152764
Two identical heaters of $220 \mathrm{~V}, 1000 \mathrm{~W}$ are placed in parallel with each other across $220 \mathrm{~V}$ line, then the combined power is:
1 $1000 \mathrm{~W}$
2 $2000\mathrm{~W}$
3 $500 \mathrm{~W}$
4 $4000 \mathrm{~W}$
Explanation:
B When two identical heater are connected across a given voltage then, Equivalent power $\mathrm{P}=\mathrm{P}_{1}+\mathrm{P}_{2}$ $\mathrm{P}=1000+1000=2000 \mathrm{~W}$
BCECE-2003
Current Electricity
152665
Water is heated with a coil of resistance $R$ connected to domestic supply. 1.The rise of temperature of water will depend on Supply voltage. 2.Current passing through the coil. 3.Time for which voltage is supplied. Select the correct answer from among the following :
1 1, 2 and 3
2 1 and 2 only
3 1 only
4 2 and 3 only
Explanation:
A Given, $\mathrm{V}=$ supply voltage, $\mathrm{I}=$ current passing though the coil, $t=$ time for which the voltage is supplied Hence, the rise of temperature of water depends directly upon heat supplied and the heat directly depends on supply voltage current and time.
NDA (II) 2019
Current Electricity
152673
Consider the following two circuits [A] 20 bulbs are connected in series to a power supply line. [B] 20 bulbs identical to [A] are connected in a parallel circuit to an identical power supply line. Identify which of the following is not true?
1 If one bulb in [A] blows out, all others will stop glowing
2 Bulbs in $[\mathrm{A}]$ glow brighter, since the current flowing in $[\mathrm{A}]$ is higher
3 If one bulb in [B] blows, other bulbs will still glow
4 Bulbs in [B] have the highest voltage across each bulb
Explanation:
B According to statement B is not true because $\mathrm{R}_{\text {eff }}=20 \mathrm{R}$ (heater assume $\mathrm{R}$ is resistance of one bulb) So, $I=\frac{V}{R_{\text {eff }}}=\frac{V}{20 R}$ which will be minimum
152764
Two identical heaters of $220 \mathrm{~V}, 1000 \mathrm{~W}$ are placed in parallel with each other across $220 \mathrm{~V}$ line, then the combined power is:
1 $1000 \mathrm{~W}$
2 $2000\mathrm{~W}$
3 $500 \mathrm{~W}$
4 $4000 \mathrm{~W}$
Explanation:
B When two identical heater are connected across a given voltage then, Equivalent power $\mathrm{P}=\mathrm{P}_{1}+\mathrm{P}_{2}$ $\mathrm{P}=1000+1000=2000 \mathrm{~W}$
BCECE-2003
Current Electricity
152665
Water is heated with a coil of resistance $R$ connected to domestic supply. 1.The rise of temperature of water will depend on Supply voltage. 2.Current passing through the coil. 3.Time for which voltage is supplied. Select the correct answer from among the following :
1 1, 2 and 3
2 1 and 2 only
3 1 only
4 2 and 3 only
Explanation:
A Given, $\mathrm{V}=$ supply voltage, $\mathrm{I}=$ current passing though the coil, $t=$ time for which the voltage is supplied Hence, the rise of temperature of water depends directly upon heat supplied and the heat directly depends on supply voltage current and time.
NDA (II) 2019
Current Electricity
152673
Consider the following two circuits [A] 20 bulbs are connected in series to a power supply line. [B] 20 bulbs identical to [A] are connected in a parallel circuit to an identical power supply line. Identify which of the following is not true?
1 If one bulb in [A] blows out, all others will stop glowing
2 Bulbs in $[\mathrm{A}]$ glow brighter, since the current flowing in $[\mathrm{A}]$ is higher
3 If one bulb in [B] blows, other bulbs will still glow
4 Bulbs in [B] have the highest voltage across each bulb
Explanation:
B According to statement B is not true because $\mathrm{R}_{\text {eff }}=20 \mathrm{R}$ (heater assume $\mathrm{R}$ is resistance of one bulb) So, $I=\frac{V}{R_{\text {eff }}}=\frac{V}{20 R}$ which will be minimum
152764
Two identical heaters of $220 \mathrm{~V}, 1000 \mathrm{~W}$ are placed in parallel with each other across $220 \mathrm{~V}$ line, then the combined power is:
1 $1000 \mathrm{~W}$
2 $2000\mathrm{~W}$
3 $500 \mathrm{~W}$
4 $4000 \mathrm{~W}$
Explanation:
B When two identical heater are connected across a given voltage then, Equivalent power $\mathrm{P}=\mathrm{P}_{1}+\mathrm{P}_{2}$ $\mathrm{P}=1000+1000=2000 \mathrm{~W}$
BCECE-2003
Current Electricity
152665
Water is heated with a coil of resistance $R$ connected to domestic supply. 1.The rise of temperature of water will depend on Supply voltage. 2.Current passing through the coil. 3.Time for which voltage is supplied. Select the correct answer from among the following :
1 1, 2 and 3
2 1 and 2 only
3 1 only
4 2 and 3 only
Explanation:
A Given, $\mathrm{V}=$ supply voltage, $\mathrm{I}=$ current passing though the coil, $t=$ time for which the voltage is supplied Hence, the rise of temperature of water depends directly upon heat supplied and the heat directly depends on supply voltage current and time.
NDA (II) 2019
Current Electricity
152673
Consider the following two circuits [A] 20 bulbs are connected in series to a power supply line. [B] 20 bulbs identical to [A] are connected in a parallel circuit to an identical power supply line. Identify which of the following is not true?
1 If one bulb in [A] blows out, all others will stop glowing
2 Bulbs in $[\mathrm{A}]$ glow brighter, since the current flowing in $[\mathrm{A}]$ is higher
3 If one bulb in [B] blows, other bulbs will still glow
4 Bulbs in [B] have the highest voltage across each bulb
Explanation:
B According to statement B is not true because $\mathrm{R}_{\text {eff }}=20 \mathrm{R}$ (heater assume $\mathrm{R}$ is resistance of one bulb) So, $I=\frac{V}{R_{\text {eff }}}=\frac{V}{20 R}$ which will be minimum
NEET Test Series from KOTA - 10 Papers In MS WORD
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Current Electricity
152764
Two identical heaters of $220 \mathrm{~V}, 1000 \mathrm{~W}$ are placed in parallel with each other across $220 \mathrm{~V}$ line, then the combined power is:
1 $1000 \mathrm{~W}$
2 $2000\mathrm{~W}$
3 $500 \mathrm{~W}$
4 $4000 \mathrm{~W}$
Explanation:
B When two identical heater are connected across a given voltage then, Equivalent power $\mathrm{P}=\mathrm{P}_{1}+\mathrm{P}_{2}$ $\mathrm{P}=1000+1000=2000 \mathrm{~W}$
BCECE-2003
Current Electricity
152665
Water is heated with a coil of resistance $R$ connected to domestic supply. 1.The rise of temperature of water will depend on Supply voltage. 2.Current passing through the coil. 3.Time for which voltage is supplied. Select the correct answer from among the following :
1 1, 2 and 3
2 1 and 2 only
3 1 only
4 2 and 3 only
Explanation:
A Given, $\mathrm{V}=$ supply voltage, $\mathrm{I}=$ current passing though the coil, $t=$ time for which the voltage is supplied Hence, the rise of temperature of water depends directly upon heat supplied and the heat directly depends on supply voltage current and time.
NDA (II) 2019
Current Electricity
152673
Consider the following two circuits [A] 20 bulbs are connected in series to a power supply line. [B] 20 bulbs identical to [A] are connected in a parallel circuit to an identical power supply line. Identify which of the following is not true?
1 If one bulb in [A] blows out, all others will stop glowing
2 Bulbs in $[\mathrm{A}]$ glow brighter, since the current flowing in $[\mathrm{A}]$ is higher
3 If one bulb in [B] blows, other bulbs will still glow
4 Bulbs in [B] have the highest voltage across each bulb
Explanation:
B According to statement B is not true because $\mathrm{R}_{\text {eff }}=20 \mathrm{R}$ (heater assume $\mathrm{R}$ is resistance of one bulb) So, $I=\frac{V}{R_{\text {eff }}}=\frac{V}{20 R}$ which will be minimum
