04. Cells, Internal Resistance and Cell Combination, Thermocouple
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Current Electricity

152552 If a cell can supply a current $I$ through a resistance $R_{1}$ and a current $I / 2$ across a resistance $R_{2}$ then the internal resistance of the cell is

1 $\mathrm{R}_{1}-2 \mathrm{R}_{2}$
2 $R_{2}-2 R_{1}$
3 $\mathrm{R}_{1}+2 \mathrm{R}_{2}$
4 $R_{2}+R_{1}$
J and K-CET-2016
Current Electricity

152553 Consider the two cells having emf $E_{1}$ and $E_{2}\left(E_{1}\right.$ $>E_{2}$ ) connected as shown in the figure. A potentiometer is used to measure potential difference between $P$ and $Q$, and the balancing length of the potentiometer wire is $0.8 \mathrm{~m}$. Same potentiometer is then used to measure potential difference between $P$ and $R$, and the balancing length is $0.2 \mathrm{~m}$. Then the ratio $E_{1} / E_{2}$ is

1 $\frac{4}{3}$
2 $\frac{5}{4}$
3 $\frac{5}{3}$
4 $\frac{4}{1}$
J and K-CET-2015
Current Electricity

152555 Two identical batteries each of emf $2 \mathrm{~V}$ and internal resistance $1 \Omega$ are available to produce heat in an external resistance by passing a current through it. The maximum power that can be developed across $\mathbf{R}$ using these batteries is

1 $3.2 \mathrm{~W}$
2 $2 \mathrm{~W}$
3 $1.28 \mathrm{~W}$
4 $\frac{8}{9} \mathrm{~W}$
AIPMT-1990
Current Electricity

152556 Two batteries of emf $4 \mathrm{~V}$ and $8 \mathrm{~V}$ with internal resistance $1 \Omega$ and $2 \Omega$ are connected in a circuit with a resistance of $9 \Omega$ as shown in figure. The current and potential difference between the points $P$ and $Q$ are

1 $\frac{1}{3} \mathrm{~A}$ and $3 \mathrm{~V}$
2 $\frac{1}{6} \mathrm{~A}$ and $4 \mathrm{~V}$
3 $\frac{1}{9} \mathrm{~A}$ and $9 \mathrm{~V}$
4 $\frac{1}{12} \mathrm{~A}$ and $12 \mathrm{~V}$
AIPMT-1988
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Current Electricity

152552 If a cell can supply a current $I$ through a resistance $R_{1}$ and a current $I / 2$ across a resistance $R_{2}$ then the internal resistance of the cell is

1 $\mathrm{R}_{1}-2 \mathrm{R}_{2}$
2 $R_{2}-2 R_{1}$
3 $\mathrm{R}_{1}+2 \mathrm{R}_{2}$
4 $R_{2}+R_{1}$
J and K-CET-2016
Current Electricity

152553 Consider the two cells having emf $E_{1}$ and $E_{2}\left(E_{1}\right.$ $>E_{2}$ ) connected as shown in the figure. A potentiometer is used to measure potential difference between $P$ and $Q$, and the balancing length of the potentiometer wire is $0.8 \mathrm{~m}$. Same potentiometer is then used to measure potential difference between $P$ and $R$, and the balancing length is $0.2 \mathrm{~m}$. Then the ratio $E_{1} / E_{2}$ is

1 $\frac{4}{3}$
2 $\frac{5}{4}$
3 $\frac{5}{3}$
4 $\frac{4}{1}$
J and K-CET-2015
Current Electricity

152555 Two identical batteries each of emf $2 \mathrm{~V}$ and internal resistance $1 \Omega$ are available to produce heat in an external resistance by passing a current through it. The maximum power that can be developed across $\mathbf{R}$ using these batteries is

1 $3.2 \mathrm{~W}$
2 $2 \mathrm{~W}$
3 $1.28 \mathrm{~W}$
4 $\frac{8}{9} \mathrm{~W}$
AIPMT-1990
Current Electricity

152556 Two batteries of emf $4 \mathrm{~V}$ and $8 \mathrm{~V}$ with internal resistance $1 \Omega$ and $2 \Omega$ are connected in a circuit with a resistance of $9 \Omega$ as shown in figure. The current and potential difference between the points $P$ and $Q$ are

1 $\frac{1}{3} \mathrm{~A}$ and $3 \mathrm{~V}$
2 $\frac{1}{6} \mathrm{~A}$ and $4 \mathrm{~V}$
3 $\frac{1}{9} \mathrm{~A}$ and $9 \mathrm{~V}$
4 $\frac{1}{12} \mathrm{~A}$ and $12 \mathrm{~V}$
AIPMT-1988
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Current Electricity

152552 If a cell can supply a current $I$ through a resistance $R_{1}$ and a current $I / 2$ across a resistance $R_{2}$ then the internal resistance of the cell is

1 $\mathrm{R}_{1}-2 \mathrm{R}_{2}$
2 $R_{2}-2 R_{1}$
3 $\mathrm{R}_{1}+2 \mathrm{R}_{2}$
4 $R_{2}+R_{1}$
J and K-CET-2016
Current Electricity

152553 Consider the two cells having emf $E_{1}$ and $E_{2}\left(E_{1}\right.$ $>E_{2}$ ) connected as shown in the figure. A potentiometer is used to measure potential difference between $P$ and $Q$, and the balancing length of the potentiometer wire is $0.8 \mathrm{~m}$. Same potentiometer is then used to measure potential difference between $P$ and $R$, and the balancing length is $0.2 \mathrm{~m}$. Then the ratio $E_{1} / E_{2}$ is

1 $\frac{4}{3}$
2 $\frac{5}{4}$
3 $\frac{5}{3}$
4 $\frac{4}{1}$
J and K-CET-2015
Current Electricity

152555 Two identical batteries each of emf $2 \mathrm{~V}$ and internal resistance $1 \Omega$ are available to produce heat in an external resistance by passing a current through it. The maximum power that can be developed across $\mathbf{R}$ using these batteries is

1 $3.2 \mathrm{~W}$
2 $2 \mathrm{~W}$
3 $1.28 \mathrm{~W}$
4 $\frac{8}{9} \mathrm{~W}$
AIPMT-1990
Current Electricity

152556 Two batteries of emf $4 \mathrm{~V}$ and $8 \mathrm{~V}$ with internal resistance $1 \Omega$ and $2 \Omega$ are connected in a circuit with a resistance of $9 \Omega$ as shown in figure. The current and potential difference between the points $P$ and $Q$ are

1 $\frac{1}{3} \mathrm{~A}$ and $3 \mathrm{~V}$
2 $\frac{1}{6} \mathrm{~A}$ and $4 \mathrm{~V}$
3 $\frac{1}{9} \mathrm{~A}$ and $9 \mathrm{~V}$
4 $\frac{1}{12} \mathrm{~A}$ and $12 \mathrm{~V}$
AIPMT-1988
For More Updates join with Us
Current Electricity

152552 If a cell can supply a current $I$ through a resistance $R_{1}$ and a current $I / 2$ across a resistance $R_{2}$ then the internal resistance of the cell is

1 $\mathrm{R}_{1}-2 \mathrm{R}_{2}$
2 $R_{2}-2 R_{1}$
3 $\mathrm{R}_{1}+2 \mathrm{R}_{2}$
4 $R_{2}+R_{1}$
J and K-CET-2016
Current Electricity

152553 Consider the two cells having emf $E_{1}$ and $E_{2}\left(E_{1}\right.$ $>E_{2}$ ) connected as shown in the figure. A potentiometer is used to measure potential difference between $P$ and $Q$, and the balancing length of the potentiometer wire is $0.8 \mathrm{~m}$. Same potentiometer is then used to measure potential difference between $P$ and $R$, and the balancing length is $0.2 \mathrm{~m}$. Then the ratio $E_{1} / E_{2}$ is

1 $\frac{4}{3}$
2 $\frac{5}{4}$
3 $\frac{5}{3}$
4 $\frac{4}{1}$
J and K-CET-2015
Current Electricity

152555 Two identical batteries each of emf $2 \mathrm{~V}$ and internal resistance $1 \Omega$ are available to produce heat in an external resistance by passing a current through it. The maximum power that can be developed across $\mathbf{R}$ using these batteries is

1 $3.2 \mathrm{~W}$
2 $2 \mathrm{~W}$
3 $1.28 \mathrm{~W}$
4 $\frac{8}{9} \mathrm{~W}$
AIPMT-1990
Current Electricity

152556 Two batteries of emf $4 \mathrm{~V}$ and $8 \mathrm{~V}$ with internal resistance $1 \Omega$ and $2 \Omega$ are connected in a circuit with a resistance of $9 \Omega$ as shown in figure. The current and potential difference between the points $P$ and $Q$ are

1 $\frac{1}{3} \mathrm{~A}$ and $3 \mathrm{~V}$
2 $\frac{1}{6} \mathrm{~A}$ and $4 \mathrm{~V}$
3 $\frac{1}{9} \mathrm{~A}$ and $9 \mathrm{~V}$
4 $\frac{1}{12} \mathrm{~A}$ and $12 \mathrm{~V}$
AIPMT-1988
NEET DIGITAL LIBRARY