

1 $\frac{E_{0} \ell}{L}$
2 $\frac{\mathrm{E}_{0} \mathrm{r}}{\left(\mathrm{r}+\mathrm{r}_{1}\right)} \cdot \frac{\ell}{\mathrm{L}}$
3 $\frac{\mathrm{LE}_{0} \mathrm{r}}{\ell \mathrm{r}_{1}}$
4 $\frac{\mathrm{LE}_{0} \mathrm{r}}{\left(\mathrm{r}+\mathrm{r}_{1}\right) \ell}$
MHT-CET 2020
Current Electricity

152853 The deflection in the galvanometer falls to $\left(\frac{1}{5}\right)^{\text {th }}$ when $4 \Omega$ resistance is connected in parallel with it. What will be the deflection if an additional resistance of $2 \Omega$ is connected in parallel with the above shunted galvanometer?

1 $\frac{1}{13}^{\text {th }}$ of the original deflection.
2 $\frac{1}{8}^{\text {th }}$ of the original deflection.
3 $\frac{1}{4}^{\text {th }}$ of the original deflection.
4 $\frac{1}{6}^{\text {th }}$ of the original deflection.
MHT-CET 2020
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