152828 A resistance wire connected in the left gap of a meter bridge balances a $10 \Omega$ resistance in the right gap at a point which divides the bridge wire in the ratio $3: 2$. If the length of the resistance wire is $1.5 \mathrm{~m}$, then the length of $1 \Omega$ of the resistance wire is

152829 A potentiometer has a uniform wire of length 5 m. A battery of emf $10 \mathrm{~V}$ and negligible internal resistance is connected between its ends. A secondary cell connected to the circuit gives balancing length at $200 \mathrm{~cm}$. The emf of the secondary cell is :

152830 In a Wheatstone's bridge, all the four arms have equal resistance ' $R$ '. If the resistance of the galvanometer arm is also ' $R$ ', the equivalent resistance of the combination as seen by the battery is

152831 Two cells having unknown e.m.f.s $E_{1}$ and $E_{2}$ $\left(E_{1}>E_{2}\right)$ are connected in potentiometer circuit so as to assist each other. The null point obtained is at $490 \mathrm{~cm}$ from the higher potential end. When cells $E_{2}$ is connected so as to oppose cell $E_{1}$ the null point is obtained at $90 \mathrm{~cm}$ from the same end. The ratio of the e.m.f.s of two cells $\left(\frac{\mathbf{E}_{1}}{\mathbf{E}_{2}}\right)$.

152828 A resistance wire connected in the left gap of a meter bridge balances a $10 \Omega$ resistance in the right gap at a point which divides the bridge wire in the ratio $3: 2$. If the length of the resistance wire is $1.5 \mathrm{~m}$, then the length of $1 \Omega$ of the resistance wire is

152829 A potentiometer has a uniform wire of length 5 m. A battery of emf $10 \mathrm{~V}$ and negligible internal resistance is connected between its ends. A secondary cell connected to the circuit gives balancing length at $200 \mathrm{~cm}$. The emf of the secondary cell is :

152830 In a Wheatstone's bridge, all the four arms have equal resistance ' $R$ '. If the resistance of the galvanometer arm is also ' $R$ ', the equivalent resistance of the combination as seen by the battery is

152831 Two cells having unknown e.m.f.s $E_{1}$ and $E_{2}$ $\left(E_{1}>E_{2}\right)$ are connected in potentiometer circuit so as to assist each other. The null point obtained is at $490 \mathrm{~cm}$ from the higher potential end. When cells $E_{2}$ is connected so as to oppose cell $E_{1}$ the null point is obtained at $90 \mathrm{~cm}$ from the same end. The ratio of the e.m.f.s of two cells $\left(\frac{\mathbf{E}_{1}}{\mathbf{E}_{2}}\right)$.

152828 A resistance wire connected in the left gap of a meter bridge balances a $10 \Omega$ resistance in the right gap at a point which divides the bridge wire in the ratio $3: 2$. If the length of the resistance wire is $1.5 \mathrm{~m}$, then the length of $1 \Omega$ of the resistance wire is

152829 A potentiometer has a uniform wire of length 5 m. A battery of emf $10 \mathrm{~V}$ and negligible internal resistance is connected between its ends. A secondary cell connected to the circuit gives balancing length at $200 \mathrm{~cm}$. The emf of the secondary cell is :

152830 In a Wheatstone's bridge, all the four arms have equal resistance ' $R$ '. If the resistance of the galvanometer arm is also ' $R$ ', the equivalent resistance of the combination as seen by the battery is

152831 Two cells having unknown e.m.f.s $E_{1}$ and $E_{2}$ $\left(E_{1}>E_{2}\right)$ are connected in potentiometer circuit so as to assist each other. The null point obtained is at $490 \mathrm{~cm}$ from the higher potential end. When cells $E_{2}$ is connected so as to oppose cell $E_{1}$ the null point is obtained at $90 \mathrm{~cm}$ from the same end. The ratio of the e.m.f.s of two cells $\left(\frac{\mathbf{E}_{1}}{\mathbf{E}_{2}}\right)$.

152828 A resistance wire connected in the left gap of a meter bridge balances a $10 \Omega$ resistance in the right gap at a point which divides the bridge wire in the ratio $3: 2$. If the length of the resistance wire is $1.5 \mathrm{~m}$, then the length of $1 \Omega$ of the resistance wire is

152829 A potentiometer has a uniform wire of length 5 m. A battery of emf $10 \mathrm{~V}$ and negligible internal resistance is connected between its ends. A secondary cell connected to the circuit gives balancing length at $200 \mathrm{~cm}$. The emf of the secondary cell is :

152830 In a Wheatstone's bridge, all the four arms have equal resistance ' $R$ '. If the resistance of the galvanometer arm is also ' $R$ ', the equivalent resistance of the combination as seen by the battery is

152831 Two cells having unknown e.m.f.s $E_{1}$ and $E_{2}$ $\left(E_{1}>E_{2}\right)$ are connected in potentiometer circuit so as to assist each other. The null point obtained is at $490 \mathrm{~cm}$ from the higher potential end. When cells $E_{2}$ is connected so as to oppose cell $E_{1}$ the null point is obtained at $90 \mathrm{~cm}$ from the same end. The ratio of the e.m.f.s of two cells $\left(\frac{\mathbf{E}_{1}}{\mathbf{E}_{2}}\right)$.