06. Measuring Instrument (Meter Bridge, Galvanometer, Ammeter, Voltmeter, Potentiometer)
Current Electricity

152821 To the potentiometer wire of length $L$ and $10 \Omega$ resistance, a battery of emf 2.5 volts and a resistance $R$ are connected in serier. If a potential difference of 1 volt is balanced across $L / 2$ length, the value of $R$ in $\Omega$ will be

1 1
2 1.5
3 2
4 2.5
Current Electricity

152823 In a meter bridge the balancing length from the left end is found to be $25 \mathrm{~cm}$. The value of the unknown resistance is (assume, standard resistance of $1 \Omega$ is in the right gap)

1 $0.25 \Omega$
2 $0.33 \Omega$
3 $0.20 \Omega$
4 $0.50 \Omega$
Current Electricity

152824 Two tangent galvanometers $A$ and $B$ have coils of radii $8 \mathrm{~cm}$ and $16 \mathrm{~cm}$ respectively and having resistance of $8 \Omega$ each. They are connected in parallel with a cell of emf $4 \mathrm{~V}$ and negligible internal resistance. The deflections produced in the tangent galvanometers $A$ and $B$ are $30^{\circ}$ and $60^{\circ}$, respectively. If $A$ has 2 turns, then $B$ must have

1 18 turns
2 12 turns
3 6 turns
4 2 turns
Current Electricity

152825 If the Wheatstone's bridge with four resistors $R_{1}, R_{2}$ and $R_{3}, R_{4}$ is balanced, then the correct expression is

1 $\frac{R_{2}}{R_{1}}=\frac{R_{4}}{R_{3}}$
2 $\frac{\mathrm{R}_{2}}{\mathrm{R}_{3}}=\frac{\mathrm{R}_{1}}{\mathrm{R}_{4}}$
3 $\mathrm{R}_{1} \mathrm{R}_{2}=\mathrm{R}_{3} \mathrm{R}_{4}$
4 $R_{1}+R_{2}=R_{3}+R_{4}$
Current Electricity

152821 To the potentiometer wire of length $L$ and $10 \Omega$ resistance, a battery of emf 2.5 volts and a resistance $R$ are connected in serier. If a potential difference of 1 volt is balanced across $L / 2$ length, the value of $R$ in $\Omega$ will be

1 1
2 1.5
3 2
4 2.5
Current Electricity

152823 In a meter bridge the balancing length from the left end is found to be $25 \mathrm{~cm}$. The value of the unknown resistance is (assume, standard resistance of $1 \Omega$ is in the right gap)

1 $0.25 \Omega$
2 $0.33 \Omega$
3 $0.20 \Omega$
4 $0.50 \Omega$
Current Electricity

152824 Two tangent galvanometers $A$ and $B$ have coils of radii $8 \mathrm{~cm}$ and $16 \mathrm{~cm}$ respectively and having resistance of $8 \Omega$ each. They are connected in parallel with a cell of emf $4 \mathrm{~V}$ and negligible internal resistance. The deflections produced in the tangent galvanometers $A$ and $B$ are $30^{\circ}$ and $60^{\circ}$, respectively. If $A$ has 2 turns, then $B$ must have

1 18 turns
2 12 turns
3 6 turns
4 2 turns
Current Electricity

152825 If the Wheatstone's bridge with four resistors $R_{1}, R_{2}$ and $R_{3}, R_{4}$ is balanced, then the correct expression is

1 $\frac{R_{2}}{R_{1}}=\frac{R_{4}}{R_{3}}$
2 $\frac{\mathrm{R}_{2}}{\mathrm{R}_{3}}=\frac{\mathrm{R}_{1}}{\mathrm{R}_{4}}$
3 $\mathrm{R}_{1} \mathrm{R}_{2}=\mathrm{R}_{3} \mathrm{R}_{4}$
4 $R_{1}+R_{2}=R_{3}+R_{4}$
Current Electricity

152821 To the potentiometer wire of length $L$ and $10 \Omega$ resistance, a battery of emf 2.5 volts and a resistance $R$ are connected in serier. If a potential difference of 1 volt is balanced across $L / 2$ length, the value of $R$ in $\Omega$ will be

1 1
2 1.5
3 2
4 2.5
Current Electricity

152823 In a meter bridge the balancing length from the left end is found to be $25 \mathrm{~cm}$. The value of the unknown resistance is (assume, standard resistance of $1 \Omega$ is in the right gap)

1 $0.25 \Omega$
2 $0.33 \Omega$
3 $0.20 \Omega$
4 $0.50 \Omega$
Current Electricity

152824 Two tangent galvanometers $A$ and $B$ have coils of radii $8 \mathrm{~cm}$ and $16 \mathrm{~cm}$ respectively and having resistance of $8 \Omega$ each. They are connected in parallel with a cell of emf $4 \mathrm{~V}$ and negligible internal resistance. The deflections produced in the tangent galvanometers $A$ and $B$ are $30^{\circ}$ and $60^{\circ}$, respectively. If $A$ has 2 turns, then $B$ must have

1 18 turns
2 12 turns
3 6 turns
4 2 turns
Current Electricity

152825 If the Wheatstone's bridge with four resistors $R_{1}, R_{2}$ and $R_{3}, R_{4}$ is balanced, then the correct expression is

1 $\frac{R_{2}}{R_{1}}=\frac{R_{4}}{R_{3}}$
2 $\frac{\mathrm{R}_{2}}{\mathrm{R}_{3}}=\frac{\mathrm{R}_{1}}{\mathrm{R}_{4}}$
3 $\mathrm{R}_{1} \mathrm{R}_{2}=\mathrm{R}_{3} \mathrm{R}_{4}$
4 $R_{1}+R_{2}=R_{3}+R_{4}$
Current Electricity

152821 To the potentiometer wire of length $L$ and $10 \Omega$ resistance, a battery of emf 2.5 volts and a resistance $R$ are connected in serier. If a potential difference of 1 volt is balanced across $L / 2$ length, the value of $R$ in $\Omega$ will be

1 1
2 1.5
3 2
4 2.5
Current Electricity

152823 In a meter bridge the balancing length from the left end is found to be $25 \mathrm{~cm}$. The value of the unknown resistance is (assume, standard resistance of $1 \Omega$ is in the right gap)

1 $0.25 \Omega$
2 $0.33 \Omega$
3 $0.20 \Omega$
4 $0.50 \Omega$
Current Electricity

152824 Two tangent galvanometers $A$ and $B$ have coils of radii $8 \mathrm{~cm}$ and $16 \mathrm{~cm}$ respectively and having resistance of $8 \Omega$ each. They are connected in parallel with a cell of emf $4 \mathrm{~V}$ and negligible internal resistance. The deflections produced in the tangent galvanometers $A$ and $B$ are $30^{\circ}$ and $60^{\circ}$, respectively. If $A$ has 2 turns, then $B$ must have

1 18 turns
2 12 turns
3 6 turns
4 2 turns
Current Electricity

152825 If the Wheatstone's bridge with four resistors $R_{1}, R_{2}$ and $R_{3}, R_{4}$ is balanced, then the correct expression is

1 $\frac{R_{2}}{R_{1}}=\frac{R_{4}}{R_{3}}$
2 $\frac{\mathrm{R}_{2}}{\mathrm{R}_{3}}=\frac{\mathrm{R}_{1}}{\mathrm{R}_{4}}$
3 $\mathrm{R}_{1} \mathrm{R}_{2}=\mathrm{R}_{3} \mathrm{R}_{4}$
4 $R_{1}+R_{2}=R_{3}+R_{4}$